Syllabus Edition

First teaching 2023

First exams 2025

|

Space-Time Interval (HL) (HL IB Physics)

Revision Note

Ashika

Author

Ashika

Last updated

Space-Time Interval

  • Einstein discovered that time and distance changes when moving from one inertial reference frame to another when travelling at speeds close to the speed of light
    • In other words, these reference frames are not absolute
  • However, some quantities are the same in all inertial frames. These are called invariant
  • These are:
    • Proper time, t0
    • Proper length, L0
    • Space-time interval, Δs
  • These are a product of Einstein's second postulate
  • In Galilean relativity:
    • Space and time are the same in all reference frames, i.e. straight capital delta t space equals space straight capital delta t apostrophe and straight capital delta x space equals space straight capital delta x apostrophe
  • In special relativity:
    • These are replaced with a space-time interval, as space and time are connected together as 4 coordinates (x, y, z, t) for an event
    • Motion can be represented as spanning both space and time using this coordinate system
  • The diagram below shows a person moving in both space x and z and in time t
    • They can also move in the y direction, but 4 dimensions are not possible to draw accurately here (in 3-dimensional space)

1-5-10-space-time-intervalMotion in space-time. The length of the arrow for the space-time interval is the same for all inertial reference frames

  • An interval in space-time is an invariant quantity in all inertial reference frames and is defined as:

open parentheses straight capital delta s close parentheses squared space equals space open parentheses c straight capital delta t close parentheses squared space minus space open parentheses straight capital delta x close parentheses squared

  • Where:
    • straight capital delta t = time interval / separation (s)
    • c = the speed of light
    • straight capital delta x = spacial separation (m)
    • straight capital delta s = space-time interval (m)
  • This means that in two inertial reference frames, although straight capital delta t and straight capital delta x will be different in both frames, straight capital delta s will be the same
  • These will be used in space-time diagrams

Worked example

An inertial reference frame S' moves relative to S with a speed close to the speed of light. When clocks in both frames show zero the origins of the two frames coincide.

An event P has coordinates x  =  2  m and ct  =  0 in frame S, and x = 2.3 m in frame S'. Show that the time coordinate of event P in frame S' is –1.1 m.

Answer:

Step 1: List the known quantities:

  • Spacial separation in frame S, increment x = 2 m
  • Time separation in frame S, c increment t = 0
  • Spacial separation in frame S', increment x apostrophe = 2.3 m

Step 2: Calculate the space-time interval in frame S

open parentheses straight capital delta s close parentheses squared space equals space open parentheses c straight capital delta t close parentheses squared space minus space open parentheses straight capital delta x close parentheses squared

open parentheses increment s close parentheses squared space equals space open parentheses 0 close parentheses space minus space open parentheses 2 close parentheses squared space equals space minus 4

Step 3: Substitute values into the space-time interval for S'

  • increment s is the same (invariant) in both reference frames

open parentheses increment s close parentheses squared space equals space open parentheses c increment t apostrophe close parentheses squared space minus space open parentheses increment x apostrophe close parentheses squared

open parentheses c increment t apostrophe close parentheses squared space equals space open parentheses increment s close parentheses to the power of 2 space end exponent space plus space open parentheses increment x apostrophe close parentheses squared

open parentheses c increment t apostrophe close parentheses squared space equals space minus 4 space plus space open parentheses 2.3 close parentheses squared space equals space 1.29

c increment t apostrophe space equals space square root of 1.29 end root space equals space plus-or-minus 1.14

Examiner Tip

The units still work out on both sides of the equation. Remember, c straight capital delta t is a speed × time which is a distance in metres, so is straight capital delta x so straight capital delta s is in metres.

Whether ct' in the worked example is + or – will come in later with space-time diagrams.

Proper Time & Length

  • In special relativity, we have found that distances and times are relative
  • This means the length of an object and the time interval of an event changes when observed in frames that are moving relative to that object
    • More on this is explored in length contraction and time dilation
  • We need to define the difference mathematically between the time and lengths measured between each frame, to know which one is being referred to

What is Proper Time and Proper Length?

  • Proper time interval, Δt0 is defined as:

The time interval between two events measured from within the reference frame in which the two events occur at the same place

  • Proper length, L0 is defined as:

The length measured in a reference frame where the object is at rest (relative to the observer)

  • These can be measured either in the moving frame S' or a rest frame S
    • This depends on the reference frame you are calculating the length and time from
  • For example, if a person in moving frame S' (e.g. on a train) measures the length of a book, they are at rest relative to the book
    • They measure the distance between points x2' and x1'
    • This is the proper length, L0 although they are technically moving (but they don't know this - otherwise it would go against Einstein's first postulate)
  • However, for an observer in frame S, at rest (e.g. on a platform
    • They will measure the distance between points x2 and x1
    • This a shortened length, L

1-5-6-proper-length-1-ib-2025-physics

The observer in S' is measuring the proper length, because they are at rest relative to the object

  • For example, if a person in the stationary frame S (e.g. on the platform) measures the length of a book, they are now at rest relative to the book
    • They measure the distance between points x2 and x1
    • This is the proper length, L0 
  • However, an observer in frame S', which is moving (e.g. on a train) sees themselves at rest but instead sees frame S as moving (remember, motion is relative)
    • They will measure the distance between points x2' and x1'
    • This a shortened length, L


1-5-6-proper-length-2-ib-2025-physics

The observer in S is measuring the proper length because they are at rest relative to the object

  • The same rules apply for the proper time, t0, except that the time measured from a frame moving relative to an event will be measured longer

Examiner Tip

Do not misinterpret this as the time or length measured in the stationary reference frame! This is not the case. It could be the time and length measured in the moving frame too, because it is a length and time measured by an observer at rest relative to the object

Again, this only works for objects moving close to the speed of light. You will never encounter this in everyday life!

You've read 0 of your 5 free revision notes this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.