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Space-Time Diagrams (HL) (HL IB Physics)

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Ashika

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Ashika

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Space-Time Diagrams

  • Spacetime (or Minkowski) diagrams represent an object's motion in spacetime
  • They help to visualise
    • Time dilation
    • Length contraction
    • Simultaneity
  • Since 4D (x, y, z, t) diagrams cannot be drawn on a 2D page, we collapse 3D space (x, y, z) into 1 spacial dimension and keep time as its own dimension
  • This gives a spacetime diagram
    • Lines drawn on a spacetime diagram are called world lines
  • Instead of the usual distance-time graphs, we plot
    • The horiztonal axis as x
    • The vertical axis as ct

1-5-10-spacetime-basics

Objects moving slower are represented by a steeper gradient on a spacetime gradient

  • Note that both axes have dimensions of length
    • This makes it easy to compare values on one axis and another
  • This means the worldlines have a gradient of
    • fraction numerator c increment t over denominator increment x end fraction space equals fraction numerator space c over denominator v end fraction where the velocity is v space equals space fraction numerator increment x space over denominator increment t end fraction
  • This means:
    • The steeper the gradient, the slower the object is moving
    • The shallower the gradient, the faster the object is moving
  • ct was first seen when the spacetime interval was introduced, and c is chosen deliberately so our diagram is oriented around the speed of light
    • ct is a sort of 'distance in time'

Worldline at Rest

1-5-10-space-time-at-rest-ib-2025-physics

A worldline for an object at rest

  • P is an object at rest
    • It has an infinite slope meaning v = 0
  • It is only moving in time, not in space

Worldline at Constant Velocity

1-5-10-space-time-at-constant-velocity-ib-2025-physics

A worldline at constant velocity has to have a gradient steeper than 1

  • Q is an object at constant velocity
  • The object moves some distance over some time
  • For an object moving at the speed of light, c (e.g. a massless photon), its worldline has a gradient of c over v space equals c over c space equals1 (a 45o angle)
  • Since nothing can travel faster than the speed of light (i.e. v cannot be greater than c), then objects can only have a gradient greater than 1
    • Therefore, a gradient of 1 is the lowest possible gradient
  • Q's motion does not need to start at the origin. As long as it has a gradient of less than 1, it can start anywhere on the x-axis

Worldline accelerating

1-5-10-space-time-accelerating

All points on a worldline representing an object accelerating must have a gradient steeper than 1

  • R is an object with a varying velocity that represents possible motion
    • It has a small gradient (larger velocity), which increases (decreasing velocity)
    • Its gradient never gets less than 1
  • S is an object with a varying velocity that represents impossible motion
    • At one point, it has a gradient of less than 1 implying a velocity greater than c
    • Even though it does not physically cross the v = c gradient line, it is still not possible because a portion of the line has a gradient of less than one

Multiple Reference Frames

  • Every point on a spacetime diagram represents an event, for example, an object moving
  • More than one inertial reference frame can be represented on a spacetime diagram
    • ct and x represent the co-ordinate axes for an observer in frame S
    • ct' and x' represent the co-ordinate axes for an observer in frame S' (moving at speed v with respect to frame S)
  • Therefore, we can combine two separate spacetime diagrams for different inertial reference frames moving at constant speed relative to each other
    • The axes for the ct' and x' are at an angle
  • The worldline T shows the equivalent worldline of P, but now in the S' reference frame
    • This represents an object at rest in its own co-ordinate system

1-5-10-moving-reference-frame

Worldline of a particle at rest in the reference frame S'

  • The axes are tilted because the ct' reference frame is travelling at speed v relative to the ct reference frame
    • The x' axis must also be tilted in order for the speed of light (the dashed line in the middle) to be the same in both reference frames
  • The scales on the time axes ct and ct′ and on the space axes x and x′ of two inertial reference frames moving relative to one another are not the same and are defined by lines of constant spacetime interval
  • If an event occurs (such as a flash of light), both reference frames will measure a different time and different position with respect to each other
    • This can be seen on a spacetime diagram

1-5-10-moving-reference-frame-event

An event is shown in reference frames S and S' with differing values of distance and time

  • The event in the S reference frame occurs at (X, cT)
  • The event in the S' reference frame occurs at (X', cT')
  • The co-ordinates in the S' reference frame are determined by lines 1 and 2
    • Line 1 is a line parallel to the x' axis
    • Line 2 is a line parallel to the ct' axis
  • The clocks in both frames show zero at the origins where two frames collide i.e. both observers start their clocks at the same time to measure any time intervals

Simultaneity

  • We can now see that simultaneous events in one frame are not simultaneous in another moving inertial reference frame
  • Let's go back to Observers A and B in Simultaneity in Special Relativity
    • We can see that Observer B sees the light reach points X and Y at the same time, whilst Observer A (in the ct'–x' co-ordinate system) sees the light from the lamp reach point X before point Y on a spacetime diagram

1-5-10-simultaneity-space-time-diagrams

Simultaneity is not possible for two reference frames moving relative to each other

Time Dilation

  • Consider two flashes of light at x = 0 in the S reference frame that occur one after another
  • When these flashes are observed in the S' frame, we can see the time between the flashes is longer
    • The time between them has increased (dilated)

1-5-10-time-dilation-space-time-diagrams

Spacetime diagrams representing time dilation

  • Another difference is that in the S' reference frame, the first flash now occurs on the -axis
    • This just means it takes place to the left of the observer

Length Contraction

  • Consider a rod measured in the S reference frame where the rod moving relative to S
  • The rod has the same speed as it does in the S' reference frame (which is also moving relative to S)

1-5-10-length-contraction-space-time-diagrams-ib-2025-physics

Spacetime diagrams representing length contraction

  • The length of the rod is measured by measuring each side at the same time
    • The observer in frame S will measure a length L
  • When the observer in frame S' measures the rod, they see the rod as stationary (as it is moving at the same speed as the observer)
    • The observer in frame S will measure a length L'
  • L is shorter than L', which means that the length has been shortened (contracted) when measured by Observer S, who is moving relative to the rod
    • Although it is the rod that is moving, remember, it is at rest in its own reference frame and Observer S is moving relative to it
  • This occurs from the fact that measurements that are simultaneous in one reference frame are not simultaneous in another

Worked example

The spacetime diagram shows the axes of an inertial reference frame S and the axes of a second inertial reference frame S′ that moves relative to S with speed 0.6432c. When clocks in both frames show zero the origins of the two frames coincide.

1-5-10-spacetime-we

Event E has co-ordinates x  =  1.5  m and ct  =  0 in frame S. 

(a)
Label, on the diagram,

(i) the space co-ordinate of event E in the S′ frame. Label this event with the letter Q.

(ii) the event that has co-ordinates x′  =  1.5  m and ct′  =  0. Label this event with the letter R.

(b)
A rod at rest in frame S has a proper length of 1.5  m. At t  =  0, the left-hand end of the rod is at x  =  0 and the right-hand end is at x  =  1.5  m.
 
Using the spacetime diagram, outline without calculation, why observers in frame S′ measure the length of the rod to be less than 1.5  m. 
 

Answer:

(a)

(i) Draw a line parallel to the ct' axis

1-5-10-spacetime-ms-1-ib-2025-physics

(ii) 

Step 1: List the known quantities

  • Speed of the spacecraft, v = 0.6432c
  • Position of event in frame S, x = 1.5 m

Step 1: Calculate the x' co-ordinate of point Q

  • To convert between a position (or time) from one co-ordinate system and another, we can use Lorentz transformations

x apostrophe space equals space gamma open parentheses x space minus space v t close parentheses

x apostrophe space equals space fraction numerator 1 over denominator square root of 1 space minus fraction numerator space open parentheses 0.6432 c close parentheses squared over denominator c squared end fraction end root end fraction open parentheses 1.5 space minus space 0 close parentheses space equals space 1.959 space equals space 2.0 space straight m

  • Since there are no other objects involved, speed v = 0

Step 2: Label this point on the axes as R

  • The co-ordinates are x′  =  1.5  m and ct′  =  0
  • Point R (at 1.5 m) is roughly 2 over 3 of the distance of Q (at 2.0 m)

1-5-10-spacetime-ms-2-ib-2025-physics

(b) 

Step 1:  Outline why observers in frame S′ measure the length of the rod to be less than 1.5  m

  • The ends of the rod must be recorded at the same time in frame S'
  • This is shown on the spacetime diagram:

1-5-10-spacetime-ms-3

  • The right-hand side of the rod intersects the x' axis at a co-ordinate that is less than 1.5 m

1-5-10-spacetime-ms-4-ib-2025-physics

Examiner Tip

This all might sound counter-intuitive because we're used to thinking of position versus time with distance-time graphs, rather than time versus position. Remember, now the gradient is fraction numerator 1 over denominator v e l o c i t y end fraction instead of equating to the velocity.

The important thing about worldlines is not their value but their gradient. Where they start doesn't matter, whether at the origin or along the x axis, their gradients cannot be less than 1.

Make sure you never write c', as there is no such thing. c is the same in all reference frames.

Notice that reading from the ct' and x' co-ordinate axis is actually no different reading from ct and x, it's just that they're slanted so it looks a bit different, but the principles are still the same.

Exam questions will generally have the units of ct and x in light years (ly), so make sure you're comfortable with this definition.

Velocity on a Space-Time Diagram

  • The worldline for a moving particle on a spacetime diagram using the x-ct axis is a diagonal line

1-5-11-spacetime-velocity

  • The velocity of the particle can be calculated by the angle of the moving particle's worldline with the ct axis
  • When we are using the x-ct axis, we can see that:

tan theta space equals fraction numerator space o p p o s i t e over denominator a d j a c e n t end fraction space equals space fraction numerator increment x over denominator c increment t end fraction

  • From mechanics, we know that velocity is the rate of change of displacement:

fraction numerator increment x over denominator increment t end fraction space equals space v

  • Therefore:

tan theta space equals v over c

  • Where:
    • θ = angle between the world line and the ct axis (°)
    • v = velocity of the object (m s–1)
    • c = speed of light

Worked example

A spaceship travels away from Earth in the direction of a nearby planet. A spacetime diagram for the Earth's reference frame shows the worldline of the spaceship. Assume the clock on the Earth, the clock on the planet, and the clock on the spaceship were all synchronized when ct = 0.

1-5-11-spacetime-velocity-we-ib-2025-physics

Show, using the spacetime diagram, that the speed of the spaceship relative to the Earth is 0.80c.

Answer:

Method 1: Using the gradient

Step 1: Choose a co-ordinate pair

  • Choose any corresponding value of ct and e.g. ct = 10, x = 8

1-5-11-spacetime-velocity-ms-1-ib-2025-physics

Step 2: Calculate the gradient

  • The gradient of a spacetime graph is c over v

g r a d i e n t space equals fraction numerator space c over denominator v end fraction space equals fraction numerator space 10 over denominator 8 end fraction

Step 3: Calculate the velocity, v

v space equals 8 over 10 c space equals space 0.8 space c

Method 2: Measure the angle

Step 1: Measure angle θ using a protractor

1-5-11-spacetime-velocity-ms-2

  • θ = 39°

Step 2: Substitute into the velocity equation

tan theta space equals space tan open parentheses 39 close parentheses space equals 0.8 space equals space v over c

v space equals space 0.8 space c

Examiner Tip

Any discussion of world lines of moving particles will only be limited to constant velocity in your exam. 

Make sure you have your protractor with you in your exam. An exam question could ask you to measure the angle θ yourself from the diagram on your exam paper.

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.