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First exams 2025

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Millikan's Oil Drop Experiment (HL IB Physics)

Revision Note

Ann H

Author

Ann H

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Millikan's Oil Drop Experiment

  • This experiment was conducted by Millikan and Fletcher in 1909
  • It determined the value of the fundamental elementary charge

Method for Millikan's Oil Drop Experiment

  • A fine mist of oil drops is sprayed into a chamber 
    • Oil is used instead of water because it does not evaporate quickly
    • This means the mass of the drops will remain constant
  • As the drops pass out of the spray nozzle they are charged by friction (alternatively, they can also be ionised by X-rays)
    • Some drops lose electrons and become positively charged
    • Some drops gain electrons and become negatively charged
  • The drops pass into a region between two metal plates and are viewed using a microscope

Equipment Set Up for Millikan's Oil Drop Experiment

4-2-milikans-oil-drop-experiment

In Millikan's Oil Drop Experiment oil is sprayed into a chamber before passing between metal plates where the electric and gravitational forces are compared

Electric vs Gravitational Force

No Electric Field

  • The oil drops fall under gravity between the metal plates
  • They reach a terminal velocity when the air resistance and gravitational force acting on the drop are equal

With Electric Field

  • A potential difference is applied between the metal plates which creates an electric field
  • The charged oil drops begin to rise when the electric field is strong enough
  • This means the upward electrical force is greater than the gravitational force
  • The equation for electric force is: 

F space equals space E q

  • Where:
    • E = electric field strength (N C-1)
    • F = electrostatic force on the charge (N)
    • q = charge (C)
  • The distance the drops rise depends upon their mass
  • With the correct potential difference applied, the electric and gravitational forces can become equal and opposite
  • The equation for gravitational force, which comes from Newton's second law, is:

W space equals space m g

  • Where:
    • W = weight of drop (N)
    • m = mass of drop (kg)
    • g = gravitational field strength (N kg−1)
  • By equating the electric and gravitational forces of the drops, the value of fundamental charge was determined to be 1.60 × 10−19 C
  • The magnitude of the charge on any object is found to be a multiple of 1.60 × 10−19
  • Therefore, Millikan's experiment provides evidence for the quantisation of charge

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Ann H

Author: Ann H

Expertise: Physics

Ann obtained her Maths and Physics degree from the University of Bath before completing her PGCE in Science and Maths teaching. She spent ten years teaching Maths and Physics to wonderful students from all around the world whilst living in China, Ethiopia and Nepal. Now based in beautiful Devon she is thrilled to be creating awesome Physics resources to make Physics more accessible and understandable for all students no matter their schooling or background.