Advanced Differentiation (DP IB Maths: AA HL)

Exam Questions

5 hours28 questions
1
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4 marks

Letspace f left parenthesis x right parenthesis equals 3 x squared.

By differentiating from first principles, show thatspace f to the power of apostrophe left parenthesis x right parenthesis equals 6 x.

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2a
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1 mark

Letspace f left parenthesis x right parenthesis equals sin space x.

Solve the equationspace f apostrophe left parenthesis x right parenthesis equals f apostrophe apostrophe apostrophe left parenthesis x right parenthesis in the interval  0 less or equal than x less or equal than 2 pi.

2b
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2 marks

Show thatspace f to the power of open parentheses 4 close parentheses end exponent open parentheses x close parentheses equals f open parentheses x close parentheses.

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3a
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2 marks

Find the derivative of each of the following functions: 

space f open parentheses x close parentheses equals cot space open parentheses x plus pi over 3 close parentheses

3b
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2 marks

g open parentheses x close parentheses equals 5 to the power of x minus 3 log subscript 3 space x

3c
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3 marks

h open parentheses x close parentheses equals arcsin space 4 x

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4a
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4 marks

For the curve defined by y equals tan space 3 x, show that

fraction numerator straight d squared y over denominator straight d x squared end fraction equals 18 open parentheses tan space 3 x plus tan cubed space 3 x close parentheses

4b
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2 marks

For the curve defined by y equals arctan space x, show that 

y to the power of apostrophe apostrophe end exponent equals negative fraction numerator 2 x over denominator x to the power of 4 plus 2 x squared plus 1 end fraction

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5a
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6 marks

Consider the functionspace f defined byspace f left parenthesis x right parenthesis equals 2 x plus cot space x0 less than x less than pi.

The following diagram shows the graph of the curve y equals f left parenthesis x right parenthesis:

q5a_5-8_medium_ib-aa-hl-maths 

The points marked straight A and straight B are the turning points of the graph.

(i)
Findspace f to the power of apostrophe left parenthesis x right parenthesis.

(ii)
Hence find the coordinates of points straight A and straight B.
5b
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4 marks

Find the equation of the normal to the graph at the point where the x-coordinate is equal to pi over 2.

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6a
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2 marks

For each of the following, find fraction numerator straight d y over denominator straight d x end fraction by differentiating implicitly with respect to x

x squared plus y squared equals 16

6b
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2 marks

4 x squared minus 3 x equals y squared plus 2 y

6c
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3 marks

  fraction numerator open parentheses x plus y close parentheses squared over denominator 3 x end fraction equals 1

6d
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4 marks

square root of x squared plus y cubed end root equals 4

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7a
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2 marks

A curve is described by the equation

2 over x minus 1 over y equals 1

Use implicit differentiation with respect to x to show that 

fraction numerator straight d y over denominator straight d x end fraction equals fraction numerator 2 y squared over denominator x squared end fraction 

7b
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4 marks

Use your result from part (a) to find the equation of the

(i)
tangent

(ii)
normal

to the curve at the point left parenthesis 1 comma space 1 right parenthesis.

7c
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5 marks
(i)
Rearrange the equation of the curve into the form y equals f left parenthesis x right parenthesis.

(ii)
Hence find an expression for fraction numerator straight d y over denominator straight d x end fraction entirely in terms of x
7d
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2 marks

Verify that your answer to part (c)(ii) and the result from part (b)(i) both give the same value for the gradient of the tangent to the curve at the point left parenthesis 1 comma space 1 right parenthesis.

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8a
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2 marks

An international mission has landed a rover on the planet Mars. After landing, the rover deploys a small drone on the surface of the planet, then rolls away to a distance of 6 metres in order to observe the drone as it lifts off into the air. Once the rover has finished moving away, the drone ascends vertically into the air at a constant speed of 2 metres per second.

Let D be the distance, in metres, between the rover and the drone at time t seconds. 

Let h be the height, in metres, of the drone above the ground at time t seconds. The entire area where the rover and drone are situated may be assumed to be perfectly horizontal.

Show that 

D equals square root of h squared plus 36 end root

8b
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5 marks
(i)
Explain why fraction numerator straight d h over denominator straight d t end fraction= 2

(ii)
Hence use implicit differentiation to show that
fraction numerator straight d D over denominator straight d t end fraction equals fraction numerator 2 h over denominator square root of h squared plus 36 end root end fraction
8c
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4 marks

Find

(i)
the rate at which the distance between the rover and the drone is increasing at the moment when the drone is 8 metres above the ground.

(ii)
the height of the drone above the ground at the moment when the distance between the rover and the drone is increasing at a rate of  1 blank ms to the power of negative 1 end exponent.

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9a
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3 marks

In the diagram below, is the outline of a type of informational signboard that a county council plans to use in one of its parks. The shape is formed by a rectangle CDEG, to one side of which an equilateral triangle EFG has been appended.

q9a_5-8_medium_ib-aa-hl-maths 

The signboards will be produced in various different sizes.  However because of the cost of the edging that must go around the perimeter of the signboards, the council is eager to design the signboards so that the area of a signboard is the maximum possible for a given perimeter.

Let vertical line CD vertical line equals x space cm and let vertical line DE vertical line equals y space cm.

(i)
Write down an expression in terms of x and y for the perimeter of the signboard, straight P.

(ii)
Hence use implicit differentiation to find fraction numerator straight d P over denominator straight d x end fraction
9b
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3 marks

Explain why, for a given perimeter, it must be true that   fraction numerator straight d P over denominator straight d x end fraction equals 0, and use this fact to show that   fraction numerator straight d y over denominator straight d x end fraction equals negative 3 over 2.

9c
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4 marks

Show that the area A, of the signboard is given by  begin mathsize 16px style A equals x y plus fraction numerator square root of 3 over denominator 4 end fraction x squared end style.

9d
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5 marks

Hence use implicit differentiation to find the ratio of y to x that gives the maximum area.

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1
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4 marks

Let f open parentheses x close parentheses equals 2 x cubed.

By differentiating from first principles, show that f apostrophe open parentheses x close parentheses equals 6 x squared.

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2a
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4 marks

Let f open parentheses x close parentheses equals cos square root of 2 x.

Find the positive solution to the equation f apostrophe open parentheses x close parentheses equals f apostrophe apostrophe apostrophe open parentheses x close parentheses minus fraction numerator 3 square root of 2 over denominator 2 end fraction   that is closest to zero.

2b
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3 marks
(i)
Show that f to the power of open parentheses 4 close parentheses end exponent open parentheses x close parentheses equals k f open parentheses x close parentheses,  where k is a constant to be determined.

(ii)
Write down the value of f to the power of open parentheses 10 close parentheses end exponent open parentheses 0 close parentheses.

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3a
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3 marks

Given that f open parentheses x close parentheses equals arctan open parentheses 1 over x close parentheses comma  find f apostrophe open parentheses x close parentheses.

3b
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4 marks

For the function g defined by gopen parentheses x close parentheses equals 4 to the power of negative x end exponent plus 2 log subscript 4 x,  show that

 g apostropheopen parentheses x close parentheses equals fraction numerator 1 over denominator open parentheses ln space 2 close parentheses x end fraction minus open parentheses ln space 2 close parentheses 2 to the power of negative 2 x plus 1 end exponent

3c
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3 marks

Find the derivative of the function h open parentheses x close parentheses equals cosec open parentheses 3 x squared close parentheses.

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4a
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6 marks

For the curve defined by y equals cot space x squared,  show that

fraction numerator straight d squared y over denominator straight d x squared end fraction equals 8 x squared open parentheses y cubed plus y close parentheses minus 2 y squared minus 2

4b
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4 marks

For the curve defined by y equals arcsin space x,  show that

y double apostrophe equals fraction numerator x over denominator open parentheses 1 minus x squared close parentheses square root of 1 minus x squared end root end fraction

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5a
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6 marks

Consider the function f defined by f open parentheses x close parentheses equals tan open parentheses straight pi over 2 minus x close parentheses plus 4 over 3 x comma space 0 less than x less than straight pi

The following diagram shows the graph of the curve y equals f open parentheses x close parentheses colon

 q5_ib-aa-hl_advanced-differentiation_hard_diagram

The points marked A and B are the turning points of the graph. 

Find the coordinates of points A and B.

5b
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4 marks

Find the equation of the normal to the graph at the point where the x-coordinate is equal to straight pi over 4.

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6a
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2 marks

For each of the following, find fraction numerator d y over denominator d x end fraction by differentiating implicitly with respect to x.

x squared over 16 plus y squared over 25 equals 1

6b
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2 marks

e to the power of x squared end exponent plus x equals y cubed minus y

6c
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3 marks

open parentheses x minus y close parentheses to the power of 7 over x squared equals 1

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7a
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4 marks

Consider the curve defined by the equation

fraction numerator 1 over denominator cube root of x cubed minus y cubed end root end fraction equals fraction numerator 2 straight pi over denominator 3 end fraction 

Use implicit differentiation to find fraction numerator d x over denominator d y end fraction in terms of x and y.

7b
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7 marks

By first rewriting the equation of the curve in the form y equals f open parentheses x close parentheses:

(i)
Determine the coordinates of the point on the curve where  fraction numerator d y over denominator d x end fraction equals 0.

(ii)
Explain why f open parentheses x close parentheses is an increasing function on all intervals open square brackets a comma b close square brackets for which the interval right square bracket a comma b left square bracket does not include the x-coordinate of the point identified in part (b)(i).

(iii)
Describe the asymptotic behaviour of the curve as x rightwards arrow plus-or-minus infinity .

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8a
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2 marks

After setting up a firework rocket on a stretch of level ground, the firework engineer lights the fuse and steps back to a safe distance of 10 metres from the rocket.  The rocket then begins to ascend vertically into the air at a constant velocity of 64 metres per second. 

Let D be the distance, in metres, between the rocket and the point on the ground where the engineer is standing at time t seconds after the rocket takes off.  Let h be the height, in metres, of the rocket above the ground at time t seconds.

Write an expression for D in terms of h only.

8b
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5 marks

Use implicit differentiation to show that

 fraction numerator d D over denominator d t end fraction equals fraction numerator 64 h over denominator square root of h squared plus 100 end root end fraction

8c
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4 marks

Find

(i)
the rate at which the distance between the rocket and the point where the engineer is standing is increasing 1.56 seconds after the rocket takes off.

(ii)
the height of the rocket above the ground at the moment when the distance between the rocket and the point where the engineer is standing is increasing at a rate of 10 space ms to the power of negative 1 end exponent .
8d
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4 marks
(i)
Describe the mathematical behaviour of  fraction numerator d D over denominator d t end fraction as h becomes large and interpret this in the context of the question.

(ii)
Comment on the validity of the model for large values of h.

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9a
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7 marks

Quadrilateral CDEF represents a corral for unicorns.  There are fences along the four sides of the corral, as well as a straight fence across the middle connecting points straight D space and space straight F.  Because of the way unicorns are trained, it is essential that triangles CDF and DEF be identical isosceles triangles, with CD equals CF equals DE equals EF.  The length of side DF, however, can vary.

q9_ib-aa-hl_advanced-differentiation_hard_diagram

Gonzolph is a unicorn trainer who is concerned about the high cost of unicorn fencing.  He would therefore like the total length of fencing, P, used in his corral to be the minimum possible for a given area, A, to be enclosed. 

Let  DF equals 2 x space straight m and let  CD equals straight y space straight m.

By first finding the derivative fraction numerator d A over denominator d x end fraction in terms of xand y, show that for a given area the equation fraction numerator d y over denominator d x end fraction equals fraction numerator 2 x squared minus y squared over denominator x y end fraction must be satisfied.

9b
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6 marks

By considering the derivative fraction numerator d P over denominator d x end fraction, show that when the length of fencing required to enclose a given area is the minimum possible then x equals open parentheses fraction numerator square root of 33 minus 1 over denominator 8 end fraction close parentheses y.

9c
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3 marks

Hence find the size of angle straight F straight C with hat on top straight D in a corral that minimises the amount of fencing required to enclose a given area.

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1
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5 marks

Let  f open parentheses x close parentheses equals open parentheses a x plus b close parentheses squared, where a comma b element of straight real numbers are constants with a not equal to 0

By differentiating from first principles, show that f apostrophe open parentheses x close parentheses equals 2 a open parentheses a x plus b close parentheses.

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2a
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6 marks

Consider the function f defined by

f open parentheses x close parentheses equals straight e to the power of negative 1 half x end exponent sin open parentheses fraction numerator square root of 3 over denominator 2 end fraction x close parentheses 

By first calculating f apostrophe open parentheses x close parentheses  and f double apostrophe open parentheses x close parentheses,  show that f apostrophe apostrophe apostrophe open parentheses x close parentheses equals f open parentheses x close parentheses.

2b
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2 marks

Write down the value of f to the power of open parentheses 29 close parentheses end exponent open parentheses 0 close parentheses.

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3a
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4 marks

Find the derivative of the function  f open parentheses x close parentheses equals tan open parentheses ln space x close parentheses plus arctan open parentheses straight e to the power of x close parentheses.

3b
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4 marks

Given that g open parentheses x close parentheses equals 27 to the power of x plus 1 end exponent plus begin inline style 1 third end style log subscript 3 x to the power of 6,  find g apostrophe open parentheses x close parentheses.  Simplify your answer as far as possible.

3c
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5 marks

Let h be the function defined by h open parentheses x close parentheses equals arcsin open parentheses cos space x close parentheses. Show that

h apostrophe open parentheses x close parentheses equals open curly brackets table row cell space space space space space space space space space space space space space space space 1 comma end cell cell open parentheses 2 k minus 1 close parentheses straight pi less than x less than 2 k straight pi end cell row cell space space space space space space space space space space space minus 1 comma end cell cell 2 k straight pi less than x less than open parentheses 2 straight k plus 1 close parentheses straight pi end cell row cell undefined comma space space space space space space space space space end cell cell x equals k straight pi end cell end table close 

where k element of straight integer numbers.

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4
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7 marks

Use differentiation to show that y equals 1 plus tan space x cubed is a solution to the equation

fraction numerator straight d squared y over denominator straight d x squared end fraction equals 18 x to the power of 4 open parentheses y cubed minus 3 y squared plus 4 y minus 2 close parentheses plus 6 x open parentheses y squared minus 2 y plus 2 close parentheses

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5a
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5 marks

Consider the curve defined by y equals arccos open parentheses ln space x close parentheses ,  for values of x satisfying 1 over straight e less or equal than x less or equal than straight e.

Show that

y to the power of n equals fraction numerator 1 over denominator x squared square root of 1 minus ln squared space x end root end fraction open parentheses fraction numerator 1 minus ln space x minus ln squared space x over denominator 1 minus ln squared x end fraction close parentheses
5b
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7 marks

Given that the curve has exactly one point of inflection, show that that point of inflection occurs when x equals e to the power of 1 over ϕ end exponent,  where ϕ equals fraction numerator 1 plus square root of 5 over denominator 2 end fraction is the so-called ‘golden ratio’.

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6
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11 marks

Consider the function f defined by f open parentheses x close parentheses equals 8 x squared plus cot space 2 x comma space 0 less than x less than straight pi over 2

The following diagram shows the graph of the curve y equals f open parentheses x close parentheses:

q6_ib-aa-hl_advance-differentiation_very-hard_diagram

The point marked A is the inflection point of the graph. 

Determine the exact coordinates of the point where the normal to the graph at point A  intersects the y-axis.

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7a
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3 marks

For each of the following, find fraction numerator d y over denominator d x end fraction by differentiating implicitly with respect to x.

fraction numerator x squared over denominator 3 square root of y end fraction plus fraction numerator y squared over denominator 4 square root of x end fraction equals 1

7b
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3 marks

sin open parentheses x y close parentheses equals open parentheses x minus 2 y close parentheses to the power of 5

7c
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3 marks

square root of e to the power of negative 2 x end exponent minus 2 e to the power of negative x minus y end exponent plus e to the power of negative 2 y end exponent end root equals straight pi

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8a
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5 marks

A curve is described by the equation

 fraction numerator x minus 2 y over denominator open parentheses x y close parentheses squared end fraction equals k 

where k element of straight real numbers is a constant.

Use implicit differentiation to show that

fraction numerator d y over denominator d x end fraction equals fraction numerator x y minus 4 y squared over denominator 2 x y minus 2 x squared end fraction
8b
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2 marks

For a particular value of k, the curve goes through the pointopen parentheses negative 1 comma negative 1 close parentheses

Find the value of k.

8c
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4 marks

Find the equation of the

(i)
tangent
(ii)
normal

to the curve at the point open parentheses 2 comma negative 1 close parentheses.

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9a
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6 marks

Two observers, Pamela and Quinlan, are standing at points P and Q respectively watching a hot air balloon take off.  The balloon takes off from point O, which is in between points P and Q and is such that points P, O and Q all lie on a straight horizontal line.

Let  be the distance OP, and let D subscript pbe the distance between point P and the balloon at any time t.  Similarly let q be the distance OQ, and let D subscript q be the distance between point Q and the balloon at any time t.  Let h be the height of the balloon above the ground at any time t.  The balloon ascends vertically upwards, but its velocity during the ascent is not necessarily constant.  All distances are measured in metres, and all times in seconds.

Show that an expression for fraction numerator d D subscript p over denominator d t end fraction can be written solely in terms of p, q and D subscript q.

9b
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2 marks

Quinlan is standing a distance of 50 metres from where the balloon takes off.  At a certain moment in time, the balloon is at a distance of 112 metres from point Q and the distance between the balloon and point Q is increasing at a rate of 1.79 straight m space straight s to the power of negative 1 end exponent.  At the same moment in time the distance between point P and the balloon is increasing at a rate of 1.05 straight m space straight s to the power of negative 1 end exponent.

Use the above information and the results of part (a) to determine the distance that Pamela is standing from the point where the balloon takes off.

9c
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3 marks

A third observer, Rhydderch, is standing at point R.  Point R is on the same side of point O as point P is, and it lies on the same horizontal line as points O, P and Q.  At the same moment described above, the distance between the balloon and point R is increasing at a rate of less than 0.8 metres per second. 

Find an inequality to express the minimum distance PR between the point where Rhydderch is standing and the point where Pamela is standing.

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10a
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4 marks

In the diagram below, CDEFG is a pentagon made up of a rectangle CDFG, to one side of which an isosceles triangle DEF has been appended.  In addition sides CD and FG of the rectangle are the same length as the equal sides DE and EFof the triangle.

q10_ib-aa-hl_advanced-differentiation_very-hard_diagram

The pentagon is intended to represent the cross-section of a new building, and the architect would like the area of the pentagon, A , to be the maximum possible for any given perimeter, P

Let CG equals 2 xunits and let DE equals y space units.

By first finding the derivative fraction numerator d P over denominator d x end fraction in terms of x and y, work out the value of the derivative fraction numerator d y over denominator d x end fraction.

10b
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8 marks

By considering the derivative fraction numerator d A over denominator d x end fraction, show that when the area is maximal for a given perimeter the following equation must hold:

20 x to the power of 4 minus 8 x cubed y minus 3 x squared y squared plus 12 x y cubed minus 12 y to the power of 4 equals 0

 

10c
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6 marks

Hence determine (i) the ratio of x to y (in the form k colon 1 for some k to be determined) that gives the maximum area for a given perimeter, and (ii) the maximum possible area for a pentagon of the above form with a perimeter of 100 metres.

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