Polynomial Functions (DP IB Analysis & Approaches (AA)) : Revision Note
Sketching Polynomial Graphs
In exams you’ll commonly be asked to sketch the graphs of different polynomial functions with and without the use of your GDC.
What’s the relationship between a polynomial’s degree and its zeros?
If a real polynomial P(x) has degree n, it will have n zeros which can be written in the form a + bi, where a, b ∈ ℝ
For example:
A quadratic will have 2 zeros
A cubic function will have 3 zeros
A quartic will have 4 zeros
Some of the zeros may be repeated
Every real polynomial of odd degree has at least one real zero
How do I sketch the graph of a polynomial function without a GDC?
Suppose
is a real polynomial with degree n
To sketch the graph of a polynomial you need to know three things:
The y-intercept
Find this by substituting x = 0 to get y = a0
The roots
You can find these by factorising or solving y = 0
The shape
This is determined by the degree (n) and the sign of the leading coefficient (an)
How does the multiplicity of a real root affect the graph of the polynomial?
The multiplicity of a root is the number of times it is repeated when the polynomial is factorised
If
is a root with multiplicity m then
is a factor of the polynomial
The graph either crosses the x-axis or touches the x-axis at a root x = k where k is a real number
If x = k has multiplicity 1 then the graph crosses the x-axis at (k, 0)
If x = k has multiplicity 2 then the graph has a turning point at (k, 0) so touches the x-axis
If x = k has odd multiplicity m ≥ 3 then the graph has a stationary point of inflection at (k, 0) so crosses the x-axis
If x = k has even multiplicity m ≥ 4 then the graph has a turning point at (k, 0) so touches the x-axis

How do I determine the shape of the graph of the polynomial?
Consider what happens as x tends to ± ∞
If an is positive and n is even then the graph approaches from the top left and tends to the top right
If an is negative and n is even then the graph approaches from the bottom left and tends to the bottom right
If an is positive and n is odd then the graph approaches from the bottom left and tends to the top right
and
If an is negative and n is odd then the graph approaches from the top left and tends to the bottom right
and
Once you know the shape, the real roots and the y-intercept then you simply connect the points using a smooth curve
There will be at least one turning point in-between each pair of roots
If the degree is n then there is at most n – 1 stationary points (some will be turning points)
Every real polynomial of even degree has at least one turning point
Every real polynomial of odd degree bigger than 1 has at least one point of inflection
If it is a calculator paper then you can use your GDC to find the coordinates of the turning points
You won’t need to find their location without a GDC unless the question asks you to

Examiner Tips and Tricks
If it is a calculator paper then you can use your GDC to find the coordinates of any turning points
If it is the non-calculator paper then you will not be required to find the turning points when sketching unless specifically asked to
Worked Example
a) The function is defined by
. Sketch the graph of
.

b) The graph below shows a polynomial function. Find a possible equation of the polynomial.


Solving Polynomial Equations
What is “The Fundamental Theorem of Algebra”?
Every real polynomial with degree n can be factorised into n complex linear factors
Some of which may be repeated
This means the polynomial will have n zeros (some may be repeats)
Every real polynomial can be expressed as a product of real linear factors and real irreducible quadratic factors
An irreducible quadratic is where it does not have real roots
The discriminant will be negative: b2 – 4ac < 0
If a + bi (b ≠ 0) is a zero of a real polynomial then its complex conjugate a – bi is also a zero
Every real polynomial of odd degree will have at least one real zero
How do I solve polynomial equations?
Suppose you have an equation P(x) = 0 where P(x) is a real polynomial of degree n
You may be given one zero or you might have to find a zero x = k by substituting values into P(x) until it equals 0
If you know a root then you know a factor
If you know x = k is a root then (x – k) is a factor
If you know x = a + bi is a root then you know a quadratic factor (x – (a + bi))( x – (a – bi))
Which can be written as ((x – a) - bi)((x – a) + bi) and expanded quickly using difference of two squares
You can then divide P(x) by this factor to get another factor
For example: dividing a cubic by a linear factor will give you a quadratic factor
You then may be able to factorise this new factor
Examiner Tips and Tricks
If a polynomial has three or less terms check whether a substitution can turn it into a quadratic
For example:
can be written as
Worked Example
Given that is a zero of the polynomial defined by
, find all three zeros of
.

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