Graphs & Roots of Polynomial Functions (DP IB Analysis & Approaches (AA): HL): Revision Note

Lucy Kirkham

Written by: Lucy Kirkham

Reviewed by: Dan Finlay

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Sketching polynomial graphs

What is a polynomial?

  • A polynomial is a sum of terms of the form axk where

    • a is a real number

    • k≥0 is an integer

  • A polynomial looks like P(x)=anxn+...+a2x2+a1x+a0

  • The degree of a polynomial is its highest power

    • e.g. the degree of 4x3+5x2−7 is 3

    • e.g. the degree of 2x−7 is 1

  • The leading term of a polynomial is the term with the highest power

    • e.g. the leading term of 4x3+5x2−7 is 4x3

What’s the relationship between a polynomial’s degree and its zeros?

  • If a real polynomial P(x) has degree n

    • it will have n zeros which can be written in the form a+bi, where a, b ∈ ℝ

      • these zeros are not necessarily distinct

      • they can be repeated

  • For example:

    • A quadratic will have 2 zeros

    • A cubic function will have 3 zeros

    • A quartic will have 4 zeros

  • Every real polynomial of odd degree has at least one real zero

What do I need to know to sketch the graph of a polynomial function?

  • Suppose P(x)=anxn+an−1xn−1+ …+a1x+a0 is a real polynomial with degree n

  • To sketch the graph of a polynomial you need to know three things:

    • The y-intercept

      • Find this by substituting x = 0 to get y = a0

    • The roots

      • You can find these by factorising or solving y = 0

    • The shape

      • This is determined by the degree (n) and the sign of the leading coefficient (an)

How does the multiplicity of a real root affect the graph of the polynomial?

  • The multiplicity of a root is the number of times it is repeated when the polynomial is factorised

    • If x=k is a root with multiplicity m then  (x−k)m is a factor of the polynomial

  • The graph either crosses the x-axis or touches the x-axis at a root x = k where k is a real number

    • If x=k has multiplicity 1 then the graph crosses the x-axis at (k, 0)

    • If x=k has multiplicity 2 then the graph has a turning point at (k, 0) so touches the x-axis 

      • If x=k has odd multiplicity m ≥ 3 then the graph has a stationary point of inflection at (k, 0) so crosses the x-axis

      • If x=k has even multiplicity m ≥ 4 then the graph has a turning point at (k, 0) so touches the x-axis

Three graphs showing curves with factors: (x-k), (x-k)², (x-k)³. Each describes how the curve interacts with the x-axis at point k.
Examples of how the multiplicity of roots affects the shape of the graph

How do I determine the shape of the graph of the polynomial?

  • Consider what happens as x tends to ± ∞

The leading coefficient an is...

The degree n is...

The graph approaches from the...

The graph tends to the...

positive

even

top left

limx→−∞f(x)=+∞

top right

limx→∞f(x)=+∞

negative

even

bottom left

limx→−∞f(x)=−∞

bottom right

limx→∞f(x)=−∞

positive

odd

bottom left

limx→−∞f(x)=−∞

top right

limx→∞f(x)=+∞

negative

odd

top left

limx→−∞f(x)=+∞

bottom right

limx→∞f(x)=−∞

Graphs of polynomial functions showing end behaviours based on the sign and parity of the leading coefficient and degree: positive/negative, even/odd.
Examples of the shapes of polynomial graphs

How do I sketch the graph of a polynomial function?

  • Plot the y-intercept

  • Plot the roots

  • Identify the multiplicity of each root

  • Identify where the graph starts and ends

  • Connect the points using a smooth curve

  • There will be at least one turning point in-between each pair of roots

    • If the degree is n then there is at most n – 1 stationary points

      • Every real polynomial of even degree has at least one turning point

      • Every real polynomial of odd degree bigger than 1 has at least one point of inflection

Examiner Tips and Tricks

If it is a calculator paper, then you can use your GDC to find the coordinates of any turning points.

If it is the non-calculator paper, then you will not be required to find the turning points when sketching unless specifically asked to.

Worked Example

a) The function  f is defined by  f(x)=(x+1)(2x−1)(x−2)2. Sketch the graph of  y=f(x).

Answer:

2-7-3-ib-aa-hl-sketching-polynomial-a-we-solution

b) The graph below shows a polynomial function. Find a possible equation of the polynomial.

Answer:

2-7-3-we-image
2-7-3-ib-aa-hl-sketching-polynomial-b-we-solution

Solving polynomial equations

What is the fundamental theorem of algebra?

  • The fundamental theorem of algebra states that every real polynomial with degree n can be factorised into n complex linear factors

    • Some of which may be repeated

    • This means the polynomial will have n zeros (some may be repeats)

  • Every real polynomial can be expressed as a product of real linear factors and real irreducible quadratic factors

    • An irreducible quadratic is where it does not have real roots

      • The discriminant will be negative: b2 – 4ac < 0

  • If a + bi (b ≠ 0) is a zero of a real polynomial

    • then its complex conjugate a – bi is also a zero

  • Every real polynomial of odd degree will have at least one real zero

How do I solve polynomial equations?

  • Let P(x) = 0 where P(x) is a real polynomial of degree n

    • P(x)=anxn+an−1xn−1+ …+a1x+a0

  • In your exam

    • you may be given one zero

    • or you might have to find a zero x=k

      • You can do this by substituting values into P(x) until it equals 0

  • If you know x=k is a real root

    • then (x−k) is a factor

  • If you know x=a+bi is a non-real root

    • then you know a quadratic factor (x−(a+bi))(x−(a−bi))

      • This can be written as ((x−a)−bi)((x−a)+bi)

      • And it simplifies to ((x−a)2+b2)

  • You can use polynomial division to divide P(x) by a factor to get another factor

    • e.g. dividing a cubic by a linear factor will give you a quadratic factor

    • You then may be able to factorise this new factor

  • You can solve the polynomial equation once you know all of its factors

Worked Example

Given that  x=12 is a zero of the polynomial defined by  f(x)=2x3−3x2+5x−2, find all three zeros of  f.

Answer:

2-7-3-ib-aa-hl-solving-polynomials-we-solution

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Lucy Kirkham

Author: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.