Proof by Induction (DP IB Maths: AA HL)

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Proof by Induction

What is proof by induction?

  • Proof by induction is a way of proving a result is true for a set of integers by showing that if it is true for one integer then it is true for the next integer
  • It can be thought of as dominoes:
    • All dominoes will fall down if:
      • The first domino falls down
      • Each domino falling down causes the next domino to fall down

What are the steps for proof by induction?

  • STEP 1: The basic step
    • Show the result is true for the base case
    • This is normally n = 1 or 0 but it could be any integer
      • For example: To prove sum from r equals 1 to n of r squared equals 1 over 6 n left parenthesis n plus 1 right parenthesis left parenthesis 2 n plus 1 right parenthesis is true for all integers n ≥ 1 you would first need to show it is true for n = 1: 
      • sum from r equals 1 to 1 of r squared equals 1 over 6 left parenthesis 1 right parenthesis left parenthesis left parenthesis 1 right parenthesis plus 1 right parenthesis left parenthesis 2 left parenthesis 1 right parenthesis plus 1 right parenthesis
  • STEP 2: The assumption step
    • Assume the result is true for n = k for some integer k
      • For example: Assume sum from r equals 1 to k of r squared equals 1 over 6 k left parenthesis k plus 1 right parenthesis left parenthesis 2 k plus 1 right parenthesis is true
    • There is nothing to do for this step apart from writing down the assumption
  • STEP 3: The inductive step
    • Using the assumption show the result is true for n = k + 1
    • It can be helpful to simplify LHS & RHS separately and show they are identical
    • The assumption from STEP 2 will be needed at some point
      • For example: L H S equals sum from r equals 1 to k plus 1 of r squared and R H S equals 1 over 6 open parentheses k plus 1 close parentheses open parentheses open parentheses k plus 1 close parentheses plus 1 close parentheses open parentheses 2 open parentheses k plus 1 close parentheses plus 1 close parentheses
  • STEP 4: The conclusion step
    • State the result is true
    • Explain in words why the result is true
    • It must include:
      • If true for n = k then it is true for n = k + 1
      • Since true for n = 1 the statement is true for all n ∈ ℤ, n ≥ 1  by mathematical induction
    • The sentence will be the same for each proof just change the base case from n = 1 if necessary

What type of statements might I be asked to prove by induction?

  • Sums of sequences
    • If the terms involve factorials then open parentheses k plus 1 close parentheses factorial equals open parentheses k plus 1 close parentheses cross times open parentheses k factorial close parentheses is useful
    • These can be written in the form sum from r equals 1 to n of f open parentheses r close parentheses equals g open parentheses n close parentheses
    • A useful trick for the inductive step is using sum from r equals 1 to k plus 1 of f open parentheses r close parentheses equals f open parentheses k plus 1 close parentheses plus sum from r equals 1 to k of f open parentheses r close parentheses
  • Divisibility of an expression by an integer
    • These can be written in the form f open parentheses n close parentheses equals m cross times q subscript n where m & qn are integers
    • A useful trick for the inductive step is using a to the power of k plus 1 end exponent equals a cross times a to the power of k
  • Complex numbers
    • You can use proof by induction to prove de Moivre’s theorem
  • Derivatives
    • Such as chain rule, product rule & quotient rule
    • These can be written in the form f to the power of open parentheses n close parentheses end exponent open parentheses x close parentheses equals g open parentheses x close parentheses
    • A useful trick for the inductive step is using f to the power of open parentheses k plus 1 close parentheses end exponent open parentheses x close parentheses equals fraction numerator d over denominator d x end fraction open parentheses f to the power of open parentheses k close parentheses end exponent open parentheses x close parentheses close parentheses
    • You will have to use the differentiation rules

Examiner Tip

  • Learn the steps for proof by induction and make sure you can use the method for a number of different types of questions before going into the exam
  • The trick to answering these questions well is practicing the pattern of using each step regularly 

Worked example

Prove by induction that sum from r equals 1 to n of r open parentheses r minus 3 close parentheses equals 1 third n open parentheses n minus 4 close parentheses open parentheses n plus 1 close parentheses for n element of straight integer numbers to the power of plus.

1-5-1-ib-aa-hl-proof-by-induction-we-solution

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Dan

Author: Dan

Expertise: Maths

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.