Practice Paper 2 (DP IB Maths: AA HL)

Practice Paper Questions

1a
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4 marks

The following table shows the mean height, y cm, of primary school children who are age x years old.

Age , bold italic x years 6.25 7.35 8.5 9.25 10.75
Mean Height,bold italic y cm 115 121 129 136 140

The relationship between x and y can be modelled by the regression line of y on x with equation y space equals space a x space plus space b.

i)
Find the value of a and the value of b.

ii)
Write down the value of Pearson's product-moment correlation coefficient, r.
1b
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2 marks

Use your regression equation from part (a) (i) to estimate the height of a child aged 9 years old.

1c
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1 mark

 Explain why it is not appropriate to use the regression equation to estimate the age of a child who is 133 cm tall.

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2a
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2 marks

An arithmetic sequence with a common difference -3.5 has first term 77.

Given that the rth term of the sequence is zero, find the value of r.

2b
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3 marks

Find the maximum value of the sum of the first n terms of the sequence.

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3
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9 marks

A and B are independent events, such that straight P open parentheses A close parentheses = 0.25 and straight P open parentheses B close parentheses = 0.52. C is another event, such that B and C are mutually exclusive and straight P open parentheses A space intersection space C close parentheses = 0.09.

Given that straight P left parenthesis space A space union space B space union space C right parenthesis= 0.95, find

i)
straight P open parentheses A space intersection space B close parentheses

ii)
straight P open parentheses C close parentheses

iii)
straight P open parentheses A apostrophe intersection B apostrophe close parentheses

iv)
straight P open parentheses A vertical line C apostrophe close parentheses

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4a
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1 mark

Let f open parentheses x close parentheses space equals space fraction numerator 5 minus x squared over denominator 3 end fraction and g open parentheses x close parentheses equals 4 minus 3 over x,  where each function has the largest possible valid domain.

Write down the range of f.

4b
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2 marks

Write down the domain and range of g.

4c
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3 marks

Find

i)
open parentheses f ring operator g close parentheses space open parentheses x close parentheses
ii)
left parenthesis g space ring operator space f right parenthesis space left parenthesis x right parenthesis.

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5a
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2 marks

The number of bacteria, n, in a dish, after t minutes is given byspace n equals 5231 e to the power of 0.12 t end exponent.

Find the initial amount of bacteria.

5b
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3 marks

Find the amount of bacteria after 12 minutes. Give your answer in the form a space cross times space 10 to the power of k, where 1 space less or equal than space a space less than space 10 comma space k space element of space straight integer numbers.

5c
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2 marks

Find the value of t when n space equals space 2.7 space cross times space 10 to the power of 4.

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6a
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2 marks

A UK energy company charges £0.22 per kilowatt hour (kWh) of electricity used.
The amount of energy used per day by the company’s customers, X
 kWh, follows the following probability density function

f left parenthesis x right parenthesis equals open curly brackets table row cell fraction numerator x left parenthesis k minus x right parenthesis over denominator 972 end fraction comma end cell cell 0 less or equal than x less or equal than 18 end cell row cell space space space space space space space space space space space space space space 0 comma end cell otherwise end table close

Show that k equals 18.

6b
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6 marks

A customer’s total daily charge consists of a fixed (standing) charge of £0.38 per day plus the charge for the electricity used.

(i)
Find the expected total daily charge.
(ii)
Find the standard deviation for the total daily charge.

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7
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5 marks

Consider the nine letters in the word MAGNITUDE.

Find the number of ways that the nine letters may be arranged if

(i)
there are no restrictions
(ii)
the four vowels (A, I, U, E) must all be together
(iii)
the arrangement starts with the letter M and ends with the letter E.

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8
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5 marks

Consider z equals cis space theta where z element of straight complex numbers comma space z not equal to 1.

Show that Re open parentheses fraction numerator 1 plus straight z over denominator 1 minus straight z end fraction close parentheses equals 0.

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9a
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5 marks

The binomial series expansion for open parentheses 1 plus t close parentheses to the power of negative 1 end exponent is given by

 open parentheses 1 plus t close parentheses to the power of negative 1 end exponent equals 1 minus t plus t squared minus... 

Using the above result and the Maclaurin series for cos open parentheses 2 x close parentheses, show that the Maclaurin series for sec open parentheses 2 x close parentheses is

1 plus 2 x squared plus 10 over 3 x to the power of 4 plus...
9b
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3 marks

By using the result from part (a) and the Maclaurin series for ln open parentheses 1 plus x close parentheses , find the value of the limit

limit as x rightwards arrow 0 of open parentheses fraction numerator x ln open parentheses 1 plus 3 x close parentheses over denominator sec open parentheses 2 x close parentheses minus 1 end fraction close parentheses

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10a
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2 marks

The Strike A Light! matchstick company produces matchsticks with a length, X mm, that is normally distributed with mean 45 and variance sigma squared.

The probability that X is greater than 45.37 is 0.1714.

Find straight P left parenthesis 44.63 space less than space X space less than space 45.37 right parenthesis.

10b
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5 marks
i)
Find sigma, the standard deviation of X.
ii)
Hence, find the probability that a randomly selected matchstick has a length
less than 44.5 mm.
10c
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3 marks

Andrew has a box of Strike A Light! matches with fifteen matchsticks remaining in it.Those matchsticks may be assumed to be a random sample. Let Y represent the number of matchsticks in Andrew's box with lengths less than 44.5 mm.

Find straight E left parenthesis Y right parenthesis.

10d
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2 marks

Find the probability that exactly one of the matchsticks in Andrew's box has a length less than 44.5 mm.

10e
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3 marks

A Strike A Light! matchstick is selected at random and is found to have a length greater than 44.5 mm.

Find the probability that the length of the matchstick is between 44.63 mm and 45.37 mm.

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11a
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6 marks

Paola is modelling a small vase from her house for her maths project. To model the edge of the vase in cross-section, she decides to use a function f of the form

f open parentheses x close parentheses equals fraction numerator q straight e to the power of x over 2 end exponent over denominator 2 plus straight e to the power of x end fraction

 

where x element of straight real numbers comma space x greater or equal than 0 and q element of straight real numbers to the power of plus

The function and the vase are represented in the diagrams below.

mi-q11a-ib-aa-sl-pp2-set-c-maths-dig1

mi-q11a-ib-aa-sl-pp2-set-c-maths-dig2



The vertical height of the vase, OB, is measured along the x-axis. The radius of the vase’s opening is OA, and its base radius is BC. 

To model the vase, she will rotate by 2 pi radians about the x-axis the region enclosed by the graph of y equals f open parentheses x close parentheses ,  the x-axis, the y-axis, and the line x equals ln space 43

Show that the volume of the solid of revolution thus formed is fraction numerator 14 q squared straight pi over denominator 45 end fraction units cubed.

11b
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2 marks

The volume of the actual vase is 100 cm cubed.

Use this information to find the value of q.

11c
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4 marks

Find the cross-sectional radius of the vase

(i)     at its base,

(ii)    at its widest point.

11d
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4 marks

Paola wants to investigate how the cross-sectional radius of the vase changes.

Sketch a graph of the derivative of f, and use it to find the value of x at which the cross-sectional radius of the vase is decreasing most rapidly.

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12a
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1 mark

A function g is defined by g open parentheses x close parentheses equals arccos open parentheses fraction numerator x squared minus 1 over denominator x squared plus 1 end fraction close parentheses comma space x element of straight real numbers. 

Show that g is an even function.

12b
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2 marks

By considering the limit of g as x tends to infinity, show that the graph of  y equals g open parentheses x close parentheses has a horizontal asymptote and state its equation.

12c
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9 marks
(i)
Show that  g to the power of apostrophe open parentheses x close parentheses equals fraction numerator negative 2 x over denominator open parentheses square root of x squared end root close parentheses open parentheses x squared plus 1 close parentheses end fraction for x element of straight real numbers comma space x greater or equal than 0.

 

(ii)
Considering the fact that square root of x squared end root equals open vertical bar x close vertical bar commaand also the expression for g to the power of apostrophe open parentheses x close parentheses above, show that g is increasing for x less than 0.
12d
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5 marks

A new function, h, is created by restricting the domain of g, such that h open parentheses x close parentheses equals arccos open parentheses fraction numerator x squared minus 1 over denominator x squared plus 1 end fraction close parentheses comma space x element of straight real numbers comma space x greater or equal than 0.,  ,  .

Find an expression for h to the power of negative 1 end exponent open parentheses x close parentheses, carefully considering the range of h in determining your final answer.

12e
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2 marks

State the domain of h to the power of negative 1 end exponent open parentheses x close parentheses.

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