Further Integration (DP IB Applications & Interpretation (AI))

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  • What is integral sin x space straight d x?

    integral sin x space straight d x equals negative cos x plus C

    This is in the exam formula booklet.

  • What is integral cos x space straight d x?

    integral cos x space straight d x equals sin x plus C

    This is in the exam formula booklet.

  • True or False?

    integral sin open parentheses a x plus b close parentheses equals negative 1 over a cos open parentheses a x close parentheses plus C

    False.

    integral sin open parentheses a x plus b close parentheses equals negative 1 over a cos open parentheses a x plus b close parentheses plus C

    This is not in the exam formula booklet.

  • What is integral straight e to the power of x space straight d x?

    integral straight e to the power of x space straight d x equals straight e to the power of x plus C

    This is in the exam formula booklet.

  • What is integral 1 over x space straight d x?

    integral 1 over x space straight d x equals ln open vertical bar x close vertical bar plus C

    This is in the exam formula booklet.

  • True or False?

    integral straight e to the power of a x plus b end exponent space straight d x equals straight e to the power of a x plus b end exponent plus C.

    False.

    integral straight e to the power of a x plus b end exponent space straight d x equals 1 over a straight e to the power of a x plus b end exponent plus C.

    This is not in the exam formula booklet.

  • What is integral cos open parentheses a x plus b close parentheses space straight d x?

    integral cos open parentheses a x plus b close parentheses space straight d x equals 1 over a sin open parentheses a x plus b close parentheses plus C

    This is not in the exam formula booklet.

  • What is integral fraction numerator 1 over denominator a x plus b end fraction space straight d x?

    integral fraction numerator 1 over denominator a x plus b end fraction space straight d x equals 1 over a ln open vertical bar a x plus b close vertical bar plus C

    This is not in the exam formula booklet.

  • True or False?

    integral open parentheses a x plus b close parentheses to the power of n space straight d x equals fraction numerator 1 over denominator a open parentheses n plus 1 close parentheses end fraction open parentheses a x plus b close parentheses to the power of n plus 1 end exponent plus C, so long as n not equal to negative 1.

    True.

    integral open parentheses a x plus b close parentheses to the power of n space straight d x equals fraction numerator 1 over denominator a open parentheses n plus 1 close parentheses end fraction open parentheses a x plus b close parentheses to the power of n plus 1 end exponent plus C, so long as n not equal to negative 1.

    This is not in the exam formula booklet.

    If n not equal to negative 1, use integral fraction numerator 1 over denominator a x plus b end fraction space straight d x equals 1 over a ln open vertical bar a x plus b close vertical bar plus C.

  • True or False?

    When integrating trigonometric functions, angles should be measured in degrees.

    False.

    When integrating trigonometric functions, angles must be measured in radians.

  • What is integral fraction numerator 1 over denominator cos squared x end fraction straight d x?

    integral fraction numerator 1 over denominator cos squared x end fraction straight d x equals tan x plus C

    This is in the exam formula booklet.

  • What is integral fraction numerator 1 over denominator cos squared open parentheses a x plus b close parentheses end fraction space straight d x?

    integral fraction numerator 1 over denominator cos squared open parentheses a x plus b close parentheses end fraction space straight d x equals 1 over a tan open parentheses a x plus b close parentheses plus C

    This is not in the exam formula booklet.

  • What is reverse chain rule?

    Reverse chain rule, also known as integrating by inspection, is spotting that the chain rule could have been used to differentiate another function and turn it into the function you are trying to integrate.

  • True or false?

    An integral in the form integral fraction numerator f to the power of apostrophe open parentheses x close parentheses over denominator f open parentheses x close parentheses end fraction space straight d x can be integrated with the reverse chain rule.

    True.

    An integral in the form integral fraction numerator f to the power of apostrophe open parentheses x close parentheses over denominator f open parentheses x close parentheses end fraction space straight d x can be integrated with the reverse chain rule, by using integral fraction numerator f to the power of apostrophe open parentheses x close parentheses over denominator f open parentheses x close parentheses end fraction space straight d x equals ln vertical line f open parentheses x close parentheses vertical line plus C.

    E.g. integral fraction numerator 2 x plus 7 over denominator x squared plus 7 x minus 12 end fraction space straight d x equals ln open vertical bar x squared plus 7 x minus 12 close vertical bar plus C

    This is not in the exam formula booklet.

  • How can you integrate an integral of the form integral g to the power of apostrophe open parentheses x close parentheses f apostrophe open parentheses g open parentheses x close parentheses close parentheses space straight d x with the reverse chain rule?

    You can integrate an integral of the form integral g to the power of apostrophe open parentheses x close parentheses f apostrophe open parentheses g open parentheses x close parentheses close parentheses space straight d x with the reverse chain rule by using integral g to the power of apostrophe open parentheses x close parentheses f apostrophe open parentheses g open parentheses x close parentheses close parentheses space straight d x equals f open parentheses g open parentheses x close parentheses close parentheses plus C.

    E.g. integral 2 x cos open parentheses x squared close parentheses space straight d x equals sin open parentheses x squared close parentheses plus C.

    This is not in the exam formula booklet.

  • What is the "adjust and compensate" method for integration?

    The adjust and compensate method is a technique used in reverse chain rule integration to deal with coefficients that don't match exactly.

    E.g. rewriting integral x cos open parentheses x squared close parentheses space straight d x as 1 half integral 2 x cos open parentheses x squared close parentheses space straight d x.

    • the thing inside the integral has been adjusted by multiplying by 2

    • 1 half is placed in front of the integral to compensate

    2 x cos open parentheses x squared close parentheses can be integrated directly using reverse chain rule.

  • What is integration by substitution?

    Integration by substitution is a method used (e.g. when reverse chain rule is difficult to spot or awkward to use) to simplify an integral by rewriting it in terms of an alternative variable.

    E.g. an integral in x might be rewritten as a simpler integral in u.

  • What is the first step in integration by substitution?

    The first step in integration by substitution is to identify the substitution to be used.

    When integrating a composite function, f open parentheses g open parentheses x close parentheses close parentheses, the substitution will frequently be u equal to the secondary (or 'inside') function in the composite function, i.e u equals g open parentheses x close parentheses.

  • True or False?

    In integration by substitution, fraction numerator straight d u over denominator straight d x end fraction can be treated like a fraction.

    True.

    In integration by substitution, fraction numerator straight d u over denominator straight d x end fraction can be treated like a fraction.

    (Note: it is not actually a fraction, it is a gradient. But it works to treat it like a fraction in integrations like this.)

  • What would be a suitable substitution to use when integrating integral open parentheses 2 x plus 5 close parentheses straight e to the power of x squared plus 5 x minus 3 end exponent space straight d x?

    When integrating integral open parentheses 2 x plus 5 close parentheses straight e to the power of x squared plus 5 x minus 3 end exponent space straight d x, a suitable substitution would be u equals x squared plus 5 x minus 3.

    Then fraction numerator straight d u over denominator straight d x end fraction equals 2 x plus 5 space space rightwards double arrow space space straight d u equals open parentheses 2 x plus 5 close parentheses straight d x, so the integral can be rewritten as integral straight e to the power of u space straight d u.

  • What should be done with the integration limits when using substitution for a definite integral?

    When using substitution for a definite integral, the integration limits should be changed from x-values to u-values.

  • What is the final step in integration by substitution for an indefinite integral?

    The final step in integration by substitution for an indefinite integral is to substitute x (or whatever the original variable is) back in.

    The final answer should always be in terms of the original variable.

  • True or False?

    When using substitution for a definite integral, you must always substitute x back in before evaluating.

    False.

    When using substitution for a definite integral, you can evaluate using the u limits without substituting x back in.

  • What does negative integral refer to?

    A negative integral is a definite integral that results in a negative value.

    This occurs when the area being calculated by the integral is below the x-axis.

  • True or False?

    The area under a curve is always positive.

    True.

    The area under a curve is always positive, even if the definite integral is negative.

  • What is the formula for finding the area under a curve using the modulus function?

    The formula for finding the area under a curve using the modulus function is A equals integral subscript a superscript b open vertical bar y close vertical bar space straight d x

    Where:

    • A is the area being calculated

    • a and b are the integration limits

    • y is the equation of the curve in terms of x

    This formula is in the exam formula booklet.

  • What should be done when finding the area under a curve that is partially below the x-axis?

    When finding the area under a curve that is partially below the x-axis, use the modulus version of the area under a curve integral A equals integral subscript a superscript b open vertical bar y close vertical bar space straight d x.

    This will automatically turn any negative parts of the integral positive.

  • True or False?

    When finding the area between a curve and a line, you always subtract the area under the line from the area under the curve.

    False.

    When finding the area between a curve and a line, you may need to add or subtract areas depending on their relative positions.

  • True or False?

    When finding the area between a curve and a line, you always need to use integration to find any relevant areas.

    False.

    When finding the area between a curve and a line, you don't always need to use integration to find relevant areas.

    For example, you may use basic area formulae (trapezoid, right triangle) to find the area under the line.

  • What should you do if no diagram is provided when solving area problems using integrals?

    If no diagram is provided when solving area problems using integrals, you should sketch a diagram, even if the curves are not completely accurate.

  • What is the area between a curve and the y-axis?

    The area between a curve and the y-axis is the region bounded by the graph of y=f(x), the y-axis, and two horizontal lines y=a and y=b.

    Graph showing example of an 'area between a curve and the y-axis'.
  • What is the formula for finding the area between a curve and the y-axis?

    The formula for finding the area between a curve and the y-axis is A equals integral subscript a superscript b open vertical bar x close vertical bar straight d y

    Where:

    • A is the area to be found

    • y equals a and y equals b are the equations of the horizontal lines bounding the area

    • x equals g open parentheses y close parentheses is the equation of the curve expressed as a function of y

    This is in the exam formula booklet.

  • True or False?

    The function y=f(x) describing the curve must be rearranged into the form x=g(y) when finding the area between a curve and the y-axis.

    True.

    The function y=f(x) describing the curve must be rearranged into the form x=g(y) when finding the area between a curve and the y-axis.

  • What is a definite integral?

    A definite integral is an integral with specified upper and lower integration limits.

    A definite integral is represented in the form integral subscript a superscript b f open parentheses x close parentheses space straight d x

    Where:

    • a is the lower integration limit

    • b is the upper integration limit

  • A definite integral can be evaluated using the equation integral subscript a superscript b f open parentheses x close parentheses space straight d x equals F open parentheses b close parentheses minus F open parentheses a close parentheses.

    What is the function F open parentheses x close parentheses, whose values appear on the right-hand side of the equation?

    In the equation integral subscript a superscript b f open parentheses x close parentheses space straight d x equals F open parentheses b close parentheses minus F open parentheses a close parentheses, used to evaluate a definite integral, the function F open parentheses x close parentheses is an antiderivative of f open parentheses x close parentheses.

    This is a result of the Fundamental Theorem of Calculus.

  • True or False?

    The constant of integration is needed in definite integration.

    False.

    The constant of integration is not needed in definite integration.

  • What is a volume of revolution?

    A volume of revolution is the volume of a solid formed when an area bounded by a function y=f(x) is rotated 2π radians (or 360°) around an axis.

    An illustration of a volume of revolution formed by rotating a function y=f(x) about the x-axis.
  • State the formula for a volume of revolution around the x-axis.

    The formula for the volume of revolution around the x-axis is V equals integral subscript a superscript b pi y squared straight d x

    Where:

    • V is the volume to be found

    • x equals a and x equals b are the equations of the vertical lines bounding the area to be rotated

    • y squared is the square of the equation of the curve y equals f open parentheses x close parentheses

    This is in the exam formula booklet.

  • True or False?

    The limits a and b to be used in the volume of revolution formula are always given directly in the question.

    False.

    The limits a and b to be used in the volume of revolution formula are not always given directly in the question.

    You may need to work the limits out. They could involve the y-axis (x=0) or a root of y=f(x).

  • State the formula for a volume of revolution around the y-axis.

    The formula for the volume of revolution around the y-axis is V equals integral subscript a superscript b pi x squared straight d y

    Where:

    • V is the volume to be found

    • y equals a and y equals b are the equations of the horizontal lines bounding the area to be rotated

    • x squared is the square of the equation of the curve x equals g open parentheses y close parentheses

    This is in the exam formula booklet.

    (Note that an equation of the curve in y equals f open parentheses x close parentheses form will need to be rearranged into x equals g open parentheses y close parentheses form to use this formula.)

  • True or False?

    When calculating the volume of a revolution about the y-axis, the equation of the curve must always be rearranged from y=f(x) form to x=g(y) form.

    True.

    When calculating the volume of a revolution about the y-axis, the equation of the curve must always be rearranged from y=f(x) form to x=g(y) form.