Vector Equations of Lines (DP IB Analysis & Approaches (AA))

Flashcards

1/24

Enjoying Flashcards?
Tell us what you think

Cards in this collection (24)

  • A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    What does the vector bold italic a represent?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The vector bold italic a represents a position vector of any point on the line.

  • A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    What does the vector bold italic b represent?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The vector bold italic b represents a direction vector.

  • True or False?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The value of lambda determines where a point lies on the line.

    True.

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The value of lambda determines where a point lies on the line.

    lambda is similar to x in the equation of a line in 2D, y equals m x plus c.

  • True or False?

    For any line, there are an infinite number of ways of writing its equation in vector form.

    True.

    For any line, there are an infinite number of ways of writing its equation in vector form.

    This is because there are an infinite number of choices for the vectors bold italic aand bold italic b.

  • True or False?

    A line passes through the points with position vectors bold italic a and bold italic b. A possible equation of the line is bold italic r equals bold italic b bold minus bold italic a plus lambda bold italic b.

    False.

    A line passes through the points with position vectors bold italic a and bold italic b. A possible equation of the line is bold italic r equals bold italic a plus lambda open parentheses bold italic b minus bold italic a close parentheses.

    Other options are bold italic r equals bold italic a plus lambda open parentheses bold italic a minus bold italic b close parentheses, bold italic r equals bold italic b plus lambda open parentheses bold italic b minus bold italic a close parentheses and bold italic r equals bold italic b plus lambda open parentheses bold italic a minus bold italic b close parentheses.

  • If the equation of a line is given in vector form, how can you determine whether a given point lies on the line?

    If the equation of a line is given in vector form, you can determine whether a given point lies on the line by:

    • setting the equation of the line equal to the position vector of the point, bold italic a plus lambda bold italic b equals bold italic p,

    • forming three equations using the components of the vectors, e.g. a subscript 1 plus lambda b subscript 1 equals p subscript 1,

    • solving any of the equations to find value for lambda,

    • checking if this value satisfies the other two equations.

    If the value satisfies the other two equations then the point lies on the line.

  • The direction vector of a line is open parentheses table row l row m row n end table close parentheses and the position vector of a point that lies on the line is open parentheses table row cell x subscript 0 end cell row cell y subscript 0 end cell row cell z subscript 0 end cell end table close parentheses. What is the equation of the line in parametric form?

    The direction vector of a line is open parentheses table row l row m row n end table close parentheses and the position vector of a point that lies on the line is open parentheses table row cell x subscript 0 end cell row cell y subscript 0 end cell row cell z subscript 0 end cell end table close parentheses. The equation of the line in parametric form is

    table row x equals cell x subscript 0 plus lambda l end cell row y equals cell y subscript 0 plus lambda m end cell row z equals cell z subscript 0 plus lambda n end cell end table

    This is given in the formula booklet.

  • True or False?

    The Cartesian equation of a line in 3D is of the form a x plus b y plus c z equals d.

    False.

    The Cartesian equation of a line in 3D is not of the form a x plus b y plus c z equals d. This is an equation of a plane.

    The cartesian equation of a line in 3D is in the form begin mathsize 16px style fraction numerator x minus blank x subscript 0 over denominator l end fraction equals blank fraction numerator y minus blank y subscript 0 over denominator m end fraction equals blank fraction numerator z minus blank z subscript 0 over denominator n end fraction end style.
    This is given in the formula booklet.

  • What is the Cartesian equation of a line in 3D?

    The Cartesian equation of a line in 3D is begin mathsize 16px style fraction numerator x minus blank x subscript 0 over denominator l end fraction equals blank fraction numerator y minus blank y subscript 0 over denominator m end fraction equals blank fraction numerator z minus blank z subscript 0 over denominator n end fraction end style.

    This is given in the formula booklet.

  • How would you write the Cartesian equation of a line if one (or more) of the components of the direction vector is zero?

    For example, if the direction vector is open parentheses table row 2 row 0 row 3 end table close parentheses.

    If one (or more) of the components of the direction vector of a line is zero then you write that the corresponding variable is equal to the relevant coordinate. You would put this as a separate equation after the other equation such as fraction numerator x minus x subscript 0 over denominator l end fraction equals fraction numerator z minus z subscript 0 over denominator n end fraction comma space y equals y subscript 0

    For example, if the direction vector is open parentheses table row 2 row 0 row 3 end table close parentheses then the Cartesian equation would look like fraction numerator x minus x subscript 0 over denominator 2 end fraction equals fraction numerator z minus z subscript 0 over denominator 3 end fraction comma space y equals y subscript 0.

  • Given the Cartesian equation of a line, how can you find a vector equation of the line?

    Given the equation begin mathsize 16px style fraction numerator x minus blank x subscript 0 over denominator l end fraction equals blank fraction numerator y minus blank y subscript 0 over denominator m end fraction equals blank fraction numerator z minus blank z subscript 0 over denominator n end fraction end style, to find a vector equation:

    • set the Cartesian equation equal to lambda,

    • rearrange each section of the equation to find expressions for x, y and z in terms of lambda,

    • the coefficients of lambda form the direction vector and the constant terms form the position vector of a point on the line.

  • An object is moving with constant velocity, bold italic v, along a straight line. The position vector of the starting point is bold italic r subscript bold 0. What is an equation for the position vector of the object after time t?

    Then the position of the object at the time, t can be given by bold italic r equals bold italic r subscript 0 plus t bold italic v where:

    • bold italic r subscript 0 is the position vector of the object when t equals 0,

    • bold italic v is the vector for the constant velocity,

    • t is the time.

  • An object is moving with velocity vector bold italic v. How do you find the speed of the object?

    An object is moving with velocity vector bold italic v. You can find the speed by finding the magnitude of the velocity vector, open vertical bar bold italic v close vertical bar.

  • How can you check to see if a line is parallel to another line?

    A line is parallel to another line if their direction vectors are scalar multiples.

  • How can you check whether two vector equations represent the same line?

    Two vector equations represent the same line if:

    • the direction vectors are scalar multiples,

    • and a point on one line also lies on the other line.

  • True or False?

    If two lines in 3D are not parallel then they must intersect.

    False.

    If two lines in 3D are not parallel then they could intersect, but they do not have to intersect; they could be skew.

  • What are skew lines?

    Skew lines are lines that are not parallel and do not intersect.

  • How do you determine whether two non-parallel lines intersect or are skew?

    To determine whether two non-parallel lines intersect or are skew, you:

    • set the vector equations equal to each other, bold italic a plus lambda bold italic b equals bold italic c plus mu bold italic d

    • use the components to form three equations in terms of lambda and mu,

    • solve any two of these equations simultaneously,

    • check whether these values for lambda and mu satisfy the third equation.

    If the third equation is satisfied then the lines intersect, otherwise they are skew.

  • How do you find the angles between two lines?

    The angles between two lines can be found by finding the angles between a direction vector of one line and a direction vector of the other line. You can use the scalar product to do this.

  • True or False?

    One angle between a line (bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1) and another line (bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2) is given by the equation cos theta equals fraction numerator bold italic b subscript bold 1 times bold italic b subscript bold 2 over denominator open vertical bar bold italic b subscript bold 1 close vertical bar open vertical bar bold italic b subscript bold 2 close vertical bar end fraction.

    True.

    One angle between a line (bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1) and another line (bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2) is given by the equation cos theta equals fraction numerator bold italic b subscript bold 1 times bold italic b subscript bold 2 over denominator open vertical bar bold italic b subscript bold 1 close vertical bar open vertical bar bold italic b subscript bold 2 close vertical bar end fraction.

  • How do you find the shortest distance between a point, P, and a line, bold italic r bold space equals bold space bold italic a plus straight lambda bold italic b?

    To find the shortest distance between a point, P, and a line, bold italic r bold space equals bold space bold italic a plus straight lambda bold italic b, you

    • let F be the point on the line closest to P, bold italic f equals bold italic a plus lambda subscript 0 bold italic b,

    • find a displacement vector equation from F to P,

    • form an equation by making the scalar product of this displacement vector and direction vector of the line equal to zero,

    • find the value of lambda subscript 0by solving the equation,

    • substitute the value of lambda subscript 0 into the displacement vector and find the magnitude.

  • True or False?

    If a line passes through the point A and has direction vector bold italic b, then the shortest distance from the line to the point P is fraction numerator open vertical bar stack A P with rightwards arrow on top cross times bold italic b close vertical bar blank over denominator open vertical bar bold italic b close vertical bar end fraction.

    True.

    If a line passes through the point A and has direction vector bold italic b, then the shortest distance from the line to the point P is fraction numerator open vertical bar stack A P with rightwards arrow on top cross times bold italic b close vertical bar blank over denominator open vertical bar bold italic b close vertical bar end fraction.

    This formula is not given in the formula booklet.

  • How do you find the shortest distance between two parallel lines?

    To find the shortest distance between two parallel lines:

    • pick a point on one of the lines,

    • find the shortest distance between this point and the other line.

  • How do you find the shortest distance between to skew lines bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1 and bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2?

    To find the shortest distance between to skew lines bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1 and bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2, you:

    • find an expression for the displacement between a general point on each line, open parentheses bold italic a subscript 1 plus lambda bold italic b subscript 1 close parentheses minus open parentheses bold italic a subscript 2 plus mu bold italic b subscript 2 close parentheses,

    • find the vector product of the two direction vectors, bold italic b subscript 1 cross times bold italic b subscript 2,

    • multiply the vector product by a constant k and set it equal to the displacement vector,

    • solve the simultaneous equations to find the value of k,

    • the shortest distance is open vertical bar k close vertical bar open vertical bar bold italic b subscript 1 cross times bold italic b subscript 2 close vertical bar.