Nucleophilic Substitution in Halogenoalkanes (HL) (DP IB Chemistry)
Revision Note
Nucleophilic Substitution in Halogenoalkanes
In nucleophilic substitution reactions involving halogenoalkanes, the halogen atom is replaced by a nucleophile
The strength of any nucleophile depends on its ability to make its lone pair of electrons available for reaction
The hydroxide ion, OH-, is a stronger nucleophile than water because it has a full negative charge
This means that it has a readily available lone pair of electrons
A water molecule only has partial charges, δ+ and δ-
This means that its lone pair of electrons is less available than the hydroxide ions
The lone pairs of electrons in a water molecule are still available to react
Lewis diagram of OH– and H2O
Lewis formulae of the hydroxide ion and water molecule - illustrating the lone pairs of electrons and charges within their structures
Examiner Tips and Tricks
In general:
A negatively charged ion will be a stronger nucleophile than a neutral molecule
A conjugate base will be a stronger nucleophile than its corresponding conjugate acid
e.g. the hydroxide ion is a stronger nucleophile than water
Nucleophilic substitution reactions can occur in two different ways (known as SN2 and SN1 reactions) depending on the structure of the halogenoalkane involved
SN1 reactions
In tertiary halogenoalkanes, the carbon that is attached to the halogen is also bonded to three alkyl groups
These halogenoalkanes undergo nucleophilic substitution by an SN1 mechanism
‘S’ stands for ‘substitution’
‘N’ stands for ‘nucleophilic’
‘1’ means that the rate of the reaction (which is determined by the slowest step of the reaction) depends on the concentration of only one reagent, the halogenoalkane
Meaning of SN1
'S' stands for substitution, N stands for nucleophilic and '1' shows that the rate of reaction depends upon the concentration of one reagent
The SN1 mechanism is a two-step reaction
In the first step, the C-X bond breaks heterolytically and the halogen leaves the halogenoalkane as an X- ion (this is the slow and rate-determining step)
As the rate-determining step only depends on the concentration of the halogenoalkane, the rate equation for an SN1 reaction is rate = k[halogenoalkane]
In terms of molecularity, an SN1 reaction is unimolecular
This forms a tertiary carbocation intermediate (which is a tertiary carbon atom with a positive charge)
In the second step, the tertiary carbocation is attacked by the nucleophile
This two-step process is evident in the energy profile diagram for an SN1 reaction
Reaction profile for an SN1 mechanism
The reaction profile for an SN1 mechanism is a two-step mechanism so has two curves. The connection between the first two curves represents the carbocation intermediate
For example, the nucleophilic substitution of 2-bromo-2-methylpropane by hydroxide ions to form 2-methyl-2-propanol
Example of SN1 mechanism
The mechanism of nucleophilic substitution in 2-bromo-2-methylpropane which is a tertiary halogenoalkane
Examiner Tips and Tricks
You are expected to know the difference between the heterolytic fission that features in SN1 reactions and homolytic fission in other reactions:
Heterolytic fission forms anions and cations and uses double-headed arrows to show the movement of both electrons from the covalent bond
Homolytic fission forms free radicals and uses single-headed arrows, sometimes called fish hooks, to show the movement of a single electron as the covalent bond breaks
SN2 reactions
In primary halogenoalkanes, the carbon that is attached to the halogen is bonded to one alkyl group
These halogenoalkanes undergo nucleophilic substitution by an SN2 mechanism
‘S’ stands for ‘substitution’
‘N’ stands for ‘nucleophilic’
‘2’ means that the rate of the reaction (which is determined by the slowest step of the reaction) depends on the concentration of both the halogenoalkane and the nucleophile ions
Meaning of SN2
'S' stands for substitution, N stands for nucleophilic and '2' shows that the rate of reaction depends upon the concentration of both the halogenoalkane and the nucleophile ions
The SN2 mechanism is a one-step reaction
The nucleophile donates a pair of electrons to the δ+ carbon atom of the halogenoalkane to form a new bond
As this is a one-step reaction, the rate-determining step depends on the concentrations of the halogenoalkane and nucleophile which means that the rate equation for an SN2 reaction is
rate = k[halogenoalkane][nucleophile]
In terms of molecularity, an SN2 reaction is bimolecular
At the same time, the C-X bond is breaking and the halogen (X) takes both electrons in the bond (heterolytic fission)
The halogen leaves the halogenoalkane as an X- ion
This one-step process is evident in the energy profile diagram for an SN2 reaction
Reaction profile for an SN2 mechanism
The reaction profile for an SN2 mechanism is a one-step reaction so has one curve. The transition state always involves partial bonds
For example, the nucleophilic substitution of bromoethane by hydroxide ions to form ethanol
Example of an SN2 mechanism
The SN2 mechanism of bromoethane with hydroxide causes an inversion of configuration
The bromine atom of the bromoethane molecule causes steric hindrance
This means that the hydroxide ion nucleophile can only attack from the opposite side of the C-Br bond
An attack from the same side as the bromine atom is sometimes called a frontal attack
While attack from the opposite side is sometimes called a backside or rear-side attack
As a result of this, the molecule has undergone an inversion of configuration
The common comparison for this is an umbrella turning inside out in the wind
As the C-OH bond forms, the C-Br bond breaks causing the bromine atom to leave as a bromide ion
Diagram to demonstrate inversion of configuration
Inversion of configuration - umbrella analogy
Examiner Tips and Tricks
If you are asked to explain reaction mechanisms where there is an inversion of configuration, you will be expected to:
Use partial charges, δ+ and δ-, to help explain why the nucleophile attacks and the halogen leaves
Use dotted, wedge and tapered bonds to show the change in configuration of the atoms / functional groups around the carbon that is being attacked
Draw the transition state with the nucleophile attached to the carbon with a dotted bond and the halogen still attached to the carbon, also, with a dotted bond
Be aware that the compound you draw is a transition state and not an intermediate
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