Propanone is made by a two stage process.
The second stage involves oxidation.
Propene → X → Propanone
What is the functional group of compound X?
COOH
OH
COO
C=O
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Syllabus Edition
First teaching 2014
Last exams 2024
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20.2 Synthetic Routes
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20.2 Synthetic Routes
Propanone is made by a two stage process.
The second stage involves oxidation.
Propene → X → Propanone
What is the functional group of compound X?
COOH
OH
COO
C=O
Choose your answer
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4-nitrophenol can be produced from phenol.
What is the name of the mechanism used to make 4-nitrophenol?
Nucleophilic substitution
Nucleophilic addition
Electrophilic addition
Electrophilic substitution
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4-methylpentanal can be formed by the oxidation of 4-methylpentan-1-ol.
Which reagent is used as an oxidising agent for this conversion?
NaBH4
NaOH
K2Cr2O7
LiAlH4
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Which reaction(s) can alkenes undergo?
I and II only
I and III only
II and III only
I, II and III
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Phenylamine can be formed from nitrobenzene.
What are the reagents used and the name of this reaction?
Reagents | Reaction | |
A. | Sn and conc H2SO4 | Substitution |
B. | NaOH | Addition |
C. | Conc HNO3 and conc HCl | Reduction |
D. | Sn and conc HCl | Reduction |
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The synthesis of ethyl butanoate can be carried out in three steps:
I II III
C4H9Br → C4H9OH → C3H7COOH → C3H7COOC2H5
What is the correct classification of the steps?
|
I |
II |
III |
A |
substitution |
oxidation |
condensation |
B |
addition |
substitution |
condensation |
C |
oxidation |
substitution |
condensation |
D |
substitution |
oxidation |
substitution |
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The synthesis of 2-propyl propanoate can be carried out in two steps:
I
CH3COCH3 → CH3CH(OH)CH3
II
CH3CH(OH)CH3 → C2H5COOCH(CH3)2
What are the reagents needed in I and II?
|
I |
II |
A |
potassium dichromate(VI) |
sulfuric acid, propanoic acid |
B |
sodium borohydride |
sulfuric acid, propanoic acid |
C |
sodium borohydride |
sulfuric acid, ethanoic acid |
D |
potassium dichromate(VI) |
sulfuric acid, ethanoic acid |
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The synthesis of phenylamine can be carried out in two steps:
I II
C6H6 → C6H5NO2 → C6H5NH2
What are the reaction types in I and II?
|
I |
II |
A |
oxidation |
substitution |
B |
addition |
substitution |
C |
substitution |
reduction |
D |
oxidation |
reduction |
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Which of the following reactions produces only pentan-2-ol?
Water and pent-1-ene
1-bromopentane and ethanolic NaOH
Water and pent-2-ene
2-bromopentane and ethanolic NaOH
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Which compound could be X in this two step reaction pathway?
C3H8 → X → C3H7OH
C2H5CN
C3H7Cl
C3H6Cl2
C2H5COOH
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The equation below shows the conversion of propanal to propyl ethanoate.
What are the reagents used and the reactions taking place?
Reaction 1 | Reagents 1 | Reaction 2 | |
A |
oxidation |
K2Cr2O7 and H2SO4 |
nucleophilic substitution (condensation) |
B |
reduction |
NaBH4 |
nucleophilic substitution (condensation) |
C |
reduction |
LiAlH4 |
oxidation |
D |
hydrogenation |
H2 |
addition |
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But-1-ene reacts separately with HBr and H2/ Ni to give products X and Z respectively.
What are the major products of the reactions?
X | Z | |
A. | CH2BrCH2CH2CH3 | CH3CH2CCH |
B. | CH3CH2CH2CH2OH | CH3CH2CH2CH3 |
C. | CH3CHBrCH2CH3 | CH3CH2CCH |
D. | CH3CHBrCH2CH3 | CH3CH2CH2CH3 |
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Methylbenzene can be converted into 4-methylphenylamine in a multi-step reaction.
Which order should the reagents be used to do this conversion?
1st reagent | 2nd reagent | 3rd reagent | |
A. | conc. HNO3 / conc. H2SO4 | Sn / conc. HCl | NaOH |
B. | Sn / conc. HCl | conc. HNO3 / conc. H2SO4 | NaOH |
C. | Sn / conc. HCl | NaOH | conc. HNO3 / conc. H2SO4 |
D. | NaOH | conc. HNO3 / conc. H2SO4 | Sn / conc. HCl |
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Which alcohol could not be produced by the reduction of an aldehyde or a ketone?
2,2-Dimethylbutan-1-ol
Propan-2-ol
3-Methylpentan-3-ol
2-Methylpentan-3-ol
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Which molecule(s) can be both reduced by sodium borohydride, NaBH4, and oxidised by warm acidified potassium dichromate (VI)?
I and II only
I and III only
II and III only
I, II and III
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