The Ion Product of Water
pH of water
- An equilibrium exists in water, where a few water molecules dissociate into proton and hydroxide ions
H2O (l) ⇌ H+ (aq) + OH– (aq)
- The equilibrium constant for this reaction is:
Kc x [H2O] = [H+][OH–]
- Since the concentration of the H+ and OH- ions is very small, the concentration of water is considered to be a constant
- This means that the expression can be rewritten as:
Kw = [H+] [OH-]
-
- Where Kw (ion product of water) = Kc x [H2O] = 1.00 10-14 at 298K
- The product of the two ion concentrations is always 1.00 x 10–14
- This makes it straightforward to see the relationship between the two concentrations and the nature of the solution:
[H+] & [OH–] Table
[H+] | [OH–] | Type of solution |
0.1 | 1 x 10–13 | acidic |
1 x 10–3 | 1 x 10–11 | acidic |
1 x 10–5 | 1 x 10–9 | acidic |
1 x 10–7 | 1 x 10–7 | neutral |
1 x 10–9 | 1 x 10–5 | alkaline |
1 x 10–11 | 1 x 10–3 | alkaline |
1 x 10–13 | 0.1 | alkaline |
Worked example
What is the pH of a solution of potassium hydroxide, KOH (aq) of concentration 1.0 × 10−3 mol dm−3 ?
Kw = 1.0 × 10−14 at 298 K
A. 3
B. 4
C. 10
D. 11
Answer:
- The correct option is D.
- Since Kw = [H+] [OH-] , rearranging gives [H+] = Kw ÷ [OH-]
- The concentration of [H+] is (1.0 × 10−14) ÷ (1.0 × 10−3) = 1.0 × 10−11 mol dm−3
- So the pH = 11
How does temperature affect the ion product of water, Kw?
- The ionisation of water is an endothermic process
2H2O (l) ⇌ H3O+ (aq) + OH- (aq)
- In accordance with Le Châtelier's principle, an increase in temperature will result in the forward reaction being favoured
- This causes an increase in the concentration of the hydrogen and hydroxide ions
- This leads to the magnitude of Kw increasing
- Therefore, the pH will decrease
- Increasing the temperature decreases the pH of water (becomes more acidic)
- Decreasing the temperature increases the pH of water (becomes more basic)
Graph to show how Kw changes with temperature
As temperature increases, Kw increases so pH decreases