Combustion Reactions (DP IB Chemistry)
Revision Note
Combustion Reactions
Combustion is a relatively fast, thermochemical reaction that requires:
Fuel
These can include reactive metals, non-metals and organic compounds such as hydrocarbons and alcohols
Oxygen
This reaction with oxygen means that combustion can be categorised as oxidation
There are other reactions with oxygen that are oxidation but not combustion, e.g. the rusting of iron
A source of ignition / trigger
This does not automatically mean that a spark or flame is required
It can include the build up of heat in a volatile liquid or exposure to high levels of oxygen in certain types of coal, for example
It is more commonly referred to as burning
Combustion is accompanied by the generation of heat and light, in the form of flame
The heat released from combustion means that the reaction is exothermic
The two types of combustion to consider are:
Complete combustion
Incomplete combustion
Combustion of metals
All metals can oxidise, but not all metals can combust
Some metals will only combust if they have a high surface area, e.g. they are finely divided as filings or a powder
Sparklers demonstrate the combustion of iron
Photo by Jez Timms on Unsplash
Sparklers are coated with iron powder which gives the characteristic sparks when it undergoes combustion
Less reactive metals such as copper don't combust
Copper does not combust because no flame is formed when it is directly heated in air
However, it does oxidise as the surface of the copper metal turns black as copper oxide is formed
More reactive metals such as those in the s-block will combust in air
The s-block metals form ionic oxides when they undergo combustion
The ionic oxides of these metals are basic, i.e. they will react with water to form solutions with a pH > 7
The standard example of a metal that combusts in air is magnesium, which burns with a bright white flame:
magnesium + oxygen → magnesium oxide
2Mg (s) + O2 (g) → 2MgO (s)
So, the general word equation for the combustion of suitable metals is:
metal + oxygen → metal oxide
Examiner Tips and Tricks
Careful: When some metals combust, they do not form the typical oxides:
Sodium forms sodium peroxide, Na2O2
Iron forms iron(II, III) oxide, Fe3O4
Since this knowledge is beyond the scope of the specification, you should achieve the marks in an exam for forming the typical oxides, e.g.
Sodium oxide, Na2O
Iron(III) oxide, Fe2O3
Combustion of non-metals
Several non-metals show a variety of oxidation states in the different oxides that they form during combustion
p-block non-metals generally form covalent oxides when they undergo combustion
These covalent oxides are acidic, i.e. they will react with water to form solutions with a pH < 7
A common example of a non-metal that combusts in air is sulfur, which burns with a blue flame
sulfur + oxygen → sulfur dioxide
S (s) + O2 (g) → SO2 (g)
So, the general word equation for the combustion of non-metals is:
non-metal + oxygen → non-metal oxide
Worked Example
Combustion of metals and non-metals
Potassium produces a lilac flame when it burns in air to form potassium oxide, K2O. Write a chemical equation for this reaction.
Write a chemical equation for the combustion of white phosphorous, P4, to form phosphorous(V) oxide, P4O10.
Answer 1:
The chemical symbol for potassium is K
The chemical formula for oxygen is O2
The chemical formula of potassium oxide is given as K2O
So, the unbalanced chemical equation is:
K + O2 → K2O
Doubling the K2O balances the oxygen atoms
Consequently, four potassium atoms are required on the reactant side to balance the equation
The balanced chemical equation is:
4K + O2 → 2K2O
Answer 2:
The chemical formula for white phosphorous is given as P4
The chemical formula for oxygen is O2
The chemical formula of phosphorus(V) oxide is given as P4O10
So, the unbalanced chemical equation is:
P4 + O2 → P4O10
The phosphorous atoms are balanced on both sides of the equation
There are 10 atoms of oxygen on the products side of the equation, which means that 5O2 are required on the reactant side to balance the equation
The balanced chemical equation is:
P4 + 5O2 → P4O10
Complete combustion of organic compounds
Many organic compounds are used as fuels because they release relatively large amounts of energy when combusted
They do not usually undergo spontaneous combustion because their combustion reactions have a high activation energy
This makes fuels easy and safe to transport and store
For more information about activation energy, see our revision note on activation energy
The organic compounds that are commonly used as fuels include:
Hydrocarbons - particularly alkanes
Alcohols
What is complete combustion?
When fuels such as hydrocarbons and alcohols are burnt in excess (plenty of) oxygen, complete combustion takes place
This means that all carbon and hydrogen will be oxidised
Therefore, the products of complete combustion are carbon dioxide and water
The word equation for complete combustion is:
fuel + oxygen → carbon dioxide + water
Combustion of hydrocarbons
For example, the word and chemical equations for the complete combustion of methane are:
Complete combustion of methane word equation:
methane + oxygen → carbon dioxide + water
Complete combustion of methane chemical equation:
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)
Combustion of Alcohols
Alcohols react with oxygen in the air when ignited and undergo complete combustion to form carbon dioxide and water
alcohol + oxygen → carbon dioxide + water
For example, the word and chemical equations for the complete combustion of ethanol are:
Complete combustion of ethanol word equation:
ethanol + oxygen → carbon dioxide + water
Complete combustion of ethanol chemical equation:
C2H5OH (l) + 3O2 (g) → 2CO2 (g) + 3H2O (l)
Examiner Tips and Tricks
Be careful when balancing equations for the combustion of alcohol, as students often forget to count the oxygen in the alcohol
Lower alcohols burn with an almost invisible flame and make good fuels
Ethanol can be produced sustainably as a fuel by the fermentation of sugars
However, the energy density (the amount of energy in kJ per kg of fuel) is lower than gasoline so cars that run on ethanol must either have a larger fuel tank or fill up more often
Blending ethanol with gasoline or diesel increases the energy density and makes it safer in case of fires as it is easier to see the flames compared to pure ethanol burning
However, there are socio-economic concerns about using large quantities of farmland to produce crops for fermentation, which could be better used for food production
Worked Example
Complete combustion of hydrocarbons and alcohols
Write chemical equations for the complete combustion of:
Propane, C3H8
Propan-1-ol, C3H7OH
Answer 1:
Since this is complete combustion, the products will be carbon dioxide and water
So, the unbalanced chemical equation is:
C3H8 + O2 → CO2 + H2O
The 3 carbons in propane will form 3CO2
The 8 hydrogens in propane will form 4H2O
This updates the unbalanced chemical equation to:
C3H8 + O2 → 3CO2 + 4H2O
There are now 10 oxygens in total on the product's side, which means that 5O2 are required on the reactant side to balance the equation
The balanced chemical equation is:
C3H8 + 5O2 → 3CO2 + 4H2O
Answer 2:
Since this is complete combustion, the products will be carbon dioxide and water
So, the unbalanced chemical equation is:
C3H7OH + O2 → CO2 + H2O
The 3 carbons in propan-1-ol will form 3CO2
The 8 hydrogens in propan-1-ol will form 4H2O
This updates the unbalanced chemical equation to:
C3H7OH + O2 → 3CO2 + 4H2O
There are now 10 oxygens in total on the product's side AND one oxygen on the reactants side
This means that 4½O2 are required on the reactant side to balance the equation
The balanced chemical equation is:
C3H7OH + 4½O2 → 3CO2 + 4H2O
OR
2C3H7OH + 9O2 → 6CO2 + 8H2O, giving whole number coefficients
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