The Ion Product of Water (DP IB Chemistry)
Revision Note
The Ion Product of Water
pH of water
An equilibrium exists in water, where a few water molecules dissociate into proton and hydroxide ions
H2O (l) ⇌ H+ (aq) + OH– (aq)
The equilibrium constant for this reaction is:
Kc x [H2O] = [H+][OH–]
Since the concentration of the H+ and OH- ions is very small, the concentration of water is considered to be a constant
This means that the expression can be rewritten as:
Kw = [H+] [OH-]
Where Kw (ion product of water) = Kc x [H2O] = 1.00 10-14 at 298K
The product of the two ion concentrations is always 1.00 x 10–14
This makes it straightforward to see the relationship between the two concentrations and the nature of the solution:
[H+] & [OH–] Table
[H+] | [OH–] | Type of solution |
---|---|---|
0.1 | 1 x 10–13 | acidic |
1 x 10–3 | 1 x 10–11 | acidic |
1 x 10–5 | 1 x 10–9 | acidic |
1 x 10–7 | 1 x 10–7 | neutral |
1 x 10–9 | 1 x 10–5 | alkaline |
1 x 10–11 | 1 x 10–3 | alkaline |
1 x 10–13 | 0.1 | alkaline |
Worked Example
What is the pH of a solution of potassium hydroxide, KOH (aq) of concentration 1.0 × 10−3 mol dm−3 ?
Kw = 1.0 × 10−14 at 298 K
A. 3
B. 4
C. 10
D. 11
Answer:
The correct option is D.
Since Kw = [H+] [OH-] , rearranging gives [H+] = Kw ÷ [OH-]
The concentration of [H+] is (1.0 × 10−14) ÷ (1.0 × 10−3) = 1.0 × 10−11 mol dm−3
So the pH = 11
How does temperature affect the ion product of water, Kw?
The ionisation of water is an endothermic process
2H2O (l) ⇌ H3O+ (aq) + OH- (aq)
In accordance with Le Châtelier's principle, an increase in temperature will result in the forward reaction being favoured
This causes an increase in the concentration of the hydrogen and hydroxide ions
This leads to the magnitude of Kw increasing
Therefore, the pH will decrease
Increasing the temperature decreases the pH of water (becomes more acidic)
Decreasing the temperature increases the pH of water (becomes more basic)
Graph to show how Kw changes with temperature
As temperature increases, Kw increases so pH decreases
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