The Equilibrium Law (DP IB Chemistry)
Revision Note
The Equilibrium Law
Equilibrium law explains how the equilibrium constant, K, can be found from the stoichiometry of the reaction
The equilibrium constant equation
The equilibrium constant expression is an expression that links the equilibrium constant, K, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
So, for a given reaction:
aA + bB ⇌ cC + dD
The corresponding equilibrium constant expression is written as:
Where:
[A] and [B] = equilibrium reactant concentrations (mol dm-3)
[C] and [D] = equilibrium product concentrations (mol dm-3)
a, b, c and d = number of moles of corresponding reactants and products
Solids are ignored in equilibrium constant expressions
The equilibrium constant, K, of a reaction is specific to a given equation
Worked Example
Deduce the equilibrium constant expression for the following reactions
Ag+ (aq) + Fe2+ (aq) ⇌ Ag (s) + Fe3+ (aq)
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
2SO2 (g) + O2 (g) ⇌ 2SO3 (g)
Answer 1:
[Ag (s)] is not included in the equilibrium constant expression as it is a solid
Answer 2:
Answer 3:
Examiner Tips and Tricks
You must use square brackets in equilibrium constant expressions as they have a specific meaning, representing concentrations
In an exam answer, you would lose the mark if you used round brackets.
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