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Born-Haber Cycle Calculations (HL) (HL IB Chemistry)

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Alexandra

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Alexandra

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Born-Haber Cycle Calculations

  • Once a Born-Haber cycle has been constructed, it is possible to calculate the lattice enthalpyHlat) by applying Hess’s law and rearranging:

ΔHf = ΔHat + ΔHat + IE + EA - ΔHlat

  • If we simplify this into three terms, this makes the equation easier to see:
    • ΔHlat
    • ΔHf
    • ΔH1 (the sum of all of the various enthalpy changes necessary to convert the elements in their standard states to gaseous ions)

  • The simplified equation becomes:

ΔHf = ΔH1 - ΔHlat

  • So, if we rearrange to calculate the lattice enthalpy, the equation becomes

ΔHlat = ΔHf + ΔH1

  • When calculating the ΔHlat, all other necessary values will be given in the question
  • A Born-Haber cycle could be used to calculate any stage in the cycle
    • For example, you could be given the lattice enthalpy and asked to calculate the enthalpy change of formation of the ionic compound
    • The principle would be exactly the same
    • Work out the direct and indirect route of the cycle (the stage that you are being asked to calculate will always be the direct route)
    • Write out the equation in terms of enthalpy changes and rearrange if necessary to calculate the required value

  • Remember: sometimes a value may need to be doubled or halved, depending on the ionic solid involved
    • For example, with MgCl2 the value for the first electron affinity of chlorine would need to be doubled in the calculation, because there are two moles of chlorine atoms
    • Therefore, you are adding 2 moles of electrons to 2 moles of chlorine atoms, to form 2 moles of chloride ions, i.e. 2Cl-

Worked example

Calculating the lattice enthalpy of KCl

Given the data below, calculate the ΔHlat of potassium chloride (KCl).

  ΔHat  (kJmol-1)
IE / EA (kJmol-1)
K +90 +418
Cl +122 -349
ΔHf  (kJmol-1)
KCl -437

Answer:

  • Step 1: Construct the Born-Haber cycle

born haber cycles KCl

  • Step 2: Applying Hess’ law, the lattice enthalpy of KCl is:

ΔHlat = -ΔHf + ΔH1

ΔHlat = -ΔHf + [(ΔHat K) + (ΔHat Cl) + (IE1 K) + (EA1 Cl)]

  • Step 3: Substitute in the numbers:

ΔHlat = -(-437) + [(+90) + (+122) + (+418) + (-349)] = 718 kJ mol-1

Worked example

Calculating the lattice enthalpy of MgO

Given the data below, calculate the of ΔHlat magnesium oxide of magnesium oxide (MgO)

  ΔHat (kJmol-1)
IE1 / EA1(kJmol-1) IE1 / EA1(kJmol-1)
Mg +148 +736 +1450
O +248 -142 +770
ΔHf  (kJmol-1)
MgO -602

Answer:

  • Step 1: Construct the Born-Haber cycle

born haber cycles

  • Step 2: Applying Hess’ law, the lattice enthalpy of MgO is:

ΔHlat = -ΔHf + ΔH1

ΔHlat = -ΔHf + [(ΔHat Mg) + (ΔHat O) + (IE1 Mg) + (IE2 Mg) + (EA1 O) + (EA2 O)]

  • Step 3: Substitute in the numbers:

ΔHlat = -(-602) + [(+148) + (+248) + (+736) + (+1450) + (-142) + (+770)]

= 3812 kJ mol-1

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Alexandra

Author: Alexandra

Expertise: Chemistry

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.