Syllabus Edition

First teaching 2023

First exams 2025

|

Electrolysis of Aqueous Solutions (HL) (HL IB Chemistry)

Revision Note

Philippa Platt

Last updated

Electrolysis of Aqueous Solutions

  • We have seen previously how simple binary compounds can be electrolysed when molten and the products of electrolysis can be predicted using our knowledge of the ions present
  • At the cathode, positive metals ions (cations) are discharged resulting in metals being deposited
  • The cations are reduced by the electrons coming from the cathode:

Pb2+(l) + 2e-  → Pb (l)

  • Meanwhile, at the anode, anions are discharged by oxidation:

2Br- (l) → Br2 (g) + 2e-

  • However, when aqueous solutions of ionic compounds are electrolysed the products are a little more complicated to predict as there are additional ions present from the water
  • Water can be oxidised to oxygen or reduced to hydrogen:
    • Oxidation reaction:

2H2O (l)  → 4H(aq) + O2 (g) + 4e

    • Reduction reaction:

2H2O (l) + 2e-→ H(g) + 2OH- (aq) 

  • At the cathode, either the metal ion M+ or water can be reduced
  • At the anode, either the anion A- or water can be oxidized
  • Which species is discharged depends on three things:
    • The relative values of Eθ
    • The concentration of the ions present
    • The identity of the electrode

Products of specified electrolytes

  • The electrolysis of water, sodium chloride solution and copper sulfate solutions is as follows:

Table showing the electrolysis products of aqueous solutions

Substance used Cathode product Anode product
Water Hydrogen Oxygen
Sodium chloride Hydrogen Oxygen / chlorine
Copper sulfate solution with inert electrodes Copper Oxygen
Copper sulfate with copper electrodes Copper -

The influence of relative values of Eθ

  • The electrolysis of water is very slow as there are few ions present, so a little acid or base can be added to increase the number of ions present and speed up the electrolysis
  • Whether acid or base is added the products are the same, but the electrode reactions are slightly different
  • Using dilute sulfuric acid as the electrolyte, the cathode reactions could be

2H2O (l) + 2e- →  H(g) + 2OH- (aq)              Eθ = -0.83V

2H+ (aq) + 2e- →  H2 (g)                               Eθ =  0.00 V

  • The Eθ is smaller for the hydrogen ion so it is preferentially reduced and H2 (g) will be discharged
  • At the anode, although sulfate ions are present in the solution, only water can be oxidised
  • This is because the sulfate ion, SO42-, contains sulfur in its maximum oxidation state (+6) so it cannot be further oxidised
  • The oxidation of water produces oxygen gas:

2H2O (l)   →  4H+ (aq) +  O2 (g) +  4e-          Eθ = -1.23 V

  • If the water is made basic by the addition of dilute sodium hydroxide solution, the cathode reactions could be:

Na+ (aq) + e- → Na (s)                                Eθ =  -2.71 V

2H2O (l) + 2e- → H2 (g) +  2OH- (aq)         Eθ = -0.83 V

  • The Eθ is smaller for water than the sodium ion, so water is preferentially reduced and H2 (g) will be discharged
  • At the anode, either the hydroxide ion or water can be oxidised:

4OH- (aq)  →  2H2O (l) + O2 (g)  +  4e-                    Eθ = -0.40 V

2H2O (l)   →  4H+ (aq) + O2 (g) +  4e-                          Eθ = -1.23 V

  • Based on these values the hydroxide ion is preferentially oxidized and O2 (g) will be discharged
  • The overall reaction whether in acid or alkali conditions is:

2H2O (l)  →  2H2 (g)   + O2 (g)

The influence of concentration of the ions

  • The electrolysis of sodium chloride solution provides an illustration of the influence of concentration on the products discharged
  • As before, we would expect hydrogen ion to be preferentially discharged at the cathode before the sodium ion:

2H+ (aq) + 2e- → H2 (g)                 Eθ =  0.00 V

  • However, at the anode, the relative proximity of the Eθ values allows the possibility of both reactions occurring:

           2Cl(aq) → Cl2 (g)  + 2e-              Eθ = -1.36 V

    2H2O (l) →  4H+ (aq)  +  O2 (g) +  4e-     Eθ = -1.23 V

  • In fact, when concentration of the sodium chloride increases to more than 25% the Cl- becomes preferentially discharged and chlorine gas is the main product of the reaction at the anode
  • The overall reaction equation is:

2NaCl (aq)  + 2H2O (l) →    2NaOH (aq) +  H2 (g)  +  Cl2 (g)

Influence of the electrodes

  • The products of electrolysis are influenced by the identity of the electrodes
  • Electrodes that take part in the redox processes are known as active electrodes and inert electrodes such as platinum and carbon are called passive electrodes
  • The electrolysis of copper sulfate solution, CuSO4 (aq),  is an example of where active and passive electrodes determine the products

Passive electrodes

  • At the cathode, the possible reactions that could take place are:

      Cu2+ (aq) + 2e- → Cu (s)                         Eθ =  +0.34 V

  2H2O (l) + 2e- → H2 (g) +  4OH- (aq)        Eθ = -0.83 V

  • Copper ions are preferentially reduced, so copper metal is deposited on the cathode
  • At the anode, water is oxidised, so oxygen gas is produced (the sulfate ion cannot be oxidised):

    2H2O (l) →  4H+ (aq)  +  O2 (g) +  4e-     Eθ = -1.23 V

  • The overall equation for the reaction is:

2CuSO4 (aq) + 2H2O (l) → 2Cu (s) + O2 (g) + 2SO42- (aq) 4H+ (aq) 

OR

2CuSO4 (aq) + 2H2O (l) → 2Cu (s) + O2 (g) + 2H2SO4 (aq)

Active electrodes

  • At the cathode, the reaction is the same as with inert electrodes:

Cu2+ (aq) + 2e- → Cu (s)                         Eθ =  +0.34 V

  • However, at the anode, the copper electrode is oxidised and dissolves to form copper ions

Cu (s)  Cu2+ (aq) + 2e-                      Eθ =  -0.34 V

  • This reaction is used to purify copper, needed to produce a very high grade of copper for use in electrical wires
  • The anode is made of impure copper and the cathode is made of pure copper
  • The impurities from the anode fall to the bottom of the cell

Diagram to show the purification of copper via electrolysis

Diagram showing the electrolytic purification of copper

The purification of copper by electrolysis

  • The anode slowly dissolves away and the cathode builds up pure copper
  • The impurities form a slime under the anode which is actually quite valuable as it often contains significant quantities of precious metals like silver

You've read 0 of your 5 free revision notes this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Philippa Platt

Author: Philippa Platt

Expertise: Chemistry

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener.