The Genetic Code (DP IB Biology)
Revision Note
Features of the Genetic Code
The sequence of DNA nucleotide bases found within a gene is determined by a triplet (three-letter) code
Each sequence of three bases (i.e. each triplet of bases) in a gene codes for one amino acid
These triplets code for different amino acids – there are 20 different amino acids that cells use to make up different proteins
For example:
CAG codes for the amino acid valine
TTC codes for the amino acid lysine
GAC codes for the amino acid leucine
CCG codes for the amino acid glycine
Some of these triplets of bases code for start (TAC – methionine) and stop signals
These start and stop signals tell the cell where individual genes start and stop
As a result, the cell reads the DNA correctly and produces the correct sequences of amino acids (and therefore the correct protein molecules) that it requires to function properly
The genetic code is non-overlapping
Each base is only read once in which codon it is part of
There are four bases, so there are 64 different codons (triplets) possible (43 = 64), yet there are only 20 amino acids that commonly occur in biological proteins
This is why the code is said to be degenerate: multiple codons can code for the same amino acids
The degenerate nature of the genetic code can limit the effect of mutations
The genetic code is also universal, meaning that almost every organism uses the same code (there are a few rare and minor exceptions)
The same triplet codes code for the same amino acids in all living things (meaning that genetic information is transferable between species)
The universal nature of the genetic code is why genetic engineering (the transfer of genes from one species to another) is possible
Deducing Amino Acid Sequences
By observing the genetic code in the mRNA it is possible to determine the sequence of amino acids that are coded for in the polypeptide
mRNA codons and amino acids table
Worked Example
Use the rules of base-pairing and the mRNA Codons and Amino Acids Table (above) to deduce the amino acid sequence coded for by the following DNA coding strand sequence TTC GAG CAT TAC GCC
Answer:
Step 1: Work out the template sequence using A-T and C-G base pairing rules
AAG CTC GTA ATG CGG
Step 2: Work out the mRNA codons, complementary to the template strand
UUC GAG CAU UAC GCC
Step 3: Use the mRNA Codons and Amino Acids Table (above) to work out the first amino acid
First base in codon = U, second base = U, third base = C
So we're looking in the top-left box of the table; this amino acid is Phe
Step 4: Repeat for the remaining 4 codons
GAG = Glu
CAU = His
UAC = Tyr
GCC = Ala
The final sequence of amino acids is Phe-Glu-His-Tyr-Ala
Elongation of the Polypeptide Chain
During translation two tRNA molecules fit onto the ribosome at any one time, bringing the amino acid they are each carrying side by side
The ribosome will move along the mRNA molecule, one codon at a time
A peptide bond is then formed (by condensation) between the two amino acids
The formation of a peptide bond between amino acids is an anabolic reaction
It requires energy, in the form of ATP
The ATP needed for translation is provided by the mitochondria within the cell
This process continues until a ‘stop’ codon on the mRNA molecule is reached – this acts as a signal for translation to stop and at this point the amino acid chain coded for by the mRNA molecule is complete
This amino acid chain is then released from the ribosome and forms the final polypeptide
The process of translation diagram
The translation stage of protein synthesis – an amino acid chain is formed
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