The Sign Test (AQA AS Psychology)
Revision Note
Written by: Claire Neeson
Reviewed by: Lucy Vinson
When to use the sign test
The sign test is a method used in interferential statistics to determine whether or not an observed result (from a statistical test) is significant
It is a non-parametric test which means that there is no assumption that the data will follow a normal distribution
It is known as the Sign Test as it is based on the number of plus or minus signs present in the data after the calculations have taken place
The criteria which determine the use of the Sign Test are
If the research investigates a difference
An experiment rather than a correlation (which investigates the relationship between variables)
Each participant experiences both conditions of the IV
Data in categories (e.g. 'Exercised for 15 minutes/Did no exercise'
Whether the hypothesis is directional or non-directional
The type of hypothesis used will determine which critical value from the statistical tables to apply to the data
Calculation of the sign test
Here is an example of how the Sign Test would be calculated using the results from a (fictional) study
A researcher hypothesises that exercising before taking a test would improve concentration
These are the results showing the test scores per participant
Participant | Concentration with exercise before test | Concentration with no exercise | Difference | Sign of difference |
---|---|---|---|---|
1 | 15 | 9 |
| |
2 | 7 | 12 |
| |
3 | 18 | 3 |
| |
4 | 5 | 5 |
| |
5 | 11 | 12 |
| |
6 | 9 | 17 |
| |
7 | 13 | 8 |
| |
8 | 6 | 16 |
| |
9 | 10 | 14 |
|
Step 1:
Subtract the ‘exercise before test' score from the ‘no exercise' score and add the answer to the ‘difference’ column e.g.
15 – 9 = 6
7 - 12 = -5
Step 2:
If the score after subtraction is positive, place a + before the number in the ‘difference’ column
If the score after subtraction is negative, place a - before the number in the 'difference' column
Note that scores of 0 difference do not have a positive or negative sign attached to them
Participant | Concentration with exercise before test | Concentration with no exercise | Difference | Sign of difference |
---|---|---|---|---|
1 | 15 | 9 | +6 |
|
2 | 7 | 12 | -5 |
|
3 | 18 | 3 | +15 |
|
4 | 5 | 5 | 0 |
|
5 | 11 | 12 | -1 |
|
6 | 9 | 17 | -8 |
|
7 | 13 | 8 | +5 |
|
8 | 6 | 16 | -10 |
|
9 | 10 | 14 | -4 |
|
Step 3:
Count the number of + and – signs
Number of + signs = 3
Number of – signs = 5
Whichever number is lower becomes the observed value (S) for the test
Observed value of S = 3
Participant | Concentration with exercise before test | Concentration with no exercise | Difference | Sign of difference |
---|---|---|---|---|
1 | 15 | 9 | +6 | + |
2 | 7 | 12 | -5 | - |
3 | 18 | 3 | +15 | + |
4 | 5 | 5 | 0 |
|
5 | 11 | 12 | -1 | - |
6 | 9 | 17 | -8 | - |
7 | 13 | 8 | +5 | + |
8 | 6 | 16 | -10 | - |
9 | 10 | 14 | -4 | - |
Step 4:
Identify the critical value using a statistical table
Look at the values which relate to whether the test is directional (one-tailed) or non-directional (two-tailed)
Select the correct level of significance at p = 0.05
Step 5:
Use N to find your critical value (N refers to the number of participants in your data set)
If you have one participant who has scored the same in both conditions (i.e. difference is 0) you need to remove them from the data (this is true for participant number 4 in the above data set)
Therefore N = 8 for the above data set as participant 4 experienced no change
Using the N column (on the critical values table) find 8
Find the 0.05 critical value (according to whether it was a one-tailed or a two-tailed test)
Step 6:
Consult your observed value (S) and ask, is the critical value at 0.05 more or less than the S value?
In this example let's say a directional (one-tailed) test was used in which case with a value of N = 8, the critical value is 1
As S = 3 is more than the critical value of 1, the researcher would have to accept the null hypothesis, there is no difference that exercising before taking a test would improve concentration
If the observed value had been equal to or less than the critical value, the researcher would be able to reject the null hypothesis and claim that there was a significant difference that exercising before taking a test would significantly improve concentration
Critical values table for The Sign Test
Level of significance for a one-tailed (directional) test: |
---|
| 0.05 | 0.025 | 0.01 | 0.005 |
Level of significance for a two-tailed (non-directional) test: |
---|
| 0.10 | 0.05 | 0.025 | 0.005 |
N |
|
|
|
|
---|---|---|---|---|
5 | 0 | - | - | - |
6 | 0 | 0 | - | - |
7 | 0 | 0 | 0 | - |
8 | 1 | 0 | 0 | 0 |
9 | 1 | 1 | 0 | 0 |
10 | 1 | 1 | 0 | 0 |
11 | 2 | 1 | 1 | 0 |
Accepting or rejecting the null hypothesis
If the calculated S value is more than the critical value, the researcher would have to accept the null hypothesis
If the calculated S value is equal to or less than the critical value, the researcher would be able to reject the null hypothesis and accept their alternative hypothesis
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