Polarisation (CIE AS Physics)

Exam Questions

1 hour21 questions
1a
Sme Calculator
2 marks

Transverse waves such as light can be polarised. 

Define the term polarised.

1b
Sme Calculator
3 marks

Explain why longitudinal waves cannot be polarised by a polarising filter.

1c
Sme Calculator
2 marks

Fig. 1.1 shows unpolarised light directed towards a polarising filter A.

3-1-s-q--q2c-easy-aqa-a-level-physics

Fig. 1.1

Polarising filter B is placed directly after A and is identical except rotated by 90º. 

State and explain what happens to the light after it has passed through polarising filter B.

1d
Sme Calculator
1 mark

In Fig. 1.1 the incident light has an intensity of I subscript 0.

State the intensity of the polarised light exiting polarising filter A.

Did this page help you?

2a
Sme Calculator
2 marks

State two ways that light can be polarised other than by a polarising filter. 

2b
Sme Calculator
2 marks

Fig. 1.1 shows unpolarised light of intensity 64 W m−2 incident on polariser A.

7-5-e-q2b-sq-cie-ial-physics

Fig. 1.1

Determine the intensity of the light leaving the analyser B.

2c
Sme Calculator
3 marks

Fig. 1.2 shows that analyser B has been rotated by 35° with respect to the polariser A. 

7-5-e-q2c-sq-cie-ial-physics

Fig. 1.2

Determine the intensity of the light leaving analyser B.

2d
Sme Calculator
2 marks

Fig. 1.3 shows that analyser B has been rotated to 90° with respect to polariser A. 

7-5-e-q2d-sq-cie-ial-physics

Fig. 1.3

Show that there is no light passing through analyser B.

Did this page help you?

1a
Sme Calculator
1 mark

A beam of vertically polarised monochromatic light is incident on a polarising filter, as shown in Fig. 5.1.

q5-paper-2-specimen-2022-cie-ial-physics

Fig. 5.1

The transmission axis of the filter is initially vertical and the transmitted light beam has the same intensity as the incident light beam.

The filter may be rotated about the direction of the light beam to change the angle of the transmission axis against the vertical.

State one angle of the transmission axis to the vertical that results in no transmitted light beam.



angle = ................................... ° 

1b
Sme Calculator
4 marks

The filter is now positioned with its transmission axis at angle θ to the vertical, as shown in Fig. 5.2.

q5b-paper-2-specimen-2022-cie-ial-physics

Fig. 5.2

The ratio  fraction numerator intensity space of space transmitted space light over denominator space intensity space of space incident space light end fraction  is equal to 0.75.

(i)
Calculate angle θ.



θ = ...................................... ° [2]

(ii)
Calculate the ratio 

fraction numerator amplitude space of space transmitted space light space space over denominator amplitude space of space incident space light end fraction.



ratio = ..................................... [2]

Did this page help you?

2a
Sme Calculator
3 marks

Unpolarised light is passed through a pair of polarising sunglasses as shown in Fig. 1.1.

7-2-2a-m-polarising-sunglasses

The light becomes plane polarised.

Explain the difference between unpolarised and plane polarised light.

2b
Sme Calculator
3 marks

Polarisation can be used to identify when some materials are under stress. Placing the material under stress causes the plane of polarisation of the light passing through the material to be rotated. The greater the stress, the greater the rotation of the plane of polarisation of the light.

A piece of transparent material under stress is positioned between two polarising filters. There is an angle of 90o between the planes of polarisation of the two polarising filters.

q16c-wph12-02-june-2021-edexcel-int-as-a-level-phy

Explain how this photograph can be used to identify areas of the material with different amounts of stress.

Did this page help you?

3a
Sme Calculator
2 marks

Fig. 1.1. shows two ways in which a wave can be made to travel along a slinky spring.

7-2-3a-m-oscillating-slinkies-q

Use arrows to show how points Q and R will move next as the two waves move to the right.

3b
Sme Calculator
3 marks

Use the diagram in Fig. 1.1.  

(i)
State which wave in Fig. 1.1 can be used to model an electromagnetic wave.
[1]
(ii)
Hence explain why it is important to correctly align a radio antenna in order to receive the strongest signal.
[2]

3c
Sme Calculator
2 marks

Light from a filament lamp is viewed through two polarising filters A and B as shown in Fig. 1.2.

7-2-3c-m-polarising-filters
    

The direction of plane polarisation is indicated on each filter using a double-headed arrow.

Explain why the observer cannot see light from the filament lamp.

Did this page help you?

1a
Sme Calculator
4 marks

A transverse wave passes straight through a polariser. A and B are two points on the wave a distance of 3 over 2λ apart. The displacement of the wave at the point when A passes through the polariser is at its maximum.

Sketch a possible graph to show the displacement of the wave against phase as it passes through the polariser, θ and label points A and B. 

1b
Sme Calculator
3 marks

Electromagnetic waves are transverse waves that carry energy through the vacuum of space as progressive transverse waves. 

Discuss the motion of an electromagnetic wave with reference to the appropriate fields.

1c
Sme Calculator
3 marks

Plane-polarised electromagnetic waves are incident on an aerial positioned to give a maximum response. High winds cause the aerial to rotate anti-clockwise about the plane of the incident wave until it makes an angle of 40° out of the plane of wave oscillation.

Calculate the percentage reduction in the amplitude of the signal received by the aerial following the high winds.

1d
Sme Calculator
3 marks

The intensity of incident radiation is 0.06 mW m−2. When the aerial is repaired, it is found to have a vibration amplitude of 5.4 mm.

Determine the angle at which the aerial has been set.

Did this page help you?

2a
Sme Calculator
2 marks

When electromagnetic waves are reflected from a shiny surface, such as a road sign, they often become polarised. 

Suggest how to determine experimentally if visible light reflected from a road sign is polarised.

2b
Sme Calculator
3 marks

Three polaroid filters P1, P2 and P3 are aligned as shown in Fig. 1.1. 

Unpolarised light is incident on P1 and subsequently passes through each of the three polaroid filters. P1 and P2 are fixed, with P2 at 20° to P1, but P3 can be rotated to any angle θ  to that of P1.

7-5-q2b-h-sq-cie-ial-physics

Fig. 1.1

Determine the angles of θ at which minima and maxima of emergent light intensity occur.

2c
Sme Calculator
2 marks

Table 1.1 lists different waves, whether they are polarised or unpolarised and a reason. 

State, by completing the spaces in the table whether the waves listed are polarised or unpolarised, and give a reason for your answer. 

Table 1.1

Wave

Polarised or Unpolarised

Reason

Light from the sun

 

 

Compression waves caused by an earthquake

Unpolarised

Longitudinal waves cannot be polarised

Electromagnetic waves from the sun passing through a sunglass lens

 

 

Ultra-sonic waves from an echo sounder

 

 

2d
Sme Calculator
4 marks

Electromagnetic waves, being transverse, can also be polarised.

A light source is viewed through two pieces of polarisers, P and Q, with their axes initially at straight pi over 2 radians from each other, as shown in Fig. 1.1.

7-5-q2d-h-sq-cie-ial-physics

Fig. 1.1

Using the axes below, sketch the variation of the intensity of light reaching the eye with angular displacement of Q with respect to P when polariser Q is rotated. 

3-1-s-q--q2d-image1-hard-aqa-a-level-physics

Did this page help you?