The Diffraction Grating (Cambridge (CIE) AS Physics)

Revision Note

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

The diffraction grating equation

  • A diffraction grating is a piece of optical equipment that creates a diffraction pattern when it diffracts monochromatic light into bright and dark fringes

bRavNlJQ_laser-diffraction-grating-set-up

A laser light is diffracted using a diffraction grating

  • A diffraction grating consists of a large number of very thinequally spaced parallel slits carved into a glass plate

diffraction-grating

A diffraction grating consists of many parallel equally spaced slits cut into the glass plate

  • Just like for single and double-slit diffraction the regions where constructive interference occurs are also the regions of maximum intensity

  • Their location can be calculated using the diffraction grating equation

d sin open parentheses theta close parentheses space equals space n lambda

  • Where:

    • d = spacing between adjacent slits (m)

    • θ = angular separation between the order of maxima (degrees)

    • n = order of maxima (n = 0, 1, 2, 3...)

    • λ = wavelength of light source (m)

Slit spacing

  • Diffraction gratings come in different sizes

    • The sizes are determined by the number of lines per millimetre (lines / mm) or lines per m

    • This is represented by the symbol N

  • d can be calculated from N using the equation

    • If is given in terms of lines per mm then will be in mm

    • If is given in terms of lines per m then will be in m

d space equals space 1 over N

diffraction-grating-sizes

Diffraction gratings come in different sizes according to the number of lines per mm

Angular separation

  • The angular separation of each maxima is calculated by rearranging the grating equation to make θ the subject

  • The angle θ is taken from the centre meaning the higher orders of are at greater angles

Angular separation, downloadable AS & A Level Physics revision notes

Angular separation increases as the order of maxima increases

  • The angular separation between two angles is found by subtracting the smaller angle from the larger one

  • The angular separation between the first and second maxima at n1 and nis θ2 – θ1

Orders of maxima

  • The maximum angle of diffraction with which maxima can be seen is when the beam is at right angles to the diffraction grating

    • This means θ = 90o and sin θ = 1

  • The highest order of maxima visible is therefore calculated by the equation:

n space equals space d over lambda

  • Since n is an integer number of maxima, if the value obtained is a decimal it must be rounded down to determine the highest-order visible

    • E.g If n is calculated as 2.7 then n = 2 is the highest-order visible

Worked Example

An experiment was set up to investigate light passing through a diffraction grating with a slit spacing of 1.7 µm. The fringe pattern was observed on a screen. The wavelength of the light is 550 nm.

Worked Example: Diffraction Grating, downloadable AS & A Level Physics revision notes

Calculate the angle α between the two second-order lines.

Answer:

Step 1: List the known quantities

  • Order of maxima, n = 2

  • Diffraction slit spacing, d = 1.7 µm = 1.7 × 10–6 m

  • Wavelength, λ = 550 nm = 550 × 10–9 m

Step 2: Rearrange for β and substitute in the values

d sin open parentheses theta close parentheses space equals space n lambda

sin open parentheses beta close parentheses space equals space fraction numerator n lambda over denominator d end fraction

sin open parentheses beta close parentheses space equals space fraction numerator 2 space cross times space open parentheses 550 space cross times space 10 to the power of negative 9 end exponent close parentheses space over denominator 1.7 space cross times space 10 to the power of negative 6 end exponent end fraction space equals space 0.64706

beta space equals space sin to the power of negative 1 end exponent open parentheses 0.64706 close parentheses space equals space 40.32 to the power of degree

Step 3: Calculate α

  • β is the angle from the centre to the second-order line

alpha space equals space 2 beta space equals space 2 cross times 40.32 space equals space 81 degree space open parentheses 2 space straight s. straight f close parentheses

Examiner Tips and Tricks

Take care that the angle θ is the correct angle taken from the centre and not the angle taken between two orders of maxima.

Determining the wavelength of light

Method

  • The wavelength of light can be determined by rearranging the grating equation to make the wavelength λ the subject

d sin open parentheses theta close parentheses space equals space n lambda space rightwards arrow space lambda space equals space fraction numerator d sin open parentheses theta close parentheses over denominator n end fraction

  • The value of θ, the angle to the specific order of maximum measured from the centre, can be calculated through trigonometry

  • Create a right angled triangle to determine the angle of diffraction, θ

    • The distance from the grating to the screen is marked as D

    • The distance between the centre and the order of maxima (e.g. n = 2 in the diagram below) on the screen is labelled as h, the fringe spacing

  • Measure both of these values with a ruler

  • Obtain the ratio space tan space theta space equals opposite over adjacent space equals space h over D space

Order of maxima and wavelength

Wavelength of light setup, downloadable AS & A Level Physics revision notes

The wavelength of light is calculated by the angle to the order of maximum

  • Calculate the inverse of tan to find theta space equals space tan to the power of negative 1 end exponent open parentheses h over D close parentheses

  • Substitute for θ back into the diffraction grating equation to find the value of the wavelength (with the corresponding order n)

Improving the experiment and reducing uncertainties

  • The fringe spacing can be subjective depending on its intensity on the screen. Take multiple measurements of h (between 3-8) and find the average

  • Use a Vernier scale to record h, in order to reduce percentage uncertainty

  • Reduce the uncertainty in h by measuring across all fringes and dividing by the number of fringes

  • Increase the grating to screen distance D to increase the fringe separation (although this may decrease the intensity of light reaching the screen)

  • Conduct the experiment in a darkened room, so the fringes are clearer

  • Use grating with more lines per mm, so values of h are greater to lower percentage uncertainty

You've read 0 of your 5 free revision notes this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.