Internal Resistance (Cambridge (CIE) AS Physics)
Revision Note
Internal resistance
All power supplies have some resistance between their terminals
This is called internal resistance (r)
This internal resistance causes the charge circulating to dissipate some energy from the power supply itself
This is why the cell becomes warm after a period of time
The internal resistance therefore causes a loss of voltage or energy loss in a power supply
A cell can be thought of as a source of e.m.f with an internal resistance connected in series. This is shown in the circuit diagram below:
Circuit with e.m.f
Circuit showing the e.m.f and internal resistance of a power supply
VR is the terminal potential difference
This is the voltage available in the circuit itself
Terminal p.d = I × R (Ohm’s law)
When a load resistor is connected, current flows through the cell and a potential difference develops across the internal resistance. This voltage is not available to the rest of the circuit so is called the ‘lost volts’
Vr is the lost volts
This is the voltage lost in the cell due to internal resistance, so, from conservation of energy:
Lost volts = e.m.f − terminal p.d
Lost volts = I × r (Ohm’s law)
The e.m.f is the sum of these potential differences, giving the equation below:
Where:
E = e.m.f (V)
I = current (A)
R = load resistance (Ω)
r = internal resistance (Ω)
IR is collectively known as the 'terminal potential difference'
Ir is collectively known as the 'lost volts'
Worked Example
A battery of e.m.f 7.3 V and internal resistance r of 0.3 Ω is connected in series with a resistor of resistance 9.5 Ω.
Determine:
a) The current in the circuit
b) Lost volts from the battery
Answer:
a)
Step 1: List the known quantities:
E.m.f, E = 7.3 V
Load resistance, R = 9.5 Ω
Internal resistance, r = 0.3 Ω
Step 2: Use the e.m.f equation to determine the current I
Step 3: Substitute the values
b)
Step 1: State the equation for lost volts
The lost volts are the voltage lost due to internal resistance
Step 2: Substitute the values
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