Demonstrating Interference (AQA AS Physics)

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Katie M

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Katie M

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Interference & Diffraction of a Laser

  • Lasers are the ideal piece of equipment to analyse diffraction and intensity patterns because they form light that is:
    • Coherent (have a constant phase difference and frequency)
    • Monochromatic (have the same wavelength)

laser-beam

A laser produces a beam of coherent monochromatic light

  • The diffraction pattern produced by a laser on a screen is made up of:
    • Areas of constructive interference - the bright strips or fringes
    • Areas of destructive interference - the dark fringes

 laser-diffraction-patterns

Laser diffraction patterns produced by gratings with different numbers of slits

  • Other sources of light, such as a filament bulb or a sodium lamp, are non-coherent, so they produce white light

Safety Issues with Lasers

  • Lasers produce a very high-energy beam of light
  • This intense beam can cause permanent eye damage or even blindness

Precautions

  • It's important to use lasers safely and follow the guidelines:
    • Never look directly at a laser or its reflection
    • Don’t shine the laser towards a person
    • Don't allow a laser beam to reflect from shiny surfaces into someone else's eyes
    • Wear laser safety goggles
    • Place a ‘laser on’ warning light outside the room
    • Stand behind the laser

Laser Warning, downloadable AS & A Level Physics revision notes

Placing a laser warning sign outside of the door is one precaution that can be taken when using lasers

Sound & EM Wave Interference

Using Sound Waves

  • Two-source interference can be demonstrated with two speakers emitting a coherent sound

Sound wave interference experiment, downloadable AS & A Level Physics revision notes

Sound wave interference from two speakers emitting a coherent sound

  • Sound waves are longitudinal waves made up of compressions and rarefactions
    • Constructive interference occurs when the compressions and rarefactions from each wave line up and the sound appears louder
    • Destructive interference occurs when a compression from one wave lines up with a rarefaction from the other and vice versa. The two waves cancel each other out, so zero sound is heard. 
    • This is the technology used in noise-cancelling headphones

Using Microwaves

  • Two-source interference for microwaves (and other electromagnetic waves) can be detected with a moveable microwave detector

Microwave interference experiment, downloadable AS & A Level Physics revision notes

A microwave interference experiment creates a diffraction pattern the same as that of a laser beam

  • The detector picks up a maximum amplitude or intensity in regions of constructive interference 
  • The detector picks up a minimum or zero amplitude, so no signal in regions of destructive interference 

Intensity Variation with Amplitude

  • By definition, the intensity of a wave (its power per unit area) is proportional to the energy transferred by the wave
  • The intensity of a wave at a particular point is related to the amplitude of the wave at that point
  • The energy transferred by a wave is proportional to the square of the amplitude
  • Therefore, the intensity of a wave is proportional to the square of the amplitude 

I proportional to A squared

  • Where:
    • I = intensity of the wave in W m–2
    • A = amplitude of the wave in metres (m)

Worked example

Two speakers are set up in a room and play a note of frequency 280 Hz. The waves are in phase as they leave the speakers. A student walks 3.0 m from speaker A towards speaker B. Before moving they initially hear a loud sound at speaker A but as they move from speaker A towards speaker B they hear quiet and loud sounds.

Calculate the number of quiet spots the student hears as they walk.

Speed of sound in air = 340 m s–1

Answer:

Step 1: Calculate the wavelength

wave equation: fλ 

lambda space equals space v over f space equals space 340 over 280 space equals space 1.2 space m

Step 2: Write down the condition for destructive interference

Path difference = open parentheses n space plus space 1 half close parentheses space lambda

Step 3: Calculate the smallest path difference

  • The shortest path difference occurs when = 0
    • Shortest path difference = lambda over 2 space equals space fraction numerator 1.2 over denominator 2 end fraction space equals space 0.6 space straight m
  • Therefore, the first quiet spot is at 0.6 m

Step 4: Calculate the next smallest path differences

  • When = 1:
    • Path difference = fraction numerator 3 lambda over denominator 2 end fraction space equals space fraction numerator 3 space cross times space 1.2 over denominator 2 end fraction space equals space 1.8 space straight m
  • When = 2:
    • Path difference = fraction numerator 5 lambda over denominator 2 end fraction space equals space fraction numerator 5 space cross times space 1.2 over denominator 2 end fraction space equals space 3.0 space straight m

Step 5: Write a concluding sentence

  • Therefore, in 3.0 m the student hears 3 quiet spots

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.