Energy Levels & Photon Emission (AQA AS Physics): Revision Note

Exam code: 7407

Katie M

Written by: Katie M

Reviewed by: Tim

Updated on

Line spectra & energy levels

  • Energy levels can be represented as a series of horizontal lines

    • The line at the bottom with the greatest negative energy represents the ground state

    • The lines above the ground state with decreasing energies represent excited states

    • The line at the top, usually 0 V or infinity , represents the ionisation energy

The energy levels of atomic hydrogen drawn as horizontal lines, with the ionisation level at the top. Ionisation level at 0 electronvolts and excited states 2 to 6 at −3.40, −1.51, −0.85 and −0.54 electronvolts. Downward transitions emit photons.
Diagram showing an electron energy transition from a higher level to ground state 1 at minus 13.6 electronvolts, with an emitted photon represented by a wave arrow.
A photon is emitted when an electron moves from a higher energy state to a lower energy state. The energy of the emitted photon is equal to the difference in energy between the energy levels in the transition

Line spectra

  • Line spectra occur when excited atoms emit light of certain wavelengths which correspond to different colours

  • The emitted light can be observed as a series of lines with spaces in between

    • These series of lines are called line or atomic spectra

  • Each element produces a unique set of spectral lines

  • No two elements emit the same set of spectral lines, therefore, elements can be identified by their line spectrum

  • There are two types of line spectra: emission spectra and absorption spectra

Emission spectra

  • When an electron transitions from a higher energy level to a lower energy level, this results in the emission of a photon

  • Each transition corresponds to a different wavelength of light and this corresponds to a line in the spectrum

  • The resulting emission spectrum contains a set of discrete wavelengths, represented by coloured lines on a black background

  • Each emitted photon has a wavelength which is associated with a discrete change in energy, according to the equation:

E = hf = hcλ

  • Where:

    • E = change in energy level (J)

    • h = Planck’s constant (J s)

    • f = frequency of photon (Hz)

    • c = the speed of light (m s-1)

    • λ = wavelength of the photon (m)

  • Line spectra provide evidence that electrons in atoms can only transition between discrete energy levels

Hydrogen emission spectrum showing bright lines at 410, 434, 486 and 656 nanometres. Energy-level diagram shows electrons dropping from n = 3, 4 and 5 to n = 2, emitting photons.
Emission spectrum of hydrogen gas

Absorption spectra

  • An atom can be raised to an excited state by the absorption of a photon

  • When white light passes through a cool, low pressure gas it is found that light of certain wavelengths are missing

    • This type of spectrum is called an absorption spectrum

  • An absorption spectrum consists of a continuous spectrum containing all the colours with dark lines at certain wavelengths

  • These dark lines correspond exactly to the differences in energy levels in an atom

  • When these electrons return to lower levels, the photons are emitted in all directions, rather than in the original direction of the white light

    • Therefore, some wavelengths appear to be missing

  • The wavelengths missing from an absorption spectrum are the same as their corresponding emission spectra of the same element

Hydrogen absorption spectrum: a continuous coloured band with dark lines at 410, 434, 486 and 656 nanometres. Matching photons are absorbed as electrons rise from n = 2 to n = 3, 4 and 5.
Absorption spectrum of hydrogen gas

Difference in discrete energy levels

  • The difference between two energy levels is equal to a specific photon energy

  • The energy (hf) of the photon is given by:

E = hf = E2  E1

  • Where:

    • E1 = Energy of the higher level (J)

    • E2 = Energy of the lower level (J)

    • h = Planck’s constant (J s)

    • f = Frequency of photon (Hz)

  • Using the wave equation, the wavelength of the emitted, or absorbed, radiation can be related to the energy difference 

λ = hcE2  E1

  • This equation shows that the larger the difference in energy between two levels ΔE (E2 - E1), the shorter the wavelength λ and vice versa

Worked Example

Some electron energy levels in atomic hydrogen are shown below.

Energy-level diagram with four horizontal levels (from bottom to top) at −3.4, −1.5, −0.85 and −0.54 electronvolts. An upward arrow is labelled 'energy'.

The longest wavelength produced as a result of electron transitions between two of the energy levels is 4.0 × 10–6 m.

a) Draw and mark:

  • The transition giving rise to the wavelength of 4.0 × 10–6 m with letter L [1]

  • The transition giving rise to the shortest wavelength with letter S [1]

b) Calculate the wavelength for the transition giving rise to the shortest wavelength. [3]

Answer:

Part (a)

Energy-level diagram with four horizontal levels (from bottom to top) at −3.4, −1.5, −0.85 and −0.54 electronvolts. An upward arrow is labelled 'energy'. A green downward arrow from −0.54 to −0.85 electronvolts is labelled L, and a green downward arrow from −0.54 to −3.4 electronvolts is labelled S.
  • Photon energy and wavelength are inversely proportional

    • Therefore, the largest energy change corresponds to the shortest wavelength (line S) [1 mark]

    • The smallest energy change corresponds to the longest wavelength (line L) [1 mark]

Part (b)

Step 1: Write down the equation linking the wavelength and the energy levels

λ = hcE2  E1

Step 2: Identify the energy levels giving rise to the shortest wavelength

  • This will be the energy levels which have the largest difference

    • E1 = 0.54 eV

    • E2 = 3.4 eV [1 mark]

  • We can ignore the negative sign since we just want the difference between the levels and the wavelength should be positive

Step 3: Calculate the wavelength

  • To convert from eV to J: multiply by 1.6 × 10–19

λ = (6.63 × 1034) × (3 × 108)(3.4  0.54) × (1.6 × 1019) [1 mark]

λ = 4.347 × 107 m = 435 nm [1 mark]

Examiner Tips and Tricks

It doesn't matter which energy level you assign as E1 or E2, you just need to know the difference between the energy of the two energy levels. 

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.