Further Forces & Newton's Laws (CIE AS Maths: Mechanics)

Exam Questions

4 hours37 questions
1a
Sme Calculator
2 marks

Use trigonometry (SOHCAHTOA) to resolve each of the following forces into its horizontal and vertical components.

3-3-q1-e-a-level-maths-mechanics

1b
Sme Calculator
2 marks

3-3-q1-b-e-a-level-maths-mechanics

Did this page help you?

2a
Sme Calculator
2 marks

The following force diagram shows three forces acting on a particle:

3-3-q-2-e-a-level-maths-mechanics

Use trigonometry to resolve the 17 N force into its horizontal and vertical components.

2b
Sme Calculator
2 marks

Hence find the magnitude and direction of the resultant forces acting on the particle in the horizontal and vertical directions.

Did this page help you?

3a
Sme Calculator
2 marks

A particle is said to be in equilibrium when the total force acting on it in any direction is zero.

The following force diagram shows three forces acting on a particle:

3-3-q-3-e-a-level-maths-mechanics

Use trigonometry to resolve the 30 N force into its horizontal and vertical components.  Give your answers correct to 3 significant figures.

3b
Sme Calculator
2 marks

Given that the particle is in equilibrium, find the values of P and space Q.

Did this page help you?

4a
Sme Calculator
1 mark

A particle of mass m space kg is suspended by a light inextensible string, with the other end of the string attached to a fixed point A.  With the string at an angle of 30 degree to the vertical, equilibrium is maintained by a horizontal force of P N which acts on the particle as shown in the diagram below:

3-3-q-4-e-a-level-maths-mechanics

Given that g is the constant of acceleration due to gravity, explain what the downward force of m g space straight N represents in the diagram.

4b
Sme Calculator
2 marks

The tension in the string, T, is a force acting on the particle along the line of the string, in the direction from the particle towards A.  The tension in the string is found to be 16 N.

Use trigonometry to resolve T into its horizontal and vertical components.

4c
Sme Calculator
2 marks

Hence find the values of P and m.

Did this page help you?

5a
Sme Calculator
3 marks

The following diagram depicts a particle A of mass m space kg on a slope that is angled at theta degree to the horizontal:

3-3-q-5-e-a-level-maths-mechanics

The weight of the particle is indicated by the force W space equals space m g.  As shown, the weight may be decomposed into its components W subscript perpendicular and W subscript parallel to,  where W subscript perpendicular space equals space m g space cos space theta is the component of the weight perpendicular to the surface of the slope and W subscript parallel to equals m g space s i n space theta is the component of the weight parallel to the surface of the slope.

A particle of mass 5 kg is sliding down a smooth slope that is angled at 30 degree to the horizontal.

By considering the forces acting on the particle in directions parallel to the surface of the slope, and by using the Newton’s Second Law of Motion equation F space equals space m a,  calculate the acceleration of the particle down the slope.

5b
Sme Calculator
3 marks

By considering the forces acting on the particle in directions perpendicular to the surface of the slope, and by using the fact that the resultant force perpendicular to the slope is zero,  calculate the normal reaction force of the slope on the particle.

Did this page help you?

6
Sme Calculator
13 marks

For an object on a rough surface, the force of friction will always act to oppose the motion of the object along the surface.  The maximum frictional force, F subscript M A X end subscript, may be found by the formula

F subscript M A X end subscript space equals space μR

where µ is a constant called the coefficient of friction, and R is the normal reaction force exerted by the surface on the object.

If the object is at rest and the sum of other forces acting on the object parallel to the surface is less than or equal to F subscript M A X end subscript, then the object will remain at rest.  In that case the actual frictional force will be equal in magnitude and opposite in direction to the sum of the other forces.  If the sum of the other forces in the parallel direction is greater than F subscript M A X end subscript, then the object will begin to accelerate in the direction of those other forces.  In that case the force of friction will be equal to F subscript M A X end subscript, and it will act in the direction opposite to the direction of motion of the object.

For an object in motion, the force of friction will always be equal to F subscript M A X end subscript, and will act in the direction opposite to the direction of motion of the object.

In each of the situations depicted below, the object is initially at rest.  Find the magnitude of the frictional force F that will act upon the object in each case, and determine whether the object will remain at rest or begin to move.

(i)
3-3-q-6-e-a-level-maths-mechanics
(ii)
WAbrQ-YT_3-3-q-6-ii-e-a-level-maths-mechanics


(iii)
3-3-q-6-iii-e-a-level-maths-mechanics


(iv)
3-3-q-6-iv-e-a-level-maths-mechanics

Did this page help you?

7
Sme Calculator
7 marks

The maximum frictional force between an object and a rough surface, F subscript M A X end subscript, may be calculated using the formula F subscript M A X end subscript space equals mu R,  where mu is the coefficient of friction and R is the normal reaction force exerted by the surface on the object.  For a stationary object, when the magnitude of the sum of other forces parallel to the surface is exactly equal to F subscript M A X end subscript the object is said to be in limiting equilibrium.  An object in limiting equilibrium is on the point of moving under the influence of the non-frictional forces. 

In each of the following examples, the object shown is at rest on a rough horizontal surface, and is on the point of moving under the influence of the force P.  By first decomposing forces into components parallel and perpendicular to the surface where necessary, calculate the value of P in each instance.

(i)
3-3-q-7-e-a-level-maths-mechanics
(ii)
3-3-q-7-ii-e-a-level-maths-mechanics

Did this page help you?

8a
Sme Calculator
3 marks

This question involves a particle of mass 5 kg in motion on a rough plane which is inclined at 30 degree to the horizontal.  The coefficient of friction between the particle and the plane is 0.3.

Initially the particle is projected up a line of greatest slope of the plane, and moves upwards until the combined forces of friction and gravity cause it to come to rest.

By first decomposing the weight of the particle into components parallel and perpendicular to the plane, determine the frictional force acting on the particle as it moves up the plane.  Be sure to give both the magnitude and the direction of the force.

8b
Sme Calculator
3 marks

Using your results from part (a), along with the Newton’s Second Law of Motion equation F space equals space m a,  determine the acceleration of the particle while it is moving up the plane.  Be sure to give both the magnitude and the direction of the acceleration.

8c
Sme Calculator
2 marks

After coming momentarily to rest, the particle begins to slide back down the plane.

Determine the frictional force acting on the particle as it slides down the plane, being sure to give both the magnitude and the direction of the force.

8d
Sme Calculator
3 marks

Determine the acceleration of the particle while it is sliding down the plane, being sure to give both the magnitude and the direction of the acceleration.

Did this page help you?

1
Sme Calculator
4 marks

The following force diagram shows three forces acting on a particle:

3-3-q-1-e-a-level-maths-mechanics

Find the magnitude and direction of the resultant forces acting on the particle in the horizontal and vertical directions.

Did this page help you?

2a
Sme Calculator
3 marks

The following force diagram shows three forces acting on a particle:

FRVC2wU4_3-3-q-2-e-a-level-maths-mechanics

Show that the resultant force on the particle in the horizontal direction is zero.

2b
Sme Calculator
3 marks

Given that the particle is in equilibrium, find the exact value of F.

Did this page help you?

3
Sme Calculator
5 marks

A particle of mass m space kg is suspended by a light inextensible string, with the other end of the string attached to a fixed point P.  With the string at an angle of 40 degree to the vertical, equilibrium is maintained by a horizontal force of 12 N which acts on the particle as shown in the diagram below:

rhJZokPx_3-3-q-3-e-a-level-maths-mechanics

Find

(i)
the tension in the string
(ii)
the value of m.

Did this page help you?

4a
Sme Calculator
3 marks

A particle of mass 10 kg is sliding down a smooth slope that is angled at 15 degree to the horizontal.

Calculate the acceleration of the particle down the slope.

4b
Sme Calculator
3 marks

Calculate the normal reaction force of the slope on the particle.

Did this page help you?

5a
Sme Calculator
4 marks

A particle of mass 7 kg is being pulled along a rough horizontal plane by a force of 45 N acting at an angle of 20 degree to the horizontal.

zcijBtyZ_3-3-q-5-e-a-level-maths-mechanics

The coefficient of friction between the particle and the plane is 0.4, and the particle is moving to the right under the influence of the force.

By first finding the normal reaction force, calculate the frictional force between the particle and the plane and state its direction.

5b
Sme Calculator
3 marks

Hence calculate the acceleration of the particle.

Did this page help you?

6
Sme Calculator
6 marks

A particle of mass 0.7 kg is on a rough plane which is angled at 35 degree to the horizontal.  The particle is being held at rest by a force of P N acting up the plane along the line of greatest slope.

vva8We4v_3-3-q-6-e-a-level-maths-mechanics

Given that the coefficient of friction between the particle and the plane is 0.35, and that the particle is on the point of slipping up the plane, find the value of P.

Did this page help you?

7
Sme Calculator
5 marks

A particle of mass 3 kg is released from rest on a rough plane which is inclined at 15 degree to the horizontal.  The coefficient of friction between the particle and the plane is 0.2.

Determine the distance the particle will slide down the plane in the first 3 seconds after it is released.

Did this page help you?

8a
Sme Calculator
4 marks

A particle of mass 3 kg is projected up a rough plane which is inclined at an angle of 25 degree to the horizontal.  It is projected up the line of greatest slope with an initial velocity of u space straight m space straight s to the power of negative 1 end exponent, and it comes to instantaneous rest after moving a distance of 1.91 m up the slope.  The coefficient of friction between the particle and the slope is 0.27.

Show that while the particle is moving up the plane it experiences a deceleration of left parenthesis sin space 25 plus 0.27 space cos space 25 right parenthesis space g space straight m space straight s to the power of negative 2 end exponent,  where g is the constant of acceleration due to gravity.

8b
Sme Calculator
3 marks

Hence find the value of  u.

Did this page help you?

9
Sme Calculator
6 marks

A box B of mass 5 kg rests on a rough horizontal table.  It is connected by a light inextensible string to a metal sphere A of mass 2 kg.  The string passes over a smooth light fixed pulley at the edge of the table so that A is hanging vertically downwards as shown in the diagram below:

3-3-q-9-m-a-level-maths-mechanics

The string between B and the pulley is horizontal, and the coefficient of friction between B and the table is 0.35.

The system is released from rest with the string taut.

Calculate

(i)
the acceleration of the two objects
(ii)
the tension in the string


as A descends.

Did this page help you?

10a
Sme Calculator
7 marks

Two particles A and B, of masses 4 kg and 3 kg respectively, are connected by means of a light inextensible string.  Particle A is held motionless on a rough fixed plane inclined at 35 degree to the horizontal.  The string passes over a smooth light pulley fixed at the top of the plane so that B is hanging vertically downwards as shown in the diagram below:

3-3-q-10-m-a-level-maths-mechanics

The string between A and the pulley lies along a line of greatest slope of the plane, and B hangs freely from the pulley.  The coefficient of friction between particle A and the plane is 0.15.

The system is released from rest with the string taut.

Calculate the acceleration of the two objects and the tension in the string as B descends.

10b
Sme Calculator
6 marks

After descending for 3.2 seconds, particle B strikes the ground and immediately comes to rest.  Particle A continues to move up the slope until the forces of gravity and friction cause it to come momentarily to rest.

Find the total distance travelled by particle A between the time that the system is first released from rest and the time that particle A comes momentarily to rest again after B has struck the ground.

Did this page help you?

1
Sme Calculator
5 marks

The following force diagram shows three forces acting on a particle:

 mech-3-3-h-q1

Find the magnitude and direction of the resultant forces acting on the particle in the horizontal and vertical directions.

Did this page help you?

2
Sme Calculator
4 marks

The following force diagram shows three forces acting on a particle:

 mech-3-3-h-q2

Given that the particle is in equilibrium, find:

(i)
the magnitude of force F
(ii)
the angle, theta, that F makes with the horizontal.

Give both your answers correct to 3 significant figures.

Did this page help you?

3
Sme Calculator
6 marks

A particle of mass m kg  hangs in equilibrium, suspended by two light inextensible strings. The strings are inclined at 25° and 70° to the horizontal, as shown in the diagram below:

mech-3-3-h-q3

Given that the tension in the string angled at 70° to the horizontal is 56 N, find the value of m.

Did this page help you?

4a
Sme Calculator
3 marks

A particle of mass 12 kg is being pushed up a smooth slope by a force of 50 N that acts horizontally. The slope is inclined at  to the horizontal, as shown in the diagram below:

mech-3-3-h-q4

Calculate the acceleration of the particle up the slope.

4b
Sme Calculator
3 marks

Calculate the normal reaction force of the slope on the particle.

Did this page help you?

5a
Sme Calculator
3 marks

A particle of mass 15 kg is sliding down a rough slope that is angled 25° to the horizontal. The coefficient of friction between the particle and the slope is 0.3.

Calculate the frictional force between the particle and the slope.

5b
Sme Calculator
3 marks

Hence calculate the acceleration of the particle down the slope.

Did this page help you?

6
Sme Calculator
6 marks

A particle of mass 0.9 kg is at rest on a rough horizontal plane.  A force of magnitude P N is acting on the particle at an angle of 40° to the horizontal.

mech-3-3-h-q6

Given that the coefficient of friction between the plane and the particle is 0.3, and that the particle is on the point of moving to the right under the influence of the force, find the value of P.

Did this page help you?

7
Sme Calculator
5 marks

A particle of mass m kg is released from rest on a rough plane inclined at θ° to the horizontal, where 45 degree less than theta less than 90 degree.  The coefficient of friction between the particle and the plane is mu.

 

Given that the particle remains motionless after it is released, show that mu greater than 1.

Did this page help you?

8
Sme Calculator
7 marks

A particle of mass 2 kg is projected up a rough plane which is inclined at an angle of 20° to the horizontal.  It is projected up the line of greatest slope with an initial velocity of u space straight m space straight s to the power of negative 1 end exponent, and it comes to instantaneous rest after moving a distance of 4.85 m up the slope.  The coefficient of friction between the particle and the slope is 0.2.

Find the value of u.

Did this page help you?

9
Sme Calculator
8 marks

Two particles A and B, of masses 2.7 kg and 2.2 kg respectively, are connected by means of a light inextensible string.  Particle A is held motionless on a rough fixed plane inclined at 25° to the horizontal.  The string passes over a smooth light pulley fixed at the top of the plane so that B is hanging vertically downwards as shown in the diagram below:

mech-3-3-h-q9

The string between A and the pulley lies along a line of greatest slope of the plane, and B hangs freely from the pulley.  The coefficient of friction between particle A and the plane is μ.

 

The system is released from rest with the string taut.  Given that particle B descends 1.82 m in the first 3 seconds after it is released, find the value of μ.

Did this page help you?

10
Sme Calculator
13 marks

Two particles A and B, of identical mass, are connected by means of a light inextensible string. Particle A is held motionless on a rough fixed plane inclined at 30° to the horizontal, and that plane is connected at its top to another rough fixed plane inclined at 70° to the horizontal.  The string passes over a smooth light pulley fixed at the top of the two planes so that B is hanging downwards in contact with the second plane.   This situation is shown in the diagram below:

mech-3-3-h-q10

The parts of the string between A and the pulley and between B and the pulley each lie along a line of greatest slope of the respective planes. The coefficient of friction between the particles and the planes is 0.15 in both cases.

The system is released from rest with the string taut, and with particle B a vertical distance of 0.75 space straight m from the ground.  Particle B descends along the slope until it reaches the ground, at which point it immediately comes to rest.  Particle A continues to move up the slope until the forces of gravity and friction cause it to come momentarily to rest.

Find the total distance travelled by particle A between the time that the system is first released from rest and the time that particle A comes momentarily to rest again after B has reached the ground.

Did this page help you?

1
Sme Calculator
5 marks

The following force diagram shows three forces acting on a particle:

3-3-v-h-q-1-a-level-maths-mechnics

Given that the resultant force on the particle in the vertical direction is 44.8 N downwards, find the size of the angle theta.  Give your answer in degrees correct to 3 significant figures.

Did this page help you?

2a
Sme Calculator
3 marks

In a warehouse, a lifting device is used to lift a load of weight W by means of two lifting cables as shown in the diagram below:

3-3-v-h-q-2-a-level-maths-mechnics

The tension, T,  is the same in each of the lifting cables,  and the angle that each of the cables makes with the vertical, theta,  is also the same.  For purposes of this question any influences on the motion of the load other than the weight of the load and the tension in the two cables may be ignored.

Given that the load is initially motionless, find an inequality in terms of T and theta that the weight W must satisfy if it is to be lifted by the cables.

2b
Sme Calculator
3 marks

Given that the load must still be accelerating in the upwards direction when theta space equals space 45 degree,  find an inequality in terms of W that the tension T must satisfy.

Did this page help you?

3
Sme Calculator
6 marks

A smooth bead B with a mass of m grams has been threaded onto a light inextensible string.  The ends of the string are fixed to two points A and C, where A is vertically above C.  The bead is held in equilibrium by a horizontal force of 3 N, with sections  A B and B C of the string making angles of 35 degree and 55 degree respectively with the vertical as shown in the diagram below:

3-3-v-h-q-3-a-level-maths-mechnics

Find the value of m.

Did this page help you?

4a
Sme Calculator
3 marks

A particle is being pulled up a smooth slope by a force of 60 N that acts at an angle of 15 degree to the slope.  The slope is inclined at 25 degree to the horizontal, as shown in the diagram below:

3-3-v-h-q-4-a-level-maths-mechnics

The particle experiences an acceleration of 0.3 space straight m space straight s to the power of negative 2 end exponent parallel to the slope in the upwards direction.

Use the information provided above to calculate the mass of the particle.

4b
Sme Calculator
3 marks

Calculate the normal reaction force of the slope on the particle.

Did this page help you?

5
Sme Calculator
6 marks

A laboratory apparatus contains a rough inclined plane that may be inclined at different angles to the horizontal.  When the plane is at an angle of theta subscript 1 to the horizontal, where 0 space less than theta subscript 1 space less than space 90 degree,  a small mass is released from rest on the plane and remains motionless.  After the angle is increased to theta subscript 2,  where theta subscript 2 space less than space 90 degree,  the same small mass is released from rest on the plane and begins to slide down the slope of the plane.

Show that

tan space theta subscript 1 space less or equal than space mu space less than space tan space theta subscript 2

where mu is the coefficient of friction between the small mass and the plane.

Did this page help you?

6
Sme Calculator
6 marks

A particle of mass 0.5 kg is at rest on a rough plane which is inclined at 35 degree to the horizontal.  The particle is being acted upon by a force of 6 N, directed at an angle of theta degree to the plane.  The line of action of the force is in the same vertical plane as the line of greatest slope of the inclined plane.

3-3-v-h-q-6-a-level-maths-mechnics

Given that the coefficient of friction between the particle and the plane is 0.4, and that the particle is on the point of slipping up the plane, find the value of theta.

You may use the following trigonometric identity in your working without proof:

6 space cos space theta space minus space 2.4 space sin space theta space identical to space fraction numerator 6 square root of 29 over denominator 5 end fraction cos space open parentheses theta plus tan to the power of negative 1 end exponent open parentheses 0.4 close parentheses close parentheses

Did this page help you?

7
Sme Calculator
7 marks

A particle of mass 0.8 kg is released from rest on a rough slope that is angled at theta degree to the horizontal, where tan space theta space equals space 2 over 7.  After 4 seconds the speed of the particle is 1.35 space straight m space straight s to the power of negative 1 end exponent.  Find the value of the coefficient of friction mu between the particle and the slope.

Did this page help you?

8a
Sme Calculator
7 marks

A particle of mass begin mathsize 20px style m end style kg is projected up a rough plane which is inclined at an angle of theta degree to the horizontal.  It is projected up the line of greatest slope with an initial velocity of begin mathsize 20px style u end style metres per second, and it comes to instantaneous rest in t subscript 1 seconds after moving a distance of s metres up the slope. The coefficient of friction between the particle and the slope is mu.

Show that:

(i)
t subscript 1 space equals space fraction numerator u over denominator g space open parentheses sin space theta space plus space mu space cos space theta close parentheses end fraction
(ii)
s space equals space fraction numerator u squared over denominator 2 space g space open parentheses sin space theta space plus space mu space cos space theta close parentheses end fraction
8b
Sme Calculator
4 marks

After coming to instantaneous rest, the particle begins to slide back down the slope, and after t2 seconds it has returned to its starting point.

Find an expression for t2 in terms of u space comma space g space comma space mu space and space theta.

Did this page help you?

9a
Sme Calculator
11 marks

You have landed on the planet Hephaestia, where the gravitational constant of acceleration g has a different value than it does on Earth. 

Your spaceship contains a device which may be used to find the value of g on any planet.  In this device a particle A with mass mA kg is connected by a light inextensible string to a light scale-pan.  A force meter C with mass mC kg is placed in the scale-pan, and a small block B with mass mB kg is placed on top of C. A is held in place on a rough plane angled at θ° to the horizontal, where the coefficient of friction between A and the plane is µ.  The string passes over a smooth light pulley fixed at the top of the plane so that the scale-pan is hanging vertically downwards as shown in the diagram below:

mech-3-3-vh-q9

With the string between A and the pulley lying along a line of greatest slope of the plane, A is projected down the plane with a velocity of v space straight m space straight s to the power of negative 1 end exponent parallel to the string.  After a time of t seconds the system comes momentarily to rest, and then the scale-pan begins to descend under the force of gravity, pulling mass A up the slope behind it.

When the scale-pan is initially moving upwards, the force exerted by B on C is denoted by FBC. When the scale-pan begins to descend, the force exerted by B on C is denoted by FBC↓. The force meter is only able to record the difference ΔF between these two values, where straight capital delta F space equals space F subscript B C end subscript downwards arrow space minus space F subscript B C end subscript upwards arrow.

Show that

straight capital delta F equals open parentheses fraction numerator 2 m subscript A m subscript B over denominator m subscript A plus m subscript B plus m subscript C end fraction close parentheses space g   mu space c o s space theta

9b
Sme Calculator
2 marks

For your ship’s device,  m subscript A space equals space 3 comma space space m subscript B space equals space 1 comma space m subscript C space equals space 2 comma space theta space equals space 30 space and space µ space equals space 0.4.

Find the value of g on Hephaestia, given that the value recorded for ΔF is 1.286 N.

Did this page help you?