Acid-Base Titration (OCR AS Chemistry A): Revision Note
Exam code: H032
PAG 2: Acid-base titration
There are a series of suggested practicals for PAG 2 - Acid-base titration
PAG 2.1: Determination of the concentration of hydrochloric acid
Making a standard solution of sodium hydrogencarbonate
Titrating this against hydrochloric acid
Determining the concentration of the acid
PAG 2.2: Determination of the molar mass of an acid
Making a solution of an unknown hydrated acid (e.g. citric acid monohydrate)
Titrating this against a sodium hydroxide solution of known concentration.
Determining the molar mass of the acid and, with additional information, the formula of the acid
PAG 2.3: Identification of an unknown carbonate
Making a solution of an unknown Group 1 carbonate
Titrating this solution against hydrochloric acid of a known concentration
Determine the molar mass of the carbonate and the identity of the metal
All three suggested practicals use volumetric analysis
This requires making standard solutions and completing titration experiments
The main difference between the practicals is how the titration results are processed
Volumetric analysis
Volumetric analysis uses the volume and concentration of one chemical reactant (a volumetric solution) to determine the concentration of another unknown solution
The technique most commonly used is a titration
The volumes are measured using two precise pieces of equipment:
A volumetric or graduated pipette
A burette
Before the titration can be done, the standard solution must be prepared
Specific apparatus must be used both when preparing the standard solution and when completing the titration, to ensure that volumes are measured precisely

Beaker
Burette
Volumetric Pipette
Conical Flask
Volumetric Flask
Making a volumetric solution
Chemists routinely prepare solutions needed for analysis, whose concentrations are known precisely
These solutions are termed volumetric solutions or standard solutions
They are made as accurately and precisely as possible using three decimal place balances and volumetric flasks
This reduces the impact of measurement uncertainties
The steps are:


Volumes & concentrations of solutions
The concentration of a solution is the amount of solute dissolved in a solvent to make 1 dm3 of solution
The solute is the substance that dissolves in a solvent to form a solution
The solvent is often water
A concentrated solution is a solution that has a high concentration of solute
A dilute solution is a solution with a low concentration of solute
Concentration is usually expressed in one of three ways:
moles per unit volume (mol dm-3)
mass per unit volume (g dm-3)
parts per million (ppm)
Worked Example
Calculate the mass of sodium hydrogencarbonate, NaHCO3, required to prepare 250 cm3 of a 0.200 mol dm-3 solution
Answer:
Calculate the moles of NaHCO3 needed from the concentration and volume:
number of moles = concentration (mol dm-3) x volume (dm3)
n = 0.200 mol dm-3 x 0.250 dm3
n = 0.0500 mol
Calculate the molar mass of NaHCO3
Mr = 23.0 + 1.0 + 12.0 + (16.0 x 3) = 84.0 g mol-1
Calculate the mass of NaHCO3 required
mass = moles x molar mass
mass = 0.0500 mol x 84.0 g mol-1 = 4.2 g
Performing the titration
The key piece of equipment used in the titration is the burette
Burettes are usually marked to a precision of 0.10 cm3
Since they are analogue instruments, the uncertainty is recorded to half the smallest marking, in other words to ±0.05 cm3
The end point or equivalence point occurs when the two solutions have reacted completely and is shown with the use of an indicator

The steps in a titration
A white tile is placed under the conical flask while the titration is performed, to make it easier to see the colour change

Titrating
The steps in a titration are:
Measuring a known volume (usually 20 or 25 cm3) of one of the solutions with a volumetric pipette and placing it into a conical flask
The other solution is placed in the burette
To start with, the burette will usually be filled to 0.00 cm3
A few drops of the indicator are added to the solution in the conical flask
The tap on the burette is opened and the solution is slowly added to the conical flask until the indicator starts to change colour
As you start getting near to the end point, the flow of the burette should be slowed right down so that the solution is added dropwise
You should be able to close the tap on the burette after one drop has caused the colour change
Multiple runs are carried out until concordant results are obtained
Concordant results are within 0.1 cm3 of each other
Recording and processing titration results
Both the initial and final burette readings should be recorded and shown to a precision of ±0.05 cm3, the same as the uncertainty

A typical layout and set of titration results
The volume delivered (titre) is calculated and recorded to an uncertainty of ±0.10 cm3
The uncertainty is doubled
This is because two burette readings are made to obtain the titre (V final – V initial)
This follows the rules for propagation of uncertainties
Concordant results are then averaged, and non-concordant results are discarded
The appropriate calculations are then done
Worked Example
PAG 2.1: Determining hydrochloric acid concentration
25.0 cm3 of hydrochloric acid was titrated with a 0.200 mol dm-3 solution of sodium hydrogencarbonate, NaHCO3.
NaHCO3 (aq) + HCl (aq) → NaCl (aq)+ H2O (l) + CO2 (g)
Use the following results to calculate the concentration of the acid, to 3 significant figures.
| Rough | Run 1 | Run 2 | Run 3 |
---|---|---|---|---|
Initial burette reading / cm3 (±0.05 cm3) | 0.00 | 23.15 | 0.20 | 23.00 |
Final burette reading / cm3 (±0.05 cm3) | 23.75 | 45.95 | 23.00 | 46.10 |
Volume delivered / cm3 (±0.10 cm3) | 23.75 | 22.80 | 22.80 | 23.10 |
Answer:
Calculate the average titre from concurrent titrations only
Concurrent titrations are within 0.10 cm3 of each other
Average titre = = 22.80 cm3
Calculate the number of moles of sodium hydrogencarbonate
Moles of NaHCO3 = x 0.200 = 4.56 x 10-3 moles
Calculate (or deduce) the number of moles of hydrochloric acid
The stoichiometry of NaHCO3 : HCl is 1 : 1
Moles of HCl = 4.56 x 10-3 moles
Calculate the concentration of hydrochloric acid
Concentration =
Concentration = = 0.182 mol dm-3
Worked Example
PAG 2.2: Determining the molar mass of an acid
0.133 g of an unknown monoprotic acid is added to a 1.0 dm3 volumetric flask and made up to the mark with distilled water. This solution is titrated with 0.070 mol dm-3 sodium hydroxide solution. The average titre required for the neutralisation of the unknown monoprotic acid is 23.40 cm3.
i) Calculate the molar mass of the unknown acid.
ii) The unknown monoprotic acid is a halogenated acid. Identify the unknown monoprotic acid.
Answer:
Part i)
Calculate the number of moles of sodium hydroxide
Moles of NaOH1.638 x 10-3 moles
State the number of moles of the unknown monoprotic acid
The stoichiometry of HX : NaOH is 1 : 1
Moles of HX = 1.638 x 10-3 moles
Calculate the molar mass of the unknown monoprotic acid
Mr =
Mr = = 81.20 g mol-1
Part ii)
Calculate the mass of the halogen
81.20 - 1.0 = 80.2
Use the periodic table to identify the halogen
80.2 ≈ Bromine (79.9)
State the final answer
The unknown monoprotic acid is HBr / hydrobromic acid
Examiner Tips and Tricks
You can potentially be asked to calculate the molar mass of any unknown acid
This includes monoprotic, diprotic and even triprotic acids
You must account for the stoichiometry of the neutralisation reaction
You have to be given information to deduce the identity of the unknown acid
Worked Example
PAG 2.3: IdentifYING an unknown carbonate
1.19 g of an unidentified Group 1 metal carbonate, X2CO3, was dissolved in water to produce a 250.0 cm³ standard solution. 25.0 cm³ aliquots of this solution were titrated with 0.150 mol dm3 hydrochloric acid. The average titre for this experiment was found to be 14.95 cm3.
Identify the Group 1 metal in the unidentified metal carbonate X2CO3.
Answer
Calculate the number of moles of hydrochloric acid
Moles of HCl2.2425 x 10-3 moles
Calculate the number of moles of X2CO3
The stoichiometric ratio is 1X2CO3 : 2HCl
Moles of X2CO31.12125 x 10-3 moles
3. Calculate the mass of X2CO3 in the 25.0 cm3 aliquot
= 0.119 g
Calculate the molar mass of X2CO3
Mr =
Mr = = 106.132 g mol-1
Calculate the mass of X in X2CO3
= 23.066
Use the periodic table to identify the Group 1 element in X2CO3
23.066 ≈ Sodium / Na (relative mass of 23.0)
Examiner Tips and Tricks
Careful: Examiners have been known to construct this question to get the mass of X as around 86.0 - 86.5
This then gets a mixture of answers of X = rubidium or francium
This happens because students use the wrong number to identify the element
Rubidium has a mass number of 85.5
Francium has an atomic number of 87
Practical skills reminder
These titration-based practicals help develop essential experimental techniques, including:
Accurately measuring volumes using volumetric pipettes, burettes, and volumetric flasks
Preparing standard solutions with appropriate equipment and minimising measurement uncertainties
Recording burette readings to the correct precision and accounting for instrumental uncertainty
Performing titrations safely and effectively, using indicators and controlling flow rates near the endpoint
Calculating concentrations, molar masses, and formulae using balanced equations and volume data
Interpreting titration data to identify unknown compounds, following correct stoichiometric reasoning
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