Water of Crystallisation
- Water of crystallisation is when some compounds can form crystals which have water as part of their structure
- A compound that contains water of crystallisation is called a hydrated compound
- The water of crystallisation is separated from the main formula by a dot when writing the chemical formula of hydrated compounds
- E.g. hydrated copper(II) sulfate is CuSO4•5H2O
- A compound which doesn’t contain water of crystallisation is called an anhydrous compound
- E.g. anhydrous copper(II) sulfate is CuSO4
- A compound can be hydrated to different degrees
- E.g. cobalt(II) chloride can be hydrated by six or two water molecules
- CoCl2•6H2O or CoCl2•2H2O
- The conversion of anhydrous compounds to hydrated compounds is reversible by heating the hydrated salt:
Hydrated: CuSO4•5H2O ⇌ CuSO4 + 5H2O :Anhydrous
- The degree of hydration can be calculated from experimental results:
- The mass of the hydrated salt must be measured before heating
- The salt is then heated until it reaches a constant mass
- The two mass values can be used to calculate the number of moles of water in the hydrated salt - known as the water of crystallisation
Worked example
Calculating water of crystallisation
10.0 g of hydrated copper sulfate are heated to a constant mass of 5.59 g.
Determine the formula of the original hydrated copper sulfate, CuSO4•xH2O.
(Mr data: CuSO4 = 159.6, H2O = 18.0)
Answer:
Compounds | CuSO4 | H2O |
Mass of each compound (g) |
5.59 | 4.41 |
Formula mass | 159.6 | 18.0 |
Moles = mass / Mr | = 0.035 | = 0.245 |
Ratio (divide by smallest value) | = 1 | = 7 |
- So, the value of x is 7
- Therefore, the formula of the hydrated salt is CuSO4•7H2O
Examiner Tip
A water of crystallisation calculation can be completed in a similar fashion to an empirical formula calculation
- Instead of elements, you start with the salt and water
- Instead of dividing by atomic masses, you divide by molecular / formula masses
- The rest of the calculation works the same way as the empirical formula calculation