Syllabus Edition

First teaching 2023

First exams 2025

|

Relative Masses (CIE AS Chemistry)

Revision Note

Test yourself
Richard

Author

Richard

Last updated

Relative Masses

Atomic Mass Unit

  • The mass of a single atom is so small that it is impossible to weigh it directly
  • Atomic masses are therefore defined in terms of a standard atom which is called the unified atomic mass unit
  • This unified atomic mass is defined as one-twelfth of the mass of a carbon-12 isotope
  • The symbol for the unified atomic mass is u (often Da, Dalton, is used as well)
  • 1 u = 1.66 x 10-27 kg

Relative atomic mass, Ar

  • The relative atomic mass (Ar) of an element is the ratio of the average mass of the atoms of an element to the unified atomic mass unit
  • The relative atomic mass is determined by using the average mass of the isotopes of a particular element
  • The Ar has no units as it is a ratio and the units cancel each other out

Relative atomic mass of Xfraction numerator average space mass space of space one space atom space of space bold X over denominator one space twelfth space of space the space space mass space of space one space carbon minus 12 space atom end fraction 

Relative isotopic mass

  • The relative isotopic mass is the mass of a particular atom of an isotope compared to the value of the unified atomic mass unit
  • Atoms of the same element with a different number of neutrons are called isotopes
  • Isotopes are represented by writing the mass number as 20Ne, or neon-20 or Ne-20
    • To calculate the average atomic mass of an element the percentage abundance is taken into account
    • Multiply the atomic mass by the percentage abundance for each isotope and add them all together
    • Divide by 100 to get average relative atomic mass
    • This is known as the weighted average of the masses of the isotopes

Relative space atomic space mass equals fraction numerator straight capital sigma open parentheses isotope space percentage space abundance cross times isotope space mass space number close parentheses over denominator 100 end fraction

Relative molecular mass, Mr

  • The relative molecular mass (Mr) is the ratio of weighted average mass of a molecule of a molecular compound to the unified atomic mass unit
  • The Mr has no units

M subscript straight r equals fraction numerator weighted space average space mass space of space molecules space in space straight a space given space sample space of space straight a space molecular space compound over denominator unified space atomic space mass space unit end fraction

  • The Mr can be found by adding up the relative atomic masses of all atoms present in one molecule
  • When calculating the Mr the simplest formula for the compound is used, also known as the formula unit
    • Eg. silicon dioxide has a giant covalent structure, however the simplest formula (the formula unit) is SiO2

Example Mr calculations

Substance Atoms present Mr
Hydrogen
(H2)
2 x H (2 x 1.0) = 2.0
Water
(H2O)
(2 x H) + (1 x O) (2 x 1.0) + (1 x 16.0) = 18.0
Potassium carbonate
(K2CO3)
(2 x K) + (1 x C) + (3 x O)

(2 x 39.1) + (1 x 12.0)
+ (3 x 16.0) = 138.2

Calcium hydroxide
(Ca(OH)2)
(1 x Ca) + (2 x O) + (2 x H) (1 x 40.1) + (2 x 16.0)
+ (2 x 1.0) = 74.1
Ammonium sulfate
((NH4)2SO4)
(2 x N) + (8 x H) + (1 x S) + (4 x O) (2 x 14.0) + (8 x 1.0) + (1 x 32.1)
+ (4 x 16.0) = 132.1

Relative formula mass, Mr 

  • The relative formula mass (Mr) is used for compounds containing ions
  • It has the same units and is calculated in the same way as the relative molecular mass
  • In the table above, the Mr for potassium carbonate, calcium hydroxide and ammonium sulfates are relative formula masses

You've read 0 of your 10 free revision notes

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Richard

Author: Richard

Expertise: Chemistry

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.