Reaction of Chlorine
- A disproportionation reaction is a reaction in which the same species is both oxidised and reduced
- The reaction of chlorine with dilute alkali is an example of a disproportionation reaction
- In these reactions, the chlorine gets oxidised and reduced at the same time
- Different reactions take place at different temperatures of the dilute alkali
Chlorine in cold alkali (15 oC)
- The reaction that takes place is:
Cl2 (aq) + 2NaOH (aq) → NaCl (aq) + NaClO (aq) + H2O (l)
- The ionic equation is:
Cl2 (aq) + 2OH– (aq) → Cl– (aq) + ClO– (aq) + H2O (l)
- The ionic equations show that the chlorine undergoes disproportionation, i.e. gets both oxidised and reduced
- Chlorine gets oxidised as there is an increase in oxidation number from 0 in Cl2 (aq) to +1 in ClO– (aq)
- The half-equation for the oxidation reaction is:
½Cl2 (aq) + 2OH– (aq) → ClO– (aq) + H2O (l) + e–
- Chlorine gets reduced as there is a decrease in oxidation number from 0 in Cl2 (aq) to –1 in Cl– (aq)
- The half-equation for the reduction reaction is:
½Cl2 (aq) + e– → Cl– (aq)
Chlorine in hot alkali (70 oC)
- The reaction that takes place is:
3Cl2 (aq) + 6NaOH (aq) → 5NaCl (aq) + NaClO3 (aq) + 3H2O (l)
- The ionic equation is:
3Cl2 (aq) + 6OH– (aq) → 5Cl– (aq) + ClO3– (aq) + H2O (l)
- The ionic equations show that the chlorine undergoes disproportionation, i.e. gets both oxidised and reduced
- Chlorine gets oxidised as there is an increase in oxidation number from 0 in Cl2 (aq) to +5 in ClO3– (aq)
- The half-equation for the oxidation reaction is:
½Cl2 (aq) + 6OH– (aq) → ClO3– (aq) + 3H2O (l) + e–
- Chlorine gets reduced as there is a decrease in oxidation number from 0 in Cl2 (aq) to –1 in Cl– (aq)
- The simplified half-equation for the reduction reaction is:
½Cl2 (aq) + e– → Cl– (aq)