Ionisation Energy Trends (Cambridge (CIE) AS Chemistry)

Revision Note

Last updated

  • Ionisation energies show periodicity - a trend across a period of the Periodic Table

  • As could be expected from their electronic configuration, the group I metals have a relatively low ionisation energy, whereas the noble gases have very high ionisation energies

  • The size of the first ionisation energy is affected by four factors:

    • Size of the nuclear charge

      • The nuclear charge increases with increasing atomic number, which means that there are greater attractive forces between the nucleus and electrons, so more energy is required to overcome these attractive forces when removing an electron

    • Distance of outer electrons from the nucleus

      • Electrons in shells that are further away from the nucleus are less attracted to the nucleus - the nuclear attraction is weaker - so the further the outer electron shell is from the nucleus, the lower the ionisation energy

    • Shielding effect of inner electrons

      • The shielding effect is when the electrons in full inner shells repel electrons in outer shells, preventing them from feeling the full nuclear charge, so the more shells an atom has, the greater the shielding effect, and the lower the ionisation energy

    • Spin-pair repulsion

      • Electrons in the same atomic orbital in a subshell repel each other more than electrons in different atomic orbitals which makes it easier to remove an electron (which is why the first ionisation energy is always the lowest)

Ionisation Energy & the Periodic Table

  • So, the first ionisation energy increases across a period and decreases down a group

Graph of first ionisation energies from H to Na

Atomic Structure Ionisation Energy across Periods, downloadable AS & A Level Chemistry revision notes

There are ionisation energy trends within periods and groups

Ionisation energy across a period

  • The ionisation energy over a period increases due to the following factors:

    • Across a period the nuclear charge increases

    • This causes the atomic radius of the atoms to decrease, as the outer shell is pulled closer to the nucleus, so the distance between the nucleus and the outer electrons decreases

    • The shielding by inner shell electrons remain reasonably constant as electrons are being added to the same shell

    • It becomes harder to remove an electron as you move across a period; more energy is needed

    • So, the ionisation energy increases

  • There is a rapid decrease in ionisation energy between the last element in one period, and the first element in the next period because:

    • There is increased distance between the nucleus and the outer electrons as you have added a new shell

    • There is increased shielding by inner electrons because of the added shell

    • These two factors outweigh the increased nuclear charge

  • There is a slight decrease in IE1 between beryllium and boron as the fifth electron in boron is in the 2p subshell, which is further away from the nucleus than the 2s subshell of beryllium

    • Beryllium has a first ionisation energy of 900 kJ mol-1 as its electron configuration is 1s2 2s2

    • Boron has a first ionisation energy of 800 kJ mol-1 as its electron configuration is 1s2 2s2 2px1

  • Nitrogen has a first ionisation energy of 1400 kJ mol-1 as its electron configuration is 1s2 2s2 2px1 2py1 2pz1

  • Oxygen has a first ionisation energy of 1310 kJ mol-1 as its electron configuration is 1s2 2s2 2px2 2py1 2pz1There is a slight decrease in IE1 between nitrogen and oxygen due to spin-pair repulsion in the 2px orbital of oxygen

Ionisation energy down a group

  • The ionisation energy down a group decreases due to the following factors:

    • The number of protons in the atom is increased, so the nuclear charge increases

    • But, the atomic radius of the atoms increases as you add more shells of electrons, making the atoms bigger

    • So, the distance between the nucleus and outer electron increases as you descend the group

    • The shielding by inner shell electrons increases as there are more shells of electrons

    • These factors outweigh the increased nuclear charge, meaning it becomes easier to remove the outer electron as you descend a group

    • So, the ionisation energy decreases

Across a period: Ionisation energy increases

Down a group: Ionisation energy decreases

Increase in nuclear charge

Increase in nuclear charge

The same number of shells

Increased number of shells

Distance from the outer electron to the nucleus decreases

Distance from the outer electron to the nucleus increases

Shielding remains relatively constant

Shielding increases

Decreased atomic / ionic radius

Increased atomic / ionic radius

The attraction between the outer electron and the nucleus gets stronger so the outer electron is harder to remove

The attraction between the outer electron and the nucleus gets weaker so the outer electron is easier to remove

Successive Ionisation Energies of an Element

  • The successive ionisation energies of an element increase

  • This is because once you have removed the outer electron from an atom, you have formed a positive ion

  • Removing an electron from a positive ion is more difficult than from a neutral atom

  • As more electrons are removed, the attractive forces increase due to decreasing shielding and an increase in the proton to electron ratio

  • The increase in ionisation energy, however, is not constant and is dependent on the atom's electronic configuration

  • Taking calcium as an example:

Table Showing the Successive Ionisation Energies of Calcium Table

Electronic Configuration

1s2 2s2 2p6 3s2 3p6 4s1

1s2 2s2 2p6 3s2 3p6 

1s2 2s2 2p6 3s2 3p5

 1s2 2s2 2p6 3s2 3p4

IE

First

Second

Third

Fourth

IE (kJ mol-1)

590

1150

4940

6480

 

Successive ionisation energies of an element

1-1-atomic-structure-successive

The ionisation energy increases as you remove more electrons from an element

 

  • The first electron removed has a low IE1 as it is easily removed from the atom due to the spin-pair repulsion of the electrons in the 4s orbital

  • The second electron is more difficult to remove than the first electron as there is no spin-pair repulsion

  • The third electron is much more difficult to remove than the second one corresponding to the fact that the third electron is in a principal quantum shell which is closer to the nucleus (3p)

  • Removal of the fourth electron is more difficult as the orbital is no longer full, and there is less spin-pair repulsion

Examiner Tips and Tricks

  • It is easy to remove electrons from a full subshell as they undergo spin-pair repulsion.

  • It gets more difficult to remove electrons from principal quantum shells that get closer to the nucleus as there is less shielding and an increase in attractive forces between the electrons and nuclear charge.

You've read 0 of your 5 free revision notes this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?