Determining Electronic Configuration (Cambridge (CIE) AS Chemistry)
Revision Note
Determining Electronic Configurations
Writing out the electronic configuration tells us how the electrons in an atom or ion are arranged in their shells, sub-shells and orbitals
This can be done using the full electron configuration or the shorthand version
The full electron configuration describes the arrangement of all electrons from the 1s sub-shell up
The shorthand electron configuration includes using the symbol of the nearest preceding noble gas to account for however many electrons are in that noble gas
Ions are formed when atoms lose or gain electrons
Negative ions are formed by adding electrons to the outer sub-shell
Positive ions are formed by removing electrons from the outer sub-shell
The transition metals fill the 4s sub-shell before the 3d sub-shell but lose electrons from the 4s first and not from the 3d sub-shell
Remember: The 4s sub-shell is lower in energy
The Periodic Table is split up into four main blocks depending on their electronic configuration:
s block elements
Have their valence electron(s) in an s orbital
p block elements
Have their valence electron(s) in a p orbital
d block elements
Have their valence electron(s) in a d orbital
f block elements
Have their valence electron(s) in an f orbital
The blocks of the Periodic Table
The elements can be divided into the s, p, d or f block, according to their outer shell electron configuration
Exceptions
Chromium and copper have the following electron configurations, which are different to what you may expect:
Cr is [Ar] 4s1 3d5 not [Ar] 4s2 3d4
Cu is [Ar] 4s1 3d10 not [Ar] 4s2 3d9
This is because the [Ar] 4s1 3d5 and [Ar] 4s1 3d10 configurations are energetically stable
Worked Example
Write down the full and shorthand electron configuration of the following:
Potassium
Calcium
Gallium
Ca2+
Answer 1:
Potassium has 19 electrons so the full electronic configuration is:
1s2 2s2 2p6 3s2 3p6 4s1
The 4s orbital is lower in energy than the 3d subshell and is therefore filled first
The nearest preceding noble gas to potassium is argon which accounts for 18 electrons so the shorthand electron configuration is:
[Ar] 4s1
Answer 2:
Calcium has 20 electrons so the full electronic configuration is:
1s2 2s2 2p6 3s2 3p6 4s2
The 4s orbital is lower in energy than the 3d subshell and is therefore filled first
The nearest preceding noble gas to potassium is argon which accounts for 18 electrons so the shorthand electron configuration is:
[Ar] 4s2
Answer 3:
Gallium has 31 electrons so the full electronic configuration is:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
Again, the nearest preceding noble gas to potassium is argon which accounts for 18 electrons so the shorthand electron configuration is:
[Ar] 4s2 3d10 4p1
Answer 4:
If you ionise calcium and remove its two outer electrons, the electronic configuration of the Ca2+ ion is identical to that of argon.
So, the full electronic configuration is:
1s2 2s2 2p6 3s2 3p6
Since this is the electronic configuration of an argon atom, the shorthand electron configuration of Ca2+ is:
[Ar]
You've read 0 of your 5 free revision notes this week
Sign up now. It’s free!
Did this page help you?