Rotational Kinematics Equations (College Board AP® Physics 1: Algebra-Based)

Study Guide

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Rotational kinematics equations

  • Rotating systems in a state of constant angular acceleration can be described by three rotational kinematic equations

  • These are analogous to the linear kinematic equations

    • Each of the three rotational kinematics equations are listed on the equation sheet and will be provided in the exams

  • For all of these equations, the following conditions apply:

    • angular acceleration is constant

    • motion is relative to an axis of rotation

  • For all these equations:

    • Time interval, increment t space equals space t (i.e. the timer is assumed to start from zero, t subscript 0 space equals space 0)

    • Change in angular velocity, increment omega space equals space omega space minus space omega subscript 0

    • Angular displacement, increment theta space equals space theta space minus space theta subscript 0

Rotational kinematic equation 1

  • This equation is used when angular displacement is not required

omega space equals space omega subscript 0 space plus space alpha t

  • Where:

    • omega = final angular velocity, in rad divided by straight s

    • omega subscript 0 = initial angular velocity, in rad divided by straight s

    • alpha = angular acceleration, in rad divided by straight s squared

    • t = time interval, in straight s

Rotational kinematic equation 2

  • This equation is used when final angular velocity is not required

theta space equals space theta subscript 0 space plus space omega subscript 0 t space plus space 1 half alpha t squared

  • Where:

    • theta = final angular position, in rad

    • theta subscript 0 = initial angular position, in rad

    • omega subscript 0 = initial angular velocity, in rad divided by straight s

    • alpha = angular acceleration, in rad divided by straight s squared

    • t = time interval, measured in straight s

Rotational kinematic equation 3

  • This equation is used when time is not required

omega squared space equals space omega subscript 0 superscript 2 space plus space 2 alpha open parentheses theta space minus space theta subscript 0 close parentheses space

  • Where:

    • omega = final angular velocity, in rad divided by straight s

    • omega subscript 0 = initial angular velocity, in rad divided by straight s

    • alpha = angular acceleration, in rad divided by straight s squared

    • theta space minus space theta subscript 0 space equals space increment theta = angular displacement, in rad

Other helpful equations in rotational kinematics

  • Angular displacement can be calculated using angular velocity and time when angular acceleration is not required

increment theta space equals space 1 half open parentheses omega subscript 0 space plus space omega close parentheses t

  • Where:

    • increment theta = angular displacement, in rad

    • omega subscript 0 = initial angular velocity, in rad divided by straight s

    • omega = final angular velocity, in rad divided by straight s

    • t = time interval, in straight s

  • Final angular position can be calculated when initial angular velocity is not required using the following equation:

theta space equals space theta subscript 0 space plus space omega t space minus space 1 half alpha t squared

  • Where:

    • theta = final angular position, in rad

    • theta subscript 0 = initial angular position, in rad

    • omega = final angular velocity, in rad divided by straight s

    • alpha = angular acceleration, in rad divided by straight s squared

    • t = time interval, in straight s

Table of rotational kinematics equations

Linear equation

Rotational equation

Quantity not required

v subscript x space equals space v subscript x 0 end subscript space plus space a subscript x t

omega space equals space omega subscript 0 space plus space alpha t

increment theta

x space equals space x subscript 0 space plus space v subscript x 0 end subscript t space plus space 1 half a subscript x t squared

theta space equals space theta subscript 0 space plus space omega subscript 0 t space plus space 1 half alpha t squared

omega

v subscript x superscript 2 space equals space v subscript x 0 end subscript superscript 2 space plus space 2 a subscript x open parentheses x space minus space x subscript 0 close parentheses

omega squared space equals space omega subscript 0 superscript 2 space plus space 2 alpha open parentheses theta space minus space theta subscript 0 close parentheses space

t

increment x space equals space 1 half open parentheses v subscript x 0 end subscript space plus space v subscript x close parentheses t

increment theta space equals space 1 half open parentheses omega subscript 0 space plus space omega close parentheses t

alpha

x space equals space x subscript 0 space plus space v subscript x t space minus space 1 half a subscript x t squared

theta space equals space theta subscript 0 space plus space omega t space minus space 1 half alpha t squared

omega subscript 0

Worked Example

The turntable of a record player spins at an angular velocity of 45 space rpm just before it is turned off. Its rotation then decelerates at a rate of 0.8 space rad divided by straight s squared.

Determine the number of rotations the turntable completes before it comes to rest.

Answer:

Step 1: List the known quantities

  • Taking the initial direction of rotation as positive

  • Final angular velocity, omega space equals space 0

  • Initial angular velocity, omega subscript 0 space equals space 45 space rpm

  • Angular acceleration, alpha space equals space minus 0.8 space rad divided by straight s squared

Step 2: Convert the angular velocity from rpm to rad/s

  • One revolution corresponds to a rotation angle of 2 straight pi radians

  • Therefore, the initial angular velocity is:

omega subscript 0 space equals space 45 space rpm cross times fraction numerator 2 straight pi over denominator 60 end fraction space equals space fraction numerator 3 straight pi over denominator 2 end fraction space rad divided by straight s

Step 3: Choose the relevant rotational kinematic equation

  • The question asks for the number of rotations completed, which is equal to the ratio

fraction numerator angular space displacement space of space the space turntable over denominator angular space displacement space of space one space rotation end fraction

  • Therefore, the quantity we need to calculate is increment theta

  • The quantities we know are omega, omega subscript 0 and alpha

  • The quantity not required in this calculation is t

omega squared space equals space omega subscript 0 superscript 2 space plus space 2 alpha open parentheses theta space minus space theta subscript 0 close parentheses

Step 4: Rearrange the equation

0 space equals space omega subscript 0 superscript 2 space plus space 2 alpha open parentheses theta space minus space theta subscript 0 close parentheses

negative 2 alpha open parentheses theta space minus space theta subscript 0 close parentheses space equals space omega subscript 0 superscript 2

theta space minus space theta subscript 0 space equals space minus fraction numerator omega subscript 0 superscript 2 over denominator 2 alpha end fraction

  • Since angular displacement is increment theta space equals space theta space minus space theta subscript 0

increment theta space equals space minus fraction numerator omega subscript 0 superscript 2 over denominator 2 alpha end fraction

Step 5: Substitute the known values and calculate the angular displacement

increment theta space equals space minus fraction numerator open parentheses fraction numerator 3 straight pi over denominator 2 end fraction close parentheses squared over denominator 2 cross times open parentheses negative 0.8 close parentheses end fraction space equals space 13.88 space rad

Step 6: Determine the number of rotations completed

  • There are 2 straight pi radians in one rotation

  • Therefore, the number of rotations completed is

fraction numerator angular space displacement space of space the space turntable over denominator angular space displacement space of space one space rotation end fraction space equals space fraction numerator 13.88 over denominator 2 straight pi end fraction space equals space 2.2

  • This means the turntable spins 2.2 times before coming to rest

Last updated:

You've read 0 of your 5 free study guides this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.