Total Energy of SHM (College Board AP® Physics 1: Algebra-Based)
Study Guide
Written by: Dan Mitchell-Garnett
Reviewed by: Caroline Carroll
Total energy of SHM
Calculating total energy
Only two types of energy store are considered in SHM systems:
Kinetic energies
Potential energies
The total energy of the system is the sum of these energies:
Where:
is the total energy of the system, measured in
is the total potential energy of the system, measured in
is the total kinetic energy of the system, measured in
It is assumed that no work is done by resistive forces such as drag or friction
This means no energy enters or leaves the system
For a system showing SHM, total energy remains constant
Different systems
The potential energy in the system will differ for different systems
Horizontal object-spring system
When oscillations are horizontal, the gravitational potential is unchanged
The only changing potential energy is the elastic potential energy of the spring
This is a spring-object system, as only these two components need to be considered
Vertical object-spring-Earth system
If an object-spring system is oscillating vertically, the gravitational potential energy is changing, as well as the elastic potential energy
The system must therefore include the Earth too, as it provides the field in which gravitational potential energy varies
The potential energy then becomes the sum of elastic and gravitational potential energies
Elastic potential must be defined with displacement from the spring's natural length
Gravitational potential can be calculated with at any point, the total energy will remain constant
Worked Example
At a time of , a system in simple harmonic motion is at maximum displacement and has a potential energy of 350 J.
At a later time of , the same system has a kinetic energy of 230 J.
Determine the system's potential energy at and justify your answer.
Answer:
Step 1: Analyze the scenario
At , the system is at maximum displacement
At maximum displacement, the velocity of the system is zero
At , the potential energy of the system is 350 J
At , the position is unknown but kinetic energy is 230 J
Step 2: Consider the energy at
At , the velocity of the system is zero
This means that kinetic energy is also zero
Recall the equation for the total energy of the system:
The total energy of the system is 350 J
Step 3: Consider the energy at
Recall that the total energy of a system in SHM is constant
At , the kinetic energy of the system is 230 J
Substitute the kinetic energy at and the total energy from into the total energy equation:
The potential energy of the system at is therefore 120 J
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