Kinetic Energy & Potential Energy of SHM (College Board AP® Physics 1: Algebra-Based)

Study Guide

Dan Mitchell-Garnett

Written by: Dan Mitchell-Garnett

Reviewed by: Caroline Carroll

Kinetic energy & potential energy of SHM

Energy changes in SHM

Graph of potential and kinetic energies

Graph showing energy changes with axes labeled 'Energy' and 'x'. Total energy is constant. Potential energy decreases to zero then increases while kinetic energy increases from zero then decreases between positions -A and A.
The sum of kinetic and potential energy is always the same value in an ideal system in SHM.
  • Kinetic energy and potential energy vary throughout a cycle for a system displaying SHM

  • However, unlike displacement, velocity and acceleration, kinetic and potential energies only vary from zero to a maximum

    • Energy is a scalar quantity and cannot have negative values

  • Where potential energy is at a maximum, kinetic energy is zero

  • Where kinetic energy is at a maximum, potential energy is zero

Variation in kinetic energy

  • Recall that kinetic energy is proportional to velocity squared

  • At the amplitude positions:

    • Velocity is zero as the object changes direction

    • At these points, kinetic energy is zero

    • Kinetic energy cannot have a value lower than zero

  • At the equilibrium position travelling in the positive direction:

    • Velocity has a maximum positive value

    • Kinetic energy has a maximum positive value

  • At the equilibrium position travelling in the negative direction:

    • Velocity has a minimum negative value

    • Kinetic energy still has a maximum positive value, as squaring the velocity negates its negative sign

Variation in potential energy

  • Work done by the restoring force in the opposite direction to displacement goes into the potential store

    • When the magnitudes of the restoring force and displacement are greatest, the potential energy has a maximum value

  • At the equilibrium position:

    • Displacement from equilibrium is zero

    • No work is done against the restoring force

    • Potential energy of the system is zero

  • At the amplitude positions:

    • The magnitudes of displacement and the restoring force are both maximum

    • Potential energy has a maximum value

Potential and kinetic energies at different positions

Three diagrams labeled A, B, and C showing an object on a horizontal surface with a spring. A: spring is at equilibrium, KE = max, EPE = 0. B: spring is compressed KE = 0, EPE = max. C: spring is extended KE = 0, EPE = max.
A shows the system's equilibrium position. Here, kinetic energy is maximum. B and C show the amplitude positions. Here, potential energy is maximum.

Total energy

  • The total energy in SHM remains constant

  • At every value of displacement, the sum of potential and kinetic energies is constant

    • This means when potential energy is zero (at equilibrium), maximum kinetic energy is equal to the total energy

    • Similarly, when kinetic energy is zero (at amplitude),maximum potential energy is equal to the total energy

Amplitude and total energy

  • Increasing the amplitude of oscillations increases the total energy in the system

  • The potential store of the SHM system is filled when the object moves against the restoring force, doing work

    • If the amplitude of oscillations is increased, more work is done so the maximum potential energy also increases

  • If maximum potential energy increases, the total energy of the system increases

Total energy of an object-ideal spring system

  • Recall that the elastic potential energy stored in a spring is:

U subscript s space equals space 1 half k open parentheses straight capital delta x close parentheses squared

  • Where:

    • U subscript s = elastic potential energy stored in the spring, measured in straight J

    • k = spring constant measured in straight N divided by straight m

    • straight capital delta x = displacement, measured in straight m

  • When displacement is equal to amplitude, A, potential energy is at a maximum:

U subscript m a x end subscript space equals space 1 half k A squared

  • Maximum potential energy is equal to total energy of the system:

E subscript t o t end subscript space equals space 1 half k A squared

Worked Example

A vertical spring with a spring constant of 80 N/m is suspended from a pole. A 0.4 kg block is connected to its lower end.

If the block is pulled 0.3 m from its equilibrium position and is released, what is its maximum speed?

Answer:

Step 1: Analyze the system

  • This is an object-ideal spring system displaying simple harmonic motion

  • The block is displaced 0.3 m from its equilibrium position, this is the amplitude of oscillations

Step 2: Apply the specific conditions

  • The total energy of the system is the sum of kinetic and potential energies

E subscript t o t a l end subscript space equals space U space plus space K

  • The potential energy of this system is in the form of elastic potential energy

U space equals space 1 half k open parentheses straight capital delta x close parentheses squared

  • At the amplitude positions, kinetic energy is zero

    • When kinetic energy is zero, potential energy is at a maximum

E subscript t o t a l end subscript space equals space U subscript m a x end subscript space plus space 0

  • At equilibrium, potential energy is zero

    • When potential energy is zero, kinetic energy is at a maximum

E subscript t o t a l end subscript space equals space 0 space plus space K subscript m a x end subscript

Step 3: Consider the amplitude positions

  • At the amplitude positions, potential energy is equal to total energy

    • Displacement is equal to amplitude, A

E subscript t o t a l end subscript space equals space 1 half k A squared

Step 4: Substitute the known quantities

  • Spring constant is 80 N/m

  • Amplitude is 0.3 m

  • Total energy is therefore:

E subscript t o t a l end subscript space equals space 1 half space cross times space 80 space cross times space 0.3 squared

E subscript t o t a l end subscript space equals space 3.6 space straight J

Step 5: Consider the equilibrium position

  • At equilibrium, kinetic energy is equal to total energy

    • Velocity is at a maximum here:

E subscript t o t a l end subscript space equals space 1 half m v subscript m a x end subscript squared

Step 6: Rearrange for maximum velocity and substitute known quantities

  • Rearrange for v subscript m a x end subscript:

v subscript m a x end subscript space equals space square root of fraction numerator 2 E subscript t o t a l end subscript over denominator m end fraction end root

  • Mass is 0.4 kg

  • Total energy is 3.6 J

  • Substitute these values into the rearranged equation:

v subscript m a x end subscript space equals space square root of fraction numerator 2 space cross times space 3.6 over denominator 0.4 end fraction end root space equals space 4.2 space straight m divided by straight s

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Dan Mitchell-Garnett

Author: Dan Mitchell-Garnett

Expertise: Physics Content Creator

Dan graduated with a First-class Masters degree in Physics at Durham University, specialising in cell membrane biophysics. After being awarded an Institute of Physics Teacher Training Scholarship, Dan taught physics in secondary schools in the North of England before moving to Save My Exams. Here, he carries on his passion for writing challenging physics questions and helping young people learn to love physics.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.