Center of Mass (College Board AP® Physics 1: Algebra-Based)

Study Guide

Test yourself
Katie M

Author

Katie M

Expertise

Physics

Center of mass

  • The center of mass of a system is defined as:

The point where all of an object’s mass can be thought to be concentrated

  • When a system consists of a single object:

    • it can be modeled as a point particle that is located at the system's center of mass

    • all interactions can be considered to act at the system's center of mass

Diagram of a broom balanced on a pivot showing the center of mass, with the handle extending left and the bristles on the right.
The center of mass of a single object is the point where all of its mass is thought to act, as a result, it is the point the weight of the object acts.
  • When a system consists of multiple objects:

    • each object can be modeled as a point particle, with an associated mass and position which contributes to the system's center of mass

    • interactions between objects within a system (i.e. internal forces) do not influence the motion of a system’s center of mass

Examiner Tip

Remember, the center of mass is a hypothetical point, so it can lie inside or outside of a body. The center of mass of a non-rigid body can change depending on its shape. For example, a person’s center of mass is lower when learning forward than when standing upright

Diagram showing a person in three poses: standing, reaching up, and bending forward, with a label indicating the center of mass shifts.

Locating center of mass

  • For systems with symmetrical mass distributions, the center of mass is located on lines of symmetry

Center of mass of a symmetrical object

Four shapes with lines indicating the center of mass: triangle, oval, trapezoid, and parallelogram, each labeled "CENTRE OF MASS."
  • The location of a system’s center of mass along a given axis can be calculated using the equation:

x with rightwards arrow on top subscript c m end subscript space equals space fraction numerator sum for i of m subscript i x with rightwards arrow on top subscript i over denominator sum for i of m subscript i end fraction

  • Where:

    • x with rightwards arrow on top subscript c m end subscript = position of the system's center of mass, in straight m

    • m subscript i = mass of each object, in kg

    • x with rightwards arrow on top subscript i = position of each object, in straight m

Calculating the center of mass of a 1D system

  • Consider a system of three objects located along the same line

  • The position of the system's center of mass can be determined using:

x with rightwards arrow on top subscript c m end subscript space equals space fraction numerator m subscript 1 x subscript 1 plus m subscript 2 x subscript 2 plus m subscript 3 x subscript 3 over denominator m subscript 1 plus m subscript 2 plus m subscript 3 end fraction

Position of the center of mass on a line

Diagram showing three masses m1, m2, and m3 on a line with distances x1, x2, x3 from the origin. A triangle marks the center of mass.
The center of mass of a system of particles along the same line will be located somewhere along that line

Calculating the center of mass of a 2D system

  • Consider a system of three objects located along the same x-y plane

  • The position of the system's center of mass can be determined using:

r with rightwards arrow on top subscript c m end subscript space equals space fraction numerator sum for i of open parentheses m subscript i r with rightwards arrow on top subscript i close parentheses over denominator sum m subscript i end fraction space equals space fraction numerator m subscript 1 r with rightwards arrow on top subscript 1 plus m subscript 2 r with rightwards arrow on top subscript 2 plus m subscript 3 r with rightwards arrow on top subscript 3 over denominator m subscript 1 plus m subscript 2 plus m subscript 3 end fraction

  • Where:

    • r with rightwards arrow on top subscript c m end subscript = position vector of the system's center of mass, in straight m

    • r with rightwards arrow on top subscript i = position vector of each particle, in straight m

Position of the center of mass on an x-y plane

Diagram of a system of particles, showing masses m1, m2, and m3 in pink shapes. The center of mass is marked with vectors and coordinates.
A system of particles along the same x-y plane can be described in terms of the position of the system's center of mass
  • The positions of the separate x and y coordinates of the system's center of mass can be determined using:

x with rightwards arrow on top subscript c m end subscript space equals space fraction numerator m subscript 1 x subscript 1 plus m subscript 2 x subscript 2 plus m subscript 3 x subscript 3 over denominator m subscript 1 plus m subscript 2 plus m subscript 3 end fraction

y with rightwards arrow on top subscript c m end subscript space equals space fraction numerator m subscript 1 y subscript 1 plus m subscript 2 y subscript 2 plus m subscript 3 y subscript 3 over denominator m subscript 1 plus m subscript 2 plus m subscript 3 end fraction

  • Using Pythagoras' theorem, the magnitude of the position vector is:

r with rightwards arrow on top subscript c m end subscript space equals space square root of open parentheses x with rightwards arrow on top subscript c m end subscript close parentheses squared space plus space open parentheses y with rightwards arrow on top subscript c m end subscript close parentheses squared end root

  • Using trigonometry, the direction of the position vector can be found from:

tan space theta space equals space y with rightwards arrow on top subscript c m end subscript over x with rightwards arrow on top subscript c m end subscript

Examiner Tip

In AP Physics 1, you will only be expected to calculate the center of mass for systems of five or fewer particles arranged in a two-dimensional configuration or for highly symmetrical systems

You've read 0 of your 10 free study guides

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.