Uniform Circular Motion (College Board AP® Physics 1: Algebra-Based)

Study Guide

Ann Howell

Written by: Ann Howell

Reviewed by: Caroline Carroll

Period and frequency of uniform circular motion

  • An object traveling in a circular path at a constant linear speed is traveling in uniform circular motion

    • The revolution of an object traveling in a circular path at a constant linear speed can be described using period and frequency

  • The time to complete one full circular path, one full rotation, or a full cycle of oscillatory motion is defined as period, T

  • The rate at which an object is completing revolutions is defined as frequency, f

  • The equation linking period and frequency is:

T space equals space 1 over f

  • Where:

    • T = period, measured in straight s

    • f = frequency, measured in Hz

  • For an object traveling at a constant linear speed, v, in a circular path, the period is given by the equation

T space equals space fraction numerator 2 pi r over denominator v end fraction

  • Where:

    • T = period, measured in straight s

    • r = radius, measured in straight m

    • v = object's linear speed, measured in straight m divided by straight s

  • The linear speed is tangential to the circle of motion

    • Linear speed always acts at right angles to the radius of the circle

Linear speed and radius in uniform circular motion

Diagram illustrating uniform circular motion, showing constant linear speed 'v' at different positions around the circle, with radius 'r' and circumference formula 2πr.
An object rotating in uniform circular motion completes one revolution of the circumference of the circle in period T

Derived equation

  • For an object traveling at a constant linear speed, v, in a circular path, the period is given by the equation

T space equals space fraction numerator 2 straight pi straight r over denominator v end fraction

Derivation:

Step 1: Identify the fundamental principle

  • The equation linking period and frequency is given by

T space equals space 1 over f

  • Where:

    • T = period, measured in straight s

    • f = frequency, measured in Hz

Step 2: Apply the specific conditions

  • The frequency of an oscillation dictates the number of oscillations in a certain time period

  • The equation linking period and frequency means there is one oscillation in period T

  • In circular motion, one oscillation covers the distance of the circumference of the circle

    • The circumference of a circle of radius, r, is given by the equation

circumference space of space circle space equals space 2 pi r

  • Average speed is calculated using the equation

average space speed space equals space fraction numerator total space distance space traveled over denominator total space time space taken end fraction

  • So the linear speed, v, is given by the equation

v equals space fraction numerator 2 straight pi straight r over denominator T end fraction

  • Where

    • linear speed, v, is equivalent to average speed, measured in straight m divided by straight s

    • the circumference of a circle is equivalent to total distance traveled, measured in straight m

    • period is equivalent to total time taken, measured in straight s

  • Rearrange to make period, T, the subject

    • Multiply both sides by T

    v space times space T space equals space fraction numerator 2 straight pi straight r over denominator T end fraction space times space T

    • Cancel out the common T's

    v space times space T space equals space fraction numerator 2 straight pi straight r over denominator up diagonal strike T end fraction space times space up diagonal strike T

    • Divide by v on both sides

    fraction numerator v space times space T over denominator v end fraction space equals space fraction numerator 2 straight pi straight r over denominator v end fraction

    • Cancel out the common v's

    fraction numerator up diagonal strike v space times space T over denominator up diagonal strike v end fraction space equals space fraction numerator 2 straight pi straight r over denominator v end fraction

    • Obtain the derived equation for period, T

T space equals space fraction numerator 2 straight pi straight r over denominator v end fraction

Worked Example

The London Eye is a giant Ferris wheel in the city of London that was built as part of the millennium celebrations it rotates slow enough so people on board can observe what is happening in the city below. The radius of the London Eye is 67.5 m and it takes 30 minutes to complete one full rotation.

Which of the following is the linear speed of the London Eye?

A      0.24 space straight m divided by straight s

B      0.47 space straight m divided by straight s

C      14.13 space straight m divided by straight s

D      848 space straight m divided by straight s

The correct answer is A

Answer:

Step 1: List the known quantities

  • Radius of London Eye, r space equals space 67.5 space straight m

  • Period of rotation, T space equals space 30 space minutes space equals space 30 space times space 60 space equals space 1800 space straight s

Step 2: Substitute the known quantities into the equation for linear speed

v equals space fraction numerator 2 straight pi straight r over denominator T end fraction

v equals space fraction numerator 2 pi open parentheses 67.5 close parentheses over denominator 1800 end fraction

v space equals space 0.24 space straight m divided by straight s

  • The answer is therefore A

Examiner Tips and Tricks

An object in uniform circular motion travels at a constant linear speed but at a changing linear velocity, v with rightwards arrow on top. This is because the direction of motion is constantly changing.

Last updated:

You've read 0 of your 5 free study guides this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Ann Howell

Author: Ann Howell

Expertise: Physics Content Creator

Ann obtained her Maths and Physics degree from the University of Bath before completing her PGCE in Science and Maths teaching. She spent ten years teaching Maths and Physics to wonderful students from all around the world whilst living in China, Ethiopia and Nepal. Now based in beautiful Devon she is thrilled to be creating awesome Physics resources to make Physics more accessible and understandable for all students, no matter their schooling or background.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.