Areas between Two Polar Curves (College Board AP® Calculus BC)

Study Guide

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Updated on

Areas between two polar curves

How do I find an area between two polar curves?

  • To find an area between two polar curves, r equals f open parentheses theta close parentheses and r equals g open parentheses theta close parentheses:

    • Sketch the two curves

    • Find the angle(s) of intersection, theta equals alpha

      • by solving f open parentheses theta close parentheses equals g open parentheses theta close parentheses

    • Draw a ray in the direction of theta equals alpha on your diagram

      • This is a straight line from the pole to the point of intersection

    • Split the area into either a sum or difference of two polar areas, for example:

      • Region R shown below is a sum

      • Region S shown below is difference

    • Use the area formula A equals integral subscript theta subscript 1 end subscript superscript theta subscript 2 space end subscript end superscript 1 half r squared space d theta to find each area

7-1-2-edexcel-al-fm-polar-multiple-areas

Examiner Tips and Tricks

If one of the polar areas is part of a circle, e.g. the circle r equals a, then it can be quicker to use the formula for the area of a circle,pi a squared.

Worked Example

A sketch of the polar curves r equals 1 plus cos space theta and r equals 3 space cos space theta where 0 less or equal than theta less or equal than pi over 2 is shown below.

The shaded region is labeled R subscript 1 and an unshaded region is labeled R subscript 2.

Graph showing two intersecting curves on axes, creating regions R1 and R2. Region R1 is shaded grey.

(a) Find the area of R subscript 1, leaving your answer as a single integral.

When theta equals 0, r equals 3 space cos space theta is 3 and r equals 1 plus cos space theta is 2, so r equals 3 space cos space theta is the larger curve

Find the angle at which the two curves intersect by setting 1 plus cos space theta equal to 3 space cos space theta and solving

table row cell 1 plus cos space theta end cell equals cell 3 space cos space theta end cell row 1 equals cell 2 space cos space theta end cell row cell 1 half end cell equals cell cos space theta end cell row theta equals cell pi over 3 end cell end table

Draw the ray theta equals pi over 3 on the diagram to see how to form the area R subscript 1

It is the difference between the two polar areas shown below

Two graphs showing a larger polar area from one curve on the left and a smaller polar area from the other curve on the right.

Use the formula A equals integral subscript theta subscript 1 end subscript superscript theta subscript 2 space end subscript end superscript 1 half r squared space d theta to work out the two individual areas, then subtract the smaller area from the larger area

integral subscript 0 superscript fraction numerator pi space over denominator 3 end fraction end superscript 1 half open parentheses 3 space cos space theta close parentheses squared space d theta minus integral subscript 0 superscript fraction numerator pi space over denominator 3 end fraction end superscript 1 half open parentheses 1 plus cos space theta close parentheses squared space d theta

The limits of the integrals are the same, so the integrals can be joined to form one single integral (as requested by the question)

integral subscript 0 superscript fraction numerator pi space over denominator 3 end fraction end superscript 1 half open square brackets open parentheses 3 space cos space theta close parentheses squared space minus open parentheses 1 plus cos space theta close parentheses squared close square brackets space d theta

(b) Find the area of R subscript 2.

R subscript 2 is the sum of the two polar areas shown below

r equals 1 plus cos space theta gives the part of the area from theta equals 0 to the point of intersection

r equals 3 space cos space theta gives the part of the area from the point of intersection to theta equals pi over 2 (where r equals 0), which is the end of the range given in the question

Two graphs, where the one on the left shows a polar region enclosed by one of the graphs and the one on the right shows a different polar region, which, when added to the first, gives the total area required.

Use the formula A equals integral subscript theta subscript 1 end subscript superscript theta subscript 2 space end subscript end superscript 1 half r squared space d theta to work out the two individual areas, then add them together

integral subscript 0 superscript fraction numerator pi space over denominator 3 end fraction end superscript 1 half open parentheses 1 plus cos space theta close parentheses squared space d theta plus integral subscript pi over 3 end subscript superscript fraction numerator pi space over denominator 2 end fraction end superscript 1 half open parentheses 3 space cos space theta close parentheses squared space d theta

Evaluate the integrals above on your calculator

1.759676... plus 0.203818...

1.963

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.