Arc Lengths of Parametric Equations (College Board AP® Calculus BC): Study Guide
Arc lengths of parametric equations
How do I find the arc length of a curve given parametrically?

The formula to find the length of the curve (the arc length),
units, from the point at
to the point at
on the parametric curve
and
is
Examiner Tips and Tricks
Questions on parametric arc lengths may ask you to leave your answer as a definite integral.
Worked Example
(a) Find the length of the curve and
from
to
.
Use the formula
It helps to find and
individually
Substitute these derivatives, and the limits and
, into the formula
If calculators are allowed, evaluate this definite integral on your calculator
If calculators are not allowed, continue by simplifying under the square root and taking out a 9
There are many ways to evaluate this definite integral, for example integration by substitution using
Note that so
and that
,
The length of the curve is 52 units
(b) Show that the length of the curve and
from
to
can be written as
In this question, you do not need to evaluate the definite integral
Start by finding and
individually
Substitute these derivatives, and the limits and
, into the formula
This is not how it is given in the question, so expand and simplify under the square root
Here, you can use the trigonometric identity to simplify further
This is almost the answer given, but a 2 must be factored out from inside the square root
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