Absolute & Conditional Convergence (College Board AP® Calculus BC)

Study Guide

Roger B

Written by: Roger B

Reviewed by: Mark Curtis

Updated on

Absolute & conditional convergence

What is absolute convergence?

  • Let sum from n equals 1 to infinity of a subscript n be an infinite series

    • If sum from n equals 1 to infinity of open vertical bar a subscript n close vertical bar, converges, then sum from n equals 1 to infinity of a subscript n is said to converge absolutely

    • I.e. a series is absolutely convergent if the corresponding series of absolute values converges

  • If a series converges absolutely then it converges

    • I.e. if you know that sum from n equals 1 to infinity of open vertical bar a subscript n close vertical bar converges, that tells you that sum from n equals 1 to infinity of a subscript n converges as well

      • There is no need to test sum from n equals 1 to infinity of a subscript n separately for convergence

What is conditional convergence?

  • Let sum from n equals 1 to infinity of b subscript n be an alternating series (i.e. with alternating positive and negative terms)

    • If sum from n equals 1 to infinity of b subscript n converges, but sum from n equals 1 to infinity of open vertical bar b subscript n close vertical bar does not converge, then sum from n equals 1 to infinity of b subscript n is said to converge conditionally

    • I.e. a series is conditionally convergent if the series itself converges, but the corresponding series of absolute values does not

  • Note that if sum from n equals 1 to infinity of open vertical bar b subscript n close vertical bar does not converge, that doesn't tell you anything about the convergence of sum from n equals 1 to infinity of b subscript n

    • I.e., sum from n equals 1 to infinity of b subscript n may converge or diverge, and needs to be tested separately

Why is the difference between absolute and conditional convergence important?

  • If a series converges absolutely, then any series obtained from it by regrouping or rearranging the terms in the series has the same value

  • This is probably what you are used to when adding numbers

    • I.e. rearranging the order or regrouping (by adding or removing brackets) doesn't change the sum

    • But this is only true when adding together finitely many numbers

      • It is not necessarily true for an infinite series!

  • For example the series 1 minus 1 plus 1 half minus 1 half plus 1 third minus 1 third plus 1 fourth minus 1 fourth plus...

    • This converges to a sum of 0, as can be seen by writing it as

      equals open parentheses 1 minus 1 close parentheses plus open parentheses 1 half minus 1 half close parentheses plus open parentheses 1 third minus 1 third close parentheses plus open parentheses 1 fourth minus 1 fourth close parentheses plus...
equals 0 plus 0 plus 0 plus 0 plus...
equals 0

    • It is conditionally convergent because the sum of absolute values gives

      equals open vertical bar 1 close vertical bar plus open vertical bar negative 1 close vertical bar plus open vertical bar 1 half close vertical bar plus open vertical bar negative 1 half close vertical bar plus open vertical bar 1 third close vertical bar plus open vertical bar negative 1 third close vertical bar plus open vertical bar 1 fourth close vertical bar plus open vertical bar negative 1 fourth close vertical bar plus...
equals 1 plus 1 plus 1 half plus 1 half plus 1 third plus 1 third plus 1 fourth plus 1 fourth plus...
equals 2 open parentheses 1 plus 1 half plus 1 third plus 1 fourth... close parentheses
rightwards arrow plus infinity

      • That is 2 times the harmonic series, which we know diverges to plus infinity

    • However the original series can be rearranged and regrouped to give a different sum

      equals 1 plus 1 half minus 1 plus 1 third plus 1 fourth minus 1 half plus 1 fifth plus 1 over 6 minus 1 third plus...
equals 1 plus open parentheses 1 half minus 1 close parentheses plus 1 third plus open parentheses 1 fourth minus 1 half close parentheses plus 1 fifth plus open parentheses 1 over 6 minus 1 third close parentheses plus...
equals 1 minus 1 half plus 1 third minus 1 fourth plus 1 fifth minus 1 over 6 plus...

      • With that rearrangement it is equal to the alternating harmonic series, which converges to a sum of ln 2

      • This appears to contradict it converging to 0 above

  • Conditionally convergent series can be regrouped and/or rearranged to give

    • a series with a different sum

    • or a series which does not converge to any sum

Worked Example

(a) The alternating harmonic series sum from n equals 1 to infinity of open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n equals 1 minus 1 half plus 1 third minus 1 fourth plus... converges to a value of ln 2. Determine whether the series is absolutely convergent or conditionally convergent.

Consider the series of absolute values

sum from n equals 1 to infinity of open vertical bar open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n close vertical bar equals sum from n equals 1 to infinity of 1 over n equals 1 plus 1 half plus 1 third plus 1 fourth plus...

That is the harmonic series, which diverges

The sequence of absolute values is the
harmonic series, which is divergent

So the alternating harmonic series is conditionally convergent

The series converges, but its sequence of absolute values diverges. Therefore it is conditionally convergent.

(b) Determine whether the series sum from n equals 1 to infinity of open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n squared is absolutely convergent, conditionally convergent, or divergent.

Start by considering the series of absolute values

sum from n equals 1 to infinity of open vertical bar open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n squared close vertical bar equals sum from n equals 1 to infinity of 1 over n squared

sum from n equals 1 to infinity of 1 over n squared is a convergent p-series with n equals 2 greater than 1

The sequence of absolute values is a
convergent p-series, with n equals 2

That means the series is absolutely convergent

sum from n equals 1 to infinity of open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n squared therefore automatically converges as well; because it is absolutely convergent there is no need to test it separately for convergence

Therefore sum from n equals 1 to infinity of open parentheses negative 1 close parentheses to the power of n plus 1 end exponent over n squared is absolutely convergent

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Roger B

Author: Roger B

Expertise: Maths

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.