Selecting Techniques for Integration (College Board AP® Calculus AB)

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Roger B

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Roger B

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Maths

Selecting techniques for integration

How do I choose the correct procedure for integrating?

  • You should be familiar with all the different methods for working out indefinite or definite integrals

    • This way you can choose the most appropriate method to use for an exam question

  • The simplest way to integrate is to use antiderivatives

    • If you recognise a function being integrated as the derivative of a standard function

      • Then use the fact that differentiation and integration are inverse operations

      • E.g. fraction numerator d over denominator d x end fraction open parentheses sin x close parentheses equals cos x

        • therefore integral cos x space d x equals sin x plus C

    • See the 'Derivatives & Antiderivatives' study guide

  • More complicated integrals can be solved by

    • using standard results for sums, differences and constant multiples of integrals

      • integral open parentheses p f open parentheses x close parentheses plus-or-minus q g open parentheses x close parentheses close parentheses space d x equals p integral f open parentheses x close parentheses space d x plus-or-minus q integral g open parentheses x close parentheses space d x

    • simplifying functions to make them easier to integrate

      • E.g. space open parentheses x squared plus 2 close parentheses squared equals x to the power of 4 plus 4 x squared plus 4

      • or space fraction numerator 5 x cubed minus 3 over denominator x squared end fraction equals 5 x minus 3 x to the power of negative 2 end exponent

    • See the 'Indefinite Integral Rules' study guide

  • Integrals involving composite functions can sometimes be solved by inspection (sometimes known as the 'reverse chain rule')

    • E.g. fraction numerator d over denominator d x end fraction open parentheses sin open parentheses x squared minus 5 x plus 4 close parentheses close parentheses equals open parentheses 2 x minus 5 close parentheses cos open parentheses x squared minus 5 x plus 4 close parentheses, by the chain rule

      • therefore integral open parentheses 2 x minus 5 close parentheses cos open parentheses x squared minus 5 x plus 4 close parentheses space d x equals sin open parentheses x squared minus 5 x plus 4 close parentheses plus C

    • See the 'Integrals of Composite Functions' study guide

  • Even trickier integrals can sometimes be solved by using u-substitution

    • E.g. by using the substitution u equals x minus 4

      • it can be shown that integral x square root of x minus 4 end root space d x equals 2 over 5 open parentheses x minus 4 close parentheses to the power of 5 over 2 end exponent plus 8 over 3 open parentheses x minus 4 close parentheses to the power of 3 over 2 end exponent plus C

    • u-substitution is also very effective for evaluating definite integrals

    • See the 'Integration Using Substitution' study guide

  • Some integrals can be solved by using completing the square

    • These integrals will usually involve variations of the standard results

      • integral fraction numerator 1 over denominator square root of 1 minus x squared end root end fraction space d x equals arcsin x plus C comma space space minus 1 less than x less than 1

      • or integral fraction numerator 1 over denominator 1 plus x squared end fraction space d x equals arc tan x plus C

    • E.g. integral fraction numerator 1 over denominator x squared minus 6 x plus 13 end fraction space d x can be integrated

      • by first completing the square on the denominator to get fraction numerator 1 over denominator x squared minus 6 x plus 13 end fraction equals fraction numerator 1 over denominator 4 plus open parentheses x minus 3 close parentheses squared end fraction equals 1 fourth times fraction numerator 1 over denominator 1 plus open parentheses fraction numerator x minus 3 over denominator 2 end fraction close parentheses squared end fraction

    • See the 'Integration Using Completing the Square' study guide

  • Some integrals can be simplified by using polynomial long division

    • E.g. space fraction numerator x cubed plus 6 x squared minus 9 x minus 11 over denominator x minus 2 end fraction can be written as space x squared plus 8 x plus 7 plus fraction numerator 3 over denominator x minus 2 end fraction

      • which is much easier to integrate

    • See the 'Integration Using Long Division' study guide

  • The value of a definite integral can be found

    • by using the result integral subscript a superscript b f open parentheses x close parentheses space d x equals F open parentheses b close parentheses minus F open parentheses a close parentheses, where F is an antiderivative of f

      • See the 'Evaluating Definite Integrals' study guide

    • or sometimes by using basic geometric area formulas

      • See the 'Accumulation of Change' study guide

    • or by using the properties of definite integrals

      • See the 'Properties of Definite Integrals' study guide

What else do I need to know about integration?

  • Be sure that you are able to work out the value of a constant of integration

    • See the 'Constant of Integration' and 'Particular Solutions' study guides

  • You should be able to approximate the value of a definite integral using Riemann sums and trapezoidal sums

    • See the 'Riemann Sums' and 'Trapezoidal Sum' study guides

  • Finally, be sure that you are familiar with the background theory of integration

    • For example

      • Accumulation of change and accumulation functions

      • Definite integrals as a limit of Riemann sums

      • The fundamental theorem of calculus

    • You may need to recognize the ideas and notation from these areas to answer exam questions on integration

    • See the study guides in the 'Riemann Sums & Definite Integrals' topic

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Roger B

Author: Roger B

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.