Motion in a Straight Line (College Board AP® Calculus AB)

Study Guide

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Introduction to straight line motion

What is straight line motion?

  • Straight line motion models how objects move in a straight line, with respect to time

    • This may be described as motion 'along the bold italic x-axis'

    • The straight line will have a positive and a negative direction

      • On the x-axis this will be the usual positive and negative directions

      • If the question doesn't specify, you can choose the positive and negative directions

      • (Just be consistent once you've made a choice!)

What terminology do I need to be aware of?

  • Particle

    • A particle is the general term used for an object

    • A particle is assumed to be the 'size' of a single point

      • So you don't need to worry about its 3D dimensions

  • Time space t 

    • Time is usually measured in seconds (straight s)

    • Displacement, velocity and acceleration are all functions of timespace t

    • 'Initial' or 'Initially' means 'when t equals 0'

  • Displacement space s

    • s is the usual notation for displacement

      • For motion along the bold italic x-axisx may be used instead of s

    • Displacement is usually measured in feet (ft) or meters (straight m)

      • Sometimes questions may not state a particular unit, and will simply use "units"

    • The displacement of a particle is its distance relative to a fixed point

      • The fixed point may be (but is not always) the particle’s initial position

    • Displacement will be zero, s equals 0, when the object is at the fixed point

    • Otherwise the displacement will be

      • positive if the particle is in the positive direction from the fixed point

      • or negative if it is in the negative direction from the fixed point

  • Distance space d

    • Distance is the magnitude of displacement

    • Use of the word distance could refer to

      • the distance traveled by a particle

      • the (straight line) distance the particle is from a particular point

    • Be careful not to confuse displacement with distance

      • Consider a bus starting and ending its journey at a bus depot,

      • its displacement will be zero when it returns to the depot

      • but the distance the bus has travelled will be the length of the route

    • Distance is always positive (or zero)

  • Velocity space v

    • Velocity is usually measured in feet or meters per second

    • The velocity of a particle is the rate of change of its displacement at timespace t

      • Velocity will be positive if the particle is moving in the positive direction

      • Or negative if it is moving in the negative direction

    • If the particle is stationary, that means the velocity is zerov equals 0

      • '(Instantaneously) at rest' also means that v equals 0

  • Speed

    • Speed is the magnitude (i.e. absolute value or modulus) of the velocity

    • For a particle moving in a straight line

      • speed is the 'velocity ignoring the direction'

      • ifspace v equals 4,  speed equals open vertical bar 4 close vertical bar equals 4

      • if v equals negative 6,  speed = open vertical bar negative 6 close vertical bar equals 6

  • Acceleration space a

    • Acceleration is usually measured in feet or meters per second squared

      • That is the same as feet or meters per second per second

    • The acceleration of a particle is the rate of change of its velocity at timespace t

    • Acceleration can be positive or negative

      • but the sign alone cannot fully describe the particle’s motion

    • If velocity and acceleration have the same sign

      • then the particle is accelerating (speeding up)

    • if velocity and acceleration have different signs

      • then the particle is decelerating (slowing down)

    • At times when the acceleration is zero, a equals 0,

      • the particle is moving with constant velocity 

    • In all cases the direction of motion is determined by the sign (+ or -) of the velocity

    • There is no special term for the magnitude of acceleration

      • "The magnitude of the acceleration" is simply used instead

Velocity & acceleration as derivatives

What is velocity as a derivative?

  • Velocity is the rate of change of displacement

    • v equals fraction numerator d s over denominator d t end fraction 

    • (differentiate displacement to get velocity)

  • Velocity is the slope of a displacement-time graph

What is acceleration as a derivative?

  • Acceleration is the rate of change of velocity

    • a equals fraction numerator d v over denominator d t end fraction 

    • (differentiate velocity to get acceleration)

  • Acceleration is the slope of a velocity-time graph

  • This means that acceleration is also the rate of change, of the rate of change of displacement

    • a equals fraction numerator d squared s over denominator d t squared end fraction

    • (differentiate displacement twice to get acceleration)

Worked Example

The displacement from the origin of a particle, P, as it travels along the x-axis is given by s subscript P equals 3 sin open parentheses 1 half t close parentheses.

The displacement from the origin of a second particle, Q, as it travels along the x-axis is given by s subscript Q equals 1 over 8 t cubed minus 7 over 4 t squared plus 5 t.

s subscript P and s subscript Q are measured in meters and t is measured in seconds for 0 less or equal than t less or equal than 10.

(a) Determine which particle is furthest from the origin at t equals 5.

Answer:

Find the displacement of each particle at t equals 5

s subscript P equals 3 sin open parentheses 1 half times 5 close parentheses equals 1.795416... meters

s subscript Q equals 1 over 8 open parentheses 5 close parentheses cubed minus 7 over 4 open parentheses 5 close parentheses squared plus 5 open parentheses 5 close parentheses equals negative 3.125 meters

P is 1.795... meters away from the origin in the positive direction, while Q is 3.125 meters away from the origin in the negative direction

At t equals 5 particle Q is the furthest from the origin.

(b) At t equals 5, determine if the particles are moving closer together, or further apart. Explain your reasoning in your working.

Answer:

This question is about the direction of motion, so we need to find the velocity

Find expressions for the velocities by differentiating the expressions for the displacements

v subscript P equals fraction numerator d s subscript P over denominator d t end fraction equals 3 over 2 cos open parentheses 1 half t close parentheses

v subscript Q equals fraction numerator d s subscript Q over denominator d t end fraction equals 3 over 8 t squared minus 7 over 2 t plus 5

Find the velocities when t equals 5

v subscript P equals 3 over 2 cos open parentheses 1 half times 5 close parentheses equals negative 1.201715... meters per second

v subscript Q equals 3 over 8 open parentheses 5 close parentheses squared minus 7 over 2 open parentheses 5 close parentheses plus 5 equals negative 3.125 meters per second

Consider the positions and velocities of the two particles

P is on the positive side (right) of the x axis (1.795... meters), moving with a negative velocity, so back towards the origin (moving to the left)

Q is on the negative side (left) of the x axis (-3.125... meters), moving with a negative velocity, so further away from the origin (moving to the left)

leftwards arrow with 3.125 on top leftwards arrow with 1.2017 on top
space space space space circle enclose Q space space space space space space space space circle enclose P

So both particles are moving to the left (negative x direction) but Q is moving faster, and its position is further to the left, so Q is "escaping" from P

Therefore at t equals 5, the particles are moving further apart

(c) At t equals 5, determine which particle has the greatest magnitude of acceleration.

Answer:

Find expressions for the accelerations by differentiating the expressions for the velocities

a subscript P equals fraction numerator d v subscript P over denominator d t end fraction equals negative 3 over 4 sin open parentheses 1 half t close parentheses

a subscript Q equals fraction numerator d v subscript Q over denominator d t end fraction equals 3 over 4 t minus 7 over 2

Find the acceleration of each when t equals 5

a subscript P equals negative 3 over 4 sin open parentheses 1 half times 5 close parentheses equals negative 0.448854... meters per second squared

a subscript Q equals 3 over 4 open parentheses 5 close parentheses minus 7 over 2 equals 0.25 meters per second squared

Whilst the acceleration of Q is the largest (as it is positive whereas P's is negative), it is P whose acceleration has the greatest absolute value (magnitude)

At t equals 5, particle P has the greatest magnitude of acceleration.

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Jamie Wood

Author: Jamie Wood

Expertise: Maths

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.