Coupled Reactions (College Board AP® Chemistry)
Study Guide
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
Making Thermodynamically Unfavorable Processes Occur
A thermodynamically unfavorable reaction is one that does not occur spontaneously
It needs the additional input of energy after the reactants are mixed together
It will have a positive ΔG° value.
We can make a thermodynamically unfavorable reaction favorable by:
Applying external energy sources
Coupling it with a thermodynamically favorable reaction that shares an intermediate
Examples of applying external energy include:
Electrical energy being used to drive an electrolytic cell
Light driving the overall conversion of carbon dioxide to glucose in photosynthesis
Coupling Reactions
We can make a thermodynamically unfavorable reaction favorable by coupling it to a favorable reaction via an intermediate
The sum of the two reactions will result in a reaction that overall has a negative ΔG° value.
For example:
The decomposition of copper(I) sulfide to produce copper as the desired product and sulfur is thermodynamically unfavorable
Cu2S (s) 2Cu (s) + S (s) ΔG° = +85.1 kJ mol-1 K < 1
The equilibrium constant is less than 1 which means there are more reactants than products at equilibrium so not much copper would be produced
This reaction can be coupled to a thermodynamically favorable reaction such as the reaction between sulfur and oxygen to give sulfur dioxide
S (s) + O2 (g) SO2 (g) ΔG° = –301.4 kJ mol-1 K > 1
At equilibrium, the equilibrium constant is greater than 1 so there will be more products than reactants
Coupling these two reactions will allow us to make a significant amount of copper because they share the common intermediate, sulfur
Even if only a small amount, sulfur will still be produced in reaction 1 when copper(I) sulfide decomposes
This will then be used up in reaction 2 by reacting with oxygen to produce sulfur dioxide
Removing the sulfur from reaction 1 causes the equilibrium to shift to the right therefore producing more copper
The thermodynamically favorable second reaction is driving the thermodynamically unfavorable reaction
Adding the two reactions together, the sulfur will cancel out to give:
Cu2S (s) + O2 (g) 2Cu (s) + SO2 (g)
Adding the two ΔG°values together:
+85.1 +(-301.4) = –216.3 kJmol-1
A negative value shows now this overall reaction is thermodynamically favorable
It will have an equilibrium constant of above 1
Copper will be produced
Coupling reactions are also used in the conversion of ATP to ADP in the body which helps drive protein synthesis
Amino acids alanine and glycine will produce alanylglycine (a dipeptide) and water:
alanine + glycine alanylglycine + H2O ΔG° = +31 kJ mol-1
This is thermodynamically unfavorable due to the positive ΔG°
The hydrolysis of ATP is thermodynamically favorable:
ATP + H2O ADP + Pi ΔG° = –33 kJmol-1
The reactions are coupled
The water cancels out to give:
alanine + glycine + ATP alanylglycine + ADP + Pi
Adding the two ΔG° values together gives an overall ΔG° = –2 kJ mol-1
The reaction is now thermodynamically favored
Worked Example
Calculate ΔG° for the following reaction:
Fe2O3 + 3CO → 2Fe + 3CO2
Fe2O3 → 2Fe + 1.5O2 (ΔG° = 742.2 kJ mol-1)
CO + 0.5O2 → CO2 (ΔG° = –283.5 kJ mol-1)
Answer:
The common intermediate is oxygen
To deduce the overall equation, the second equation needs multiplying by three as does the value of ΔG°
–293.5 x 3 = –850.5 kJ mol-1
ΔG° for the reaction = 742.2 + (-850.5) = –108.3 kJ mol-1
Examiner Tips and Tricks
Remember: Coupling reactions involve a thermodynamically favorable reaction driving an unfavorable one.
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