Introduction to Entropy (College Board AP® Chemistry)

Study Guide

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Alexandra Brennan

Expertise

Chemistry

Entropy & Phase Changes

  • Entropy (S) in a system reflects the variety of ways particles and their energy can be arranged

    • It is a measure of the system's disorder or randomness

  • When a system becomes more disordered, its entropy goes up

    • This rise in entropy signals increased energetic stability

  • Take the thermal decomposition of calcium carbonate (CaCO3) as an example:

CaCO3(s) → CaO(s) + CO2(g)

  • The creation of a gas molecule (CO2) adds disorder to the system

  • The production of two product molecules compared to one reactant molecule adds disorder to teh system

  • The constant movement of CO2 molecules makes them more disordered than the original solid (CaCO3)

  • This results in a higher overall entropy

  • Consider another example: when a solid transitions to a liquid, like the melting of ice:

H2O(s) → H2O(l)

  • In the solid state, water molecules in ice are fixed in position with limited movement

  • In the liquid state, these particles are more randomly arranged, allowing for freer motion

  • As a result, the liquid state is more disordered, leading to an increase in entropy compared to the solid state

  • In both cases, systems with higher entropy are energetically preferred because a disordered state allows for a more evenly spread distribution of energy

Increasing entropy in a system

Entropy change, downloadable AS & A Level Chemistry revision notes

Melting a solid will cause the particles to become more disordered resulting in a higher entropy state

  • For reactions involving reactants and products that are both in the gas phase, the entropy generally increases when the total number of moles of gas-phase products is greater than the number of  moles of gas-phase reactants 

Worked Example

In which reaction would you expect the largest decrease in entropy?

  1. CH4 (l) + 2O2 (g) → CO2 (g) + 2H2O (g)

  2. CH4 (g) + 2O2 (g) → CO2 (s) + 2H2O (g)

  3. CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g)

  4. CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)

Answer:

  • All four reactions have the same number of molecules as reactants and products, which means that the number of molecules will not be a consideration for this question

  • Reaction 1 will show an increase in entropy as one of the reactants is a liquid but all products are gases 

    • Therefore, reaction 1 cannot be the correct answer 

  • Reaction 2 will show a decrease in entropy as the three gaseous reactants form one solid and two gaseous products  

  • Reaction 3 will show no change in entropy as all of the reactants and products are gases 

    • Therefore, reaction 3 cannot be the correct answer 

  • Reaction 4 will show a decrease in entropy as the three gaseous reactants form one gaseous and two liquid products

  • Between reactions 2 and 4:

    • Reaction 4 will have the biggest decrease in entropy as there is a bigger change in the disorder of the particles for this reaction

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Alexandra Brennan

Author: Alexandra Brennan

Expertise: Chemistry

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.