pH & pOH of Strong Acids & Bases (College Board AP® Chemistry)
Study Guide
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
pH & pOH of Strong Acids & Bases
Strong Acids
Most strong acids are monoprotic and fully ionize in aqueous solutions
Examples include HCl (hydrochloric acid) and HNO3 (nitric acid)
Due to the acid fully ionizing, there is a high concentration of H+/H3O+ ions resulting in the solution having a low pH
The H+/H3O+ concentration is equal to the molar concentration of the acid:
[H+ (aq)] = Mstrong acid
This can be used to calculate the pH using:
pH = -log10[H+ (aq)]
The position of the equilibrium is so far over to the right that you can represent the reaction as an irreversible reaction
Diagram to show the ionization of a strong acid
The diagram shows the complete dissociation of a strong acid in aqueous solution
Strong Bases
Strong bases, such as Group 1 metal hydroxides, completely dissociate in aqueous solutions
A large concentration of OH– ions are present in the solution causing it to have a high pH
Group 1 hydroxides produce one hydroxide ion per formula unit but others, such as Ca(OH)2 will produce more than one
Therefore the concentration of hydroxide ions can be calculated using:
[OH-] = Mstrong base x number of OH- ions per mole
This can then be used to calculate pOH:
pOH = -log [OH–]
pOH can then be used to calculate pH:
pH = 14 - pOH
The dissociation of a strong base can be represented using the diagram below
The position of the equilibrium is on the right and so the reaction is irreversible
Diagram to show the dissociation of a strong base
The diagram shows the complete dissociation of a strong base in aqueous solution
Worked Example
1. Calculate the pH for a solution with a hydrogen ion concentration of 1.6 x 10-4 M.
2. Calculate the pH of a solution containing 0.00052 M Ba(OH)2.
Answers:
Answer 1:
The pH of the solution is:
pH = -log [H+]
pH = -log 1.6 x 10-4
pH = 3.80
Answer 2:
The pH of the solution is:
[OH-] = 0.00052 x 2 = 0.00104
pOH = -log 0.00104 = 2.98
pH = 14 - 2.98 = 11.02
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