Titration Curves of Polyprotic Acids (College Board AP® Chemistry)
Study Guide
Written by: Philippa Platt
Reviewed by: Stewart Hird
Titration Curves of Polyprotic Acids
Polyprotic Acids
Polyprotic acids contain more than one ionising hydrogen atoms
E.g. H2SO4, H3PO4
These acids ionize and stepwise
Ionization steps for phosphoric acid, H3PO4
Step | Equation |
---|---|
Step 1 | H3PO4 H2PO4– + H+ |
Step 2 | H2PO4– HPO42– + H+ |
Step 3 | HPO4– PO43– + H+ |
Titrations of polyprotic acids have more than one equivalence point due to the series of ionization steps
If H3PO4 is titrated against a strong base such as NaOH
At each equivalence point, the acid is neutralised to H2PO4, HPO42– and PO43– respectively
The pH at these points can be determined by using
Ka =
Between the equivalence points, there are mixtures of a conjugate acid and its conjugate base and are known as buffer regions
At the midpoint of these regions, the pH = pKa of the acid and the concentration of the conjugate acid and base are equal
E.g. [H2PO4] = [HPO42–]
This is the half-equivalence point
pH curve for addition of NaOH to H3PO4
At the midpoints of each ionization step, the pH of the acid is equal to the pKa
Last updated:
You've read 0 of your 10 free study guides
Unlock more, it's free!
Did this page help you?