Magnitude of the Equilibrium Constant (College Board AP® Chemistry)

Study Guide

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Fallon

Written by: Fallon

Reviewed by: Stewart Hird

Magnitude of the Equilibrium Constant

  • The equilibrium constant (K) is the ratio of products and reactants in a system at equilibrium

 straight K subscript straight C equals fraction numerator open square brackets products close square brackets over denominator open square brackets reactants close square brackets end fraction            straight K subscript straight P space equals space straight P subscript products over straight P subscript reactants

  • The magnitude of the equilibrium constant indicates the extent to which the reaction proceeds

  • When K > 1, the products are favored at equilibrium

    • If K is very large, the forward reaction essentially proceeds to completion

  • When K < 1, the reactants are favored at equilibrium

    • If K is very small, the forward reaction barely proceeds. In other words, the reverse reaction essentially proceeds to completion

  • When comparing the equilibrium constants of two or more reactions at the same temperature, the reaction with the greatest value for K will have the greatest proportion of products at equilibrium

Worked Example

C2H4 (g) ⇌ C2H2 (g) + H2 (g)                KP = 1.54 x10-7

Pure C2H4 (g) is placed in a 1.0 L rigid, sealed flask at 700 K and allowed to react according to the equation shown above. Which of the following statements correctly compares the partial pressures of C2H4 (g) and H2 (g) after equilibrium is established?

  1. straight P subscript straight C subscript 2 straight H subscript 4 left parenthesis eq right parenthesis end subscript space greater than space straight P subscript straight H subscript 2 left parenthesis eq right parenthesis end subscript , because the smaller the KP value, the greater the partial pressure of the reactants at equilibrium

  2. straight P subscript straight C subscript 2 straight H subscript 4 left parenthesis eq right parenthesis end subscript space equals space straight P subscript straight H subscript 2 left parenthesis eq right parenthesis end subscript , because at equilibrium the partial pressures of the products and reactants must be constant and equal

  3. straight P subscript straight H subscript 2 left parenthesis eq right parenthesis end subscript space greater than space straight P subscript straight C subscript 2 straight H subscript 4 left parenthesis eq right parenthesis end subscript , because the initial rate of the forward reaction is greater than that of the reverse reaction leading to an increase in the partial pressure of the products at equilibrium

  4. straight P subscript straight H subscript 2 left parenthesis eq right parenthesis end subscript space greater than space straight P subscript straight C subscript 2 straight H subscript 4 left parenthesis eq right parenthesis end subscript , because the smaller the KP value, the faster the rate of reaction and the greater the partial pressure of the products at equilibrium

Answer:

  • At equilibrium, the partial pressures of the products and reactants must remain constant, but they do not necessarily have to be equal

  • A very small KP value indicates that the forward reaction barely proceeds and that the reactants are favored at equilibrium

  • So at equilibrium, the flask will container a much greater proportion of C2H4 (g) than H2 (g)

  • As the gases occupy the same volume and are held at the same temperature, the partial pressure of C2H4 (g) at equilibrium will be greater than that of H2 (g)

Worked Example

Into two separate flasks, a solution containing 1.0 M OH-(aq) is combined with a solution containing 1.0 M of the appropriate metal ion as shown in the table below. The ions react via an equilibrium reaction to form a complex ion.

Flask

Chemical Reaction

Kc at 25°C

A

Al3+ (aq) + 4OH- (aq) ⇌ Al(OH)4- (aq)      

1.1 x 1033

B

Zn2+ (aq) + 4OH-(aq) ⇌ Zn(OH)42-(aq)    

4.6 x 1017

 After reaching equilibrium at 25°C, which flask contains a higher concentration of its respective complex ion?


Answer:

  • A very large Kc value indicates that the forward reaction essentially proceeds to completion

  • The larger the Kc value, the greater the proportion of products in the equilibrium mixture

  • As both flasks initially contain equimolar amounts of the reactants and the reaction in flask A has a larger Kc value, the concentration of the complex ion in flask A at equilibrium will be greater than that of flask B

Examiner Tips and Tricks

If you forget which side of a reaction is favored based on the value of K you can perform a quick test using simple concentrations. This is summarized in the table below.

….. Are favored

Concentrations at equilibrium

Value of Kc

Result

Products

2M = [products]

1M = [reactants]

straight K subscript straight c equals 2 over 1

Kc > 1

Reactants

1M = [products]

2M = [reactants]

straight K subscript straight c equals 1 half

Kc < 1


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Fallon

Author: Fallon

Expertise: Chemistry Content Creator

Fallon obtained a double major in chemistry and secondary education, and after graduating she taught Chemistry and Organic Chemistry for 7 years. Fallon’s passion for creating engaging classroom materials led her to pursue a career in content development. For over 3 years, Fallon has created videos, review materials, and practice questions for AP Chemistry, IGCSE, and other international exam boards.

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.