Enthalpy of Reaction (College Board AP® Chemistry)

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Philippa Platt

Written by: Philippa Platt

Reviewed by: Stewart Hird

Enthalpy of Reaction

  • The standard enthalpy change for a chemical reaction, ΔH°, refers to the heat transferred at constant pressure under standard conditions and states

  • These standard conditions are:

    • A pressure of 100 kPa

    • A concentration of 1 M for all solutions

    • Each substance involved in the reaction is in its standard state (solid, gas or liquid)

  • Temperature is not part of the definition of standard state, but a temperature of 25 oC (298 K) is usually given as the specified temperature

  • To show that a reaction has been carried out under standard conditions, the symbol ° is used

  • Eg. Δ = the standard enthalpy change

Standard Enthalpies

  • There are a few Standard Enthalpy changes which are used commonly in energy calculations and they are summarised below:

Standard Enthalpy
Change of ...

Definition


Symbol

Exothermic/

Endothermic

Reaction

The enthalpy change when the reactants in the stoichiometric equation react to give the products under standard conditions

Δr

Both

Formation

The enthalpy change when one mole of a compound is formed from its elements under standard conditions

Δf

Both

Combustion

The enthalpy change when one mole of a substance is burnt in excess oxygen under standard conditions

Δc

Exothermic

Neutralisation

The enthalpy change when one mole of water is
formed by reacting an acid and alkali under standard conditions

Δneut

Exothermic

  • Practice your understanding of enthalpy changes on the following worked examples:

Worked Example

One mole of water is formed from hydrogen and oxygen releasing 286 kJ

H2 (g) + ½O2 (g)  H2O (l)             Δr= -286 kJ mol-1

Calculate ΔHr for the reaction below:

2H2 (g) + O2 (g)  2H2O (l)

Answer:

  • Since two moles of water molecules are formed in the question above, the energy released is simply:

    • ΔHr = 2 mol x (-286 kJ mol-1)

    • ΔHr = - 572 kJ

Worked Example

Calculate ΔHr for the reaction below

4Fe (s) +O2 (g)    2Fe2O3 (s)

given that Δf  [Fe2O3 (s)]  = - 824 kJ mol-1

Answer:

  • Since two moles of Fe2O3 (s) are formed the total change in enthalpy for the reaction above is:

    • ΔHf =  2 mol x ( -824 kJ mol-1)

    • ΔHf = - 1648 kJ

Worked Example

Identify each of the following as  Δr, Δf, Δc or Δneut

  1. MgCO3 (s) MgO (s) + CO2 (g)

  2. C (graphite) + O2 (g)  CO2 (g)

  3. HCl (aq) + NaOH (aq)   NaCl (aq) + H2O (l)

Answers:

  • Answer 1: Δr

  • Answer 2: Δf as one mole of CO2 is formed from its elements in standard state and Δc as one mole of carbon is burnt in oxygen

  • Answer 3: Δneut as one mole of water is formed from the reaction of an acid and alkali

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.