Enthalpy & Bond Energies (College Board AP® Chemistry)

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Philippa Platt

Written by: Philippa Platt

Reviewed by: Stewart Hird

Enthalpy & Bond Energies

  • When bonds are broken or made enthalpy changes take place

    • A chemical bond is a force of attraction between two atoms

    • Breaking the bond requires the input of energy it is therefore an endothermic process

  • The energy change required to break the bond depends on the atoms that form the bond

    • The energy required to break a particular bond is called the bond dissociation enthalpy

    • This is usually just shortened to bond enthalpy or bond energy

  • Bond formation is the opposite of bond breaking and so energy is released when bonds are formed

    • It is therefore an exothermic process

Diagram to show bond breaking and bond making

bond breaking and bond making

To break bonds energy is required from the surroundings and to make new bonds energy is released from the reaction to the surroundings

  • The amount of energy released when a particular bond is formed has the same magnitude as the energy taken in when the bond is broken but has the opposite sign

Overall enthalpy changes

  • If more energy is released when new bonds are formed than energy is required to break bonds, the reaction is exothermic

    • The products are more stable than the reactants

  • If more energy is required to break bonds than energy is released when new bonds are formed, the reaction is endothermic

    • The products are less stable than the reactants

  • The relationship between bond breaking and bond making can be shown graphically like this:

Bond enthalpy profiles

bond-enthalpy-profile

Diagram to show the energy profiles of both exothermic and endothermic reactions


Average bond energy

  • Bond energies are affected by other atoms in the molecule (the environment)

  • Therefore, an average of a number of the same type of bond but in different environments is calculated

  • This bond energy is known as the average bond energy and is defined as

    • 'The energy needed to break one mole of bonds in a gaseous molecule averaged over similar compounds

Average Bond Enthalpy of Methane

average-bond-enthalpies

The average bond enthalpy of C-H is found by taking the bond dissociation enthalpy for the whole molecule and dividing it by the number of C-H bonds

  • The first C-H bond is easier to break than the second as the remaining hydrogens are pulled more closely to the carbon

  • However, since it is impossible to measure the energy of each C-H bond an average is taken

  • This value is also compared with a range of similar compounds to obtain an accepted value for the average bond enthalpy

Enthalpy Calculations

Bond enthalpy calculations

  • Bond energies are used to find the ΔH°r of a reaction when this cannot be done experimentally

  • The process is a step-by-step summation of the bond enthalpies of all the molecules present finishing with this formula:

ΔH°r = Enthalpy change for bonds broken + Enthalpy change for bonds formed

  • These two worked examples show how to lay out your calculation

Worked Example

Calculate the enthalpy of reaction for the Haber process reaction.

The relevant bond energies are given in the table below:

Bond

Average Bond Energy (kJ mol-1)

Nidentical toN

945

Hnegative signH

436

NminusH

391

Answer:

  • Step 1: The chemical equation for the Haber process is:

    • N2 (g) + 3H2 (g) ⇌ 2NH3 (g)

    • N≡N       3 H-H         6 N-H

  • Step 2: Set out the calculation as a balance sheet as shown below:

Bonds broken  (kJ mol-1)

Bonds formed (kJ mol-1)

1 x Nidentical toN= 1 x 945 = 945

 6 N-H = 6 x 391

3 x HminusH = 3 x 436 = 1308

Total= +2253

Total = -2346

   Note! Values for bonds broken are positive (endothermic) and values for bonds formed are negative (exothermic)

  • Step 3: Calculate the standard enthalpy of reaction:

    • ΔH°r = enthalpy change for bonds broken + enthalpy change for bonds formed

    • ΔH°r = (+2253 kJ mol-1) + (-2346 kJ mol-1)

    • ΔH°r = -93 kJ mol-1

Worked Example

The complete combustion of ethyne, C2H, is shown in the equation below:

2C2H2 (g) + 5O2 (g) 2H2O (g) + 4CO2 (g)

Using the average bond enthalpies given in the table, what is the enthalpy of combustion of ethyne?

Bond

Average Bond Energy (kJ mol-1)

Cnegative signH

414

Cidentical toC

839

OequalsO

498

CequalsO

804

OminusH

463

OminusC

358

Answer:

  • Step 1: The enthalpy of combustion is the enthalpy change when one mole of a substance reacts in excess oxygen to produce water and carbon dioxide. The chemical reaction should be therefore simplified such that only one mole of ethyne reacts in excess oxygen:

      H-C≡C-H + 2 ½ O=O → H-O-H + 2O=C=O

  • Step 2: Set out the calculation as a balance sheet as shown below:

Bonds broken  (kJ mol-1)

Bonds formed  (kJ mol-1)

2 x CH = 2 x 414= 828
1 x CC= 1 x 839= 839
2½ OO = 2½  x 498 = 1245

2 x OH= 2 x 463 - 926
4 x CO =  4 x 804 = 3216

Total = +2912

Total= -4142

  • ΔH°r = enthalpy change for bonds broken + enthalpy change for bonds formed

  • ΔH°r = (+2912 kJ mol-1) + (- 4142 kJ mol-1)

  • ΔH°r = -1230 kJ mol-1

Examiner Tips and Tricks

  • The key to success in bond enthalpy calculations is to be very careful when accounting for every bond present

    • Always draw out the full displayed structures of the molecules so you don't miss any of the bonds.

  • Watch out for coefficients in the balanced equations as students often miss those, forget to multiply them by the bond enthalpies and get the answer wrong!

  • It is super important to show your steps because bond enthalpy calculations often carry 3 marks, 2 of which could be for workings if you get the final answer wrong

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.