Reaction Mechanism & Rate Law (College Board AP® Chemistry)

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Oluwapelumi Kolawole

Written by: Oluwapelumi Kolawole

Reviewed by: Stewart Hird

Reaction Mechanism & Rate Law

  • An important tool used to verify a proposed reaction mechanism is its rate law

    • A rate law is an equation that shows the relationship between the rate of a reaction and the concentration of the reactants

    • Typically, rate laws are only determined experimentally

  • However, rate laws may be predicted from the assumed elementary reaction(s) of the reaction mechanism

    • If this prediction does not agree with the experimental rate law, the assumed mechanism must be wrong

  • For example, the reaction between nitrogen dioxide and fluorine gas

    • The overall equation is:

2NO2 (g)  + F2 (g)  → 2NO2F2 (g)

  • The experimental rate law, which is a summary of the experimental data, is:

Rate = k[NO2][F2]

  • If this reaction occurred in a single step, a proposed mechanism with a single elementary reaction would be:

NO2 (g)  + NO2 (g)  + F2 (g)  → NO2F2 (g) + NO2F2 (g)

  • Rate laws for elementary reactions can obtained from the stoichiometric coefficient of the reactants in a balanced chemical equation

  • Hence, for the elementary reaction above, the rate law is given as:

Rate = k[NO2]2[F2]

  • However, this does not agree with the experimental rate law and must be discarded

  • Therefore, we can conclude that the reaction occurs in more than one step

Rate-Limiting Step

  • Many reactions are characterized by a multistep mechanism consisting of two or more elementary reactions

  • For example, the reaction above is believed to occur in two steps:

NO2 (g)  + F2 (g) →  NO2F2 (g)  + F         (step 1)

NO2 (g)  + F →  NO2F2 (g)                         (step 2)

  • Each step of the mechanism has its own rate constant, activation energy and rate law

    • The rate law for each of the steps are:

NO2 (g) + F2(g) → NO2F2 (g) + F              Rate = k1[NO2][F2]

NO2 (g) + F →  NO2F2 (g)                           Rate = k2[NO2][F]

  • Often one step, called rate-limiting step, is much slower than the others

    • It is usually the step with the highest activation energy and lowest rate constant

    • The rate-limiting step determines the overall rate of the reaction and the rate equation

  • In the reaction between nitrogen dioxide and fluorine gas, the step involving the reaction between NO2 and F2 molecules (step 1) is the slowest elementary step

    • The overall rate law for the reaction between nitrogen dioxide and fluorine gas is determined by the rate equation for the elementary reaction in step 1

    • This means that the rate law is:

Rate = k[NO2][F2]

  • This matches the molecularity of the equation for step 1, with one molecule of NO2 and one molecule of F2

  • In general, the rate law for a reaction may be determined from a balanced chemical equation describing the slowest step of the elementary reactions involved in its reaction mechanism

    • But, the determined rate law must agree with the experimental rate law in order to accept the proposed mechanism

Worked Example

The equation of the reaction between ozone and nitrogen dioxide is given as:

2NO2 (g) + O3 (g) → N2O5 (g)+ O2 (g)

A proposed reaction mechanism for the reaction involves two elementary reactions:

NO2 (g)  + O3 (g)  → NO3 (g)  + O2 (g)     (step 1)

NO3 (g)  + NO2 (g)  → N2O5 (g)                (step 2)

The experimental rate law is:

k[NO2][O3

  1. What can you say about the relative rates of the two steps of the mechanism?

  2. Identify the intermediate in the reaction mechanism

Answer:

Answer a)

  • The experimental rate law corresponds to the rate law of the first step:

    • Rate = k[NO2][O3]

  • Therefore, step 1 is the rate-limiting step with the slower reaction rate, while step 2 has a faster rate of reaction

Answer b)

  • The intermediate is NO3 because it is produced in step 1 and consumed in step 2

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Oluwapelumi Kolawole

Author: Oluwapelumi Kolawole

Expertise: Chemistry Content Creator

Oluwapelumi is a Pharmacist with over 15000+ hours of AP , IB, IGCSE, GCSE and A-Level chemistry tutoring experience. His love for chemistry education has seen him work with various Edtech platforms and schools across the world. He’s able to bring his communication skills as a healthcare professional in breaking down seemingly complex chemistry concepts into easily understood concepts for students.

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.