VSEPR Theory (College Board AP® Chemistry)
Study Guide
Written by: Martín
Reviewed by: Stewart Hird
VSEPR Theory
The valence shell electron pair repulsion (VSEPR) theory is based on the principle that electron groups such as single bonds, double bonds, triple bonds, or single electrons repel one another through Coulombic forces
The minimize this repulsion, the valence shell electrons should be placed as far apart in the space as possible
VSEPR theory consist of three rules:
Bonding pairs and lone pairs should be arranged as far apart in space as possible
Double and triple bonds are one electron group
The Coulombic repulsion forces from lone pairs are stronger than the bonding pairs
The VSEPR theory and the number of electron groups in an atoms is a useful tool that can be used to predict the structural and electron properties of the molecules
Two electron groups
If there are two electron groups around the central atom, the angle between the bond is 180° which maximize their separation
The geometry of this molecules is LINEAR
g. BeCl2, CO2, and ethyne (HC≡CH)
Examples of Linear Molecules
Beryllium chloride, carbon dioxide and ethyne all have two electron groups
Three electron groups
If there are three electron groups around the central atom, the angle between the bonds is 120° which maximize their separation
The geometry of this molecule is TRIGONAL PLANAR
E.g. BF3, CH2CH2 and CH2O
Examples of Trigonal Planar Molecules
Boron trifluoride, ethene and methanal all have three electron groups
Four electron groups
Molecules with four electron groups have three dimensional geometries
If there are four electron groups around the central atom, there are three case scenarios:
If the four electron groups are bonding groups, the angle between the bonds is 109.5° which maximize their separation
The geometry of this molecules is TETRAHEDRAL
E.g. CH4, NH4+
Examples of Tetrahedral Molecules
Methane and ammonium ions have four electron domains
If three electron groups are bonding groups and one is a lone pair, the angle is approximately 107° which is slightly less than 109.5° due to the Coulombic force of repulsion generated by the lone pair
The geometry of this molecules is TRIGONAL PYRAMIDAL
E.g. NH3
NH3 has a Trigonal Pyramidal Geometry
The molecular geometry of ammonia
If two electron groups are bonding groups and two are lone pairs, the angle is approximately 104.5° which is less than 109.5° due to the Coulombic force of repulsion generated by the two lone pairs
Bond Angles in Water
The order of electron pair repulsion is lone pairs > lone pair: bonding pair > bonding pairs
The geometry of this molecules is BENT or ANGULAR
E.g. H2O
Water Has a Bent Geometry
The molecular geometry of water
Five electron groups
Molecules with five electron groups have three dimensional geometries
If there are five electron groups around the central atom, there are four case scenarios:
If the five electron groups are bonding groups, the angle between the equatorial bonds is 120° and the angle between the axial bonds is 90° which maximize their separation
The geometry of this molecules is TRIGONAL BIPYRAMIDAL
E.g. PCl5
PCl5 Has a Trigonal Bipyramidal Geometry
The molecular geometry of phosphorus pentachloride
If four electron groups are bonding groups and one of them is a lone pair, the angle between the equatorial bonds is slightly less than 120° and the angle between the axial bonds is slightly less than 90° due to the Coulombic force of repulsion generated by the lone pair
The geometry of this molecules is SEESAW
E.g. SF4
SF4 Has a Seesaw Geometry
The molecular geometry sulfur tetrafluoride
If three electron groups are bonding groups and two of them are lone pairs, it is a flat molecule
The angle between bonds is slightly less than 90° due to the Coulombic force of repulsion generated by the lone pairs
The geometry of this molecules is T-SHAPED
E.g. ClF3
ClF3 Has a T-shaped Geometry
The molecular geometry of chlorine trifluoride
If two electron groups are bonding groups and three of them are lone pairs, it is a flat molecule
The angle between bonds is slightly 180° due to the Coulombic force of repulsion generated by the lone pairs
The geometry of this molecules is LINEAR
E.g. I3-
I3- Has a Linear Geometry
The molecular geometry of the triiodide ion
Six electron groups
Molecules with five electron groups have three dimensional geometries
If there are six electron groups around the central atom, there are three case scenarios:
If the six electron groups are bonding groups, the angle between the bonds is 90° which maximize their separation
The geometry of this molecules is OCTAHEDRAL
E.g. SF6
SF6 Has an Octahedral Geometry
The molecular geometry of sulfur hexafluoride
If five electron groups are bonding groups and one of them is a lone pair, the angle between the bonds is slightly less than 90° due to the Coulombic force of repulsion generated by the lone pair
The geometry of this molecules is SQUARE PYRAMIDAL
E.g. BrF5
BrF5 Has a Square Pyramidal Geometry
The molecular geometry of bromine pentafluoride
If four electron groups are bonding groups and two of them are lone pairs, it is a flat molecule
The angle between the bonds is 90° and the lone pairs are place at 180° minimizing the repulsion interaction between them
The geometry of this molecules is SQUARE PLANAR
E.g. XeF4
XeF4 Has a Square Planar Geometry
The molecular geometry of xenon tetrafluoride
In the table below it is a summary of the molecules that are part of the VSEPR
Summary of the VSEPR theory
Electron groups | Bonding groups | Lone Pairs | Molecular Geometry | Bond angles |
---|---|---|---|---|
2 | 2 | 0 | Linear | 180° |
3 | 3 | 0 | Trigonal planar | 120° |
3 | 2 | 1 | Bent | <120° |
4 | 4 | 0 | Tetrahedral | 109.5° |
4 | 3 | 1 | Trigonal pyramidal | 107° |
4 | 2 | 2 | Bent | 104.5° |
5 | 5 | 0 | Trigonal bipyramidal | 120° (equatorial) 90° (axial) |
5 | 4 | 1 | Seesaw | <120° (equatorial) <90° (axial) |
5 | 3 | 2 | T-shaped | <90° |
5 | 2 | 3 | Linear | 180° |
6 | 6 | 0 | Octahedral | 90° |
6 | 5 | 1 | Square pyramidal | <90° |
6 | 4 | 2 | Square planar | 90° |
Examiner Tips and Tricks
VSEPR theory is one of the most assessed topics in AP Chemistry. The molecular geometry, bond angles, bond order, relative bond energies, relative bond lengths, presence of dipole moment, and hybridization of valence orbitals can be predicted by using this model. Therefore, it is important that you understand its main principles and know how to explain them in terms of the Coulombic repulsion between the electron groups
Molecular Geometry
Predicting molecular geometry
The molecular geometry of any molecule can be determined following simple steps:
Draw an accurate Lewis structure for the molecule or ion
Count the number of electron groups
Count the number of bonding groups and the number of lone pairs
Apply the VSEPR theory to predict the molecular geometry
Worked Example
Predict the molecular geometry in the following molecules or ions:
H2S
NH2Cl
ICl4-
Answers:
Answer 1: The total number of valence electrons in H2S is = 1 + 1 + 6 = 8, so there are four pairs of electrons around S
Answer 2: The total number of valence electrons in NH2Cl is = 5 + 1 + 1 + 7 = 14
Answer 3: The total number of valence electrons in ICl4- is = 7 x 5 + 1 = 36
Bond Angles
Predicting bond angles
The bond angle of any molecule can be determined following simple steps:
Draw an accurate Lewis structure for the molecule or ion
Count the number of electron groups and place them as far as possible
Count the number of bonding groups and the number of lone pairs
Apply the VSEPR theory to predict the bond angle
Worked Example
Predict the bond angles in the following molecules or ions:
H2S
NH2Cl
ICl4-
Answers:
Answer 1: The total number of valence electrons in H2S is = 1 + 1 + 6 = 8, so there are four pairs of electrons around S
Answer 2: The total number of valence electrons in NH2Cl is = 5 + 1 + 1 + 7 = 14
Answer 3: The total number of valence electrons in ICl4- is = 7 x 5 + 1 = 36
Relative Bond Energies
Bond energy
The bond energy is the amount of energy required to break 1 mol of bonds in the gas phase
It reflects the strength of a chemical bond between two atoms. The higher the energy, the stronger the bond
It is influenced by factors such as bond type (ionic or covalent), bond length, and the presence of multiple bonds
There are some important rules to follow when predicting the relative bond energy:
Single bonds are generally weaker than double bonds, and double bonds are weaker than triple bonds. Therefore, single bonds have smaller bond energy
The presence of multiple bonds increases bond strength because there is a greater Coulombic attraction between the electrons and the nuclei of the atoms
Bond lengths
Triple bonds has the highest bond energy (in red) and therefore they are the strongest ones
Bond order is also a great chemical tool used to compare the bond energies between molecules
Bond order
The bond order is the amount of bonding pairs of electrons between atoms
Higher bond orders indicates greater stability and higher bond energy
Bond order is usually an integer
When a molecule has resonance, the bond order does not need to be an integer
The bond order can be calculated by using three simple steps
Draw an accurate Lewis structures
Count the number of bonding pairs in the molecule
Count the number of bonding groups
Divide the number of bonding pairs by the number of bonding groups
Worked Example
Predict which of the following molecules has a the highest relative bond energy
Answer:
In order to predict the molecule with the highest bond energy, the bond order of each molecule can be calculated
Ethane
Bonding pairs = 7
Bonding groups = 7
Bond order = Bonding pairs / Bonding groups
Bond order = 7 / 7 = 1
Ethene
Bonding pairs = 6
Bonding groups = 5
Bond order = Bonding pairs / Bonding groups
Bond order = 6 / 5 = 1.2
Ethyne
Bonding pairs = 5
Bonding groups = 3
Bond order = Bonding pairs / Bonding groups
Bond order = 5 / 3 = 1.7
As seen in the calculations, the molecule with the highest bond order is ethyne. Since higher bond order correlates with higher stability, the molecule that needs the biggest amount of energy to break its bonds is ethyne.
Relative Bond Lengths
Bond length
The bond energy refers to the distance between the nuclei of two atoms that are chemical bonded
It is influenced by factors such as bond type (ionic or covalent), bond length, the presence of multiple bonds, and the atomic radius of the atoms
There are some important rules to follow when predicting the relative bond lengths:
If the atomic radius of the atoms involved increases, the bond length will increase
This occurs because the valence electrons are pulled with less Coulombic force of attraction by the nuclei of the atoms
The presence of multiple bonds decreased the bond length because there is a greater Coulombic attraction between the electrons and the nuclei of the atoms
Bond Lengths
Triple bonds have the smallest bond length (in blue) because of the greater Coulombic forces of attraction
Bond order is also a great chemical tool used to compare the bond lengths between molecules
If you want to know how to calculate the bond order, check the previous section about Relative Bond Energy
Worked Example
Which of the following molecules will have the longest single covalent bond?
HCl
HF
HBr
HI
Answer:
The correct answer is D
This is because the iodine atom has the largest radius compared to Cl, F, and Br
This information can be obtained using the periodic table. Iodine is the down Group 17 under F, Cl and Br
Therefore, the coulombic attraction between the nucleus of the iodine atom and the valence electrons is the smallest, compared to the other halogens
Dipole Moments
Dipole moment measures the separation of positive and negative charge within a molecule
If a molecule exhibits dipole moments, it is said that the molecule is polar
There are two important factors to consider if a molecule is polar or not:
The presence of polar covalent bonds in the molecule
The molecular geometry
There are cases of molecules that have polar covalent bond, but their polarity its neutralized by the molecular geometry
This occurs because the atoms are arranged in a particular way, so the individual dipole moments cancel each other out
You can think of a dipole moment as a “tug of war game”. If the atoms pull the electrons with the same force in opposite directions, the net dipole moment of the molecule is zero
E.g. The molecule below CH3Cl is a polar molecule. The net dipole moment of the molecule points towards the chlorine atom which attracts the electrons with the strongest Coulombic force of attraction
The CH3Cl Molecule
There are four polar covalent bonds in CH3Cl which do not cancel each other out causing CH3Cl to be a polar molecule; the overall dipole is towards the electronegative chlorine atom
E.g. The molecule below CCl4 is a nonpolar molecule. Even if the C-Cl bonds are highly polar due to the difference in electronegativity between C and Cl, the net dipole moment cancels out because all the chlorine nuclei are pulling the electrons with the same Coulombic force of attraction
The CCl4 molecule
Though CCl4 has four polar covalent bonds, the individual dipole moments cancel each other out causing CCl4 to be a nonpolar molecule
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